Tìm x, biết:
\(a,\dfrac{3}{4}+x=-\dfrac{5}{2}\)
\(b,\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\)
\(c,\dfrac{2}{3}x-\dfrac{5}{7}=\dfrac{9}{7}\)
\(d,\left(\dfrac{1}{2}x-\dfrac{2}{3}\right):\dfrac{-3}{7}=2\dfrac{4}{5}\)
\(e,2,4x-40\%x+x=-1\dfrac{1}{5}\)
\(f,\left(2x-1\right)^3=2x-1\)