Đó là đáp án c

Nhẩm thôi

Phép tính b)95+62-60+95x5:2

B đó bạn ơi

tích cho mik đi

6: =>x=9/10+1/5=9/10+2/10=11/10

7: =>x=3/8-5/12=36/96-40/96=-1/24

8: =>x=7/6-5/4=14/12-15/12=-1/12

9: =>x=1/35+2/7=1/35+10/35=11/35

10: =>x=2/7-7/10=20/70-49/70=-29/70

1, \(x=-\dfrac{5}{3}-\dfrac{1}{2}=-\dfrac{10}{6}-\dfrac{3}{6}=-\dfrac{13}{6}\)

2, \(x=\dfrac{1}{3}-\dfrac{3}{5}=\dfrac{5-9}{15}=-\dfrac{4}{15}\)

4, \(x=-\dfrac{7}{9}+\dfrac{4}{3}=\dfrac{-7+12}{9}=\dfrac{5}{9}\)

5, \(x=\dfrac{5}{6}-\dfrac{7}{3}=\dfrac{5-14}{6}=-\dfrac{9}{6}=-\dfrac{3}{2}\)

6, \(x=\dfrac{9}{10}+\dfrac{1}{5}=\dfrac{9+2}{10}=\dfrac{11}{10}\)

7, \(x=\dfrac{3}{8}-\dfrac{5}{12}=\dfrac{9-10}{12}=-\dfrac{1}{12}\)

8, \(x=\dfrac{7}{6}-\dfrac{5}{4}=\dfrac{14-15}{12}=-\dfrac{1}{12}\)

9, \(x=\dfrac{1}{35}+\dfrac{2}{7}=\dfrac{1+10}{35}=\dfrac{11}{35}\)

10, \(x=-\dfrac{7}{10}+\dfrac{2}{7}=\dfrac{-49+20}{70}=\dfrac{-29}{70}\)

Zui lòng chia nhỏ

1: =>x=-5/3-1/2=-13/6

2: =>x=1/3-3/5=-4/15

4: =>x=-7/9+4/3=-7/9+12/9=5/9

5: =>x=5/6-7/3=5/6-14/6=-9/6=-3/2

6: =>x=9/10+1/5=11/10

7: =>x=3/8-5/12=36/96-40/96=-1/24

8: Đề sai rồi bạn

a) 100-5-5-...-5

=100-(20x5)

=100-100

=0

k cho mk là đủ

\(1,\dfrac{3x-1}{4}+\dfrac{6x-2}{8}=\dfrac{1-3x}{6}\\ \Leftrightarrow1,\dfrac{3x-1}{4}+\dfrac{3x-1}{4}=\dfrac{1-3x}{6}\\ \Leftrightarrow2.\dfrac{3x-1}{4}=\dfrac{1-3x}{6}\\ \Leftrightarrow\dfrac{3x-1}{4}=\dfrac{1-3x}{12}\\ \Leftrightarrow12\left(3x-1\right)=4\left(1-3x\right)\\ \Leftrightarrow3\left(3x-1\right)=1-3x\\ \Leftrightarrow9x-3-1+3x=0\\ \Leftrightarrow12x-4=0\\ \Leftrightarrow x=\dfrac{1}{3}\)

\(2,\left(2x-1\right)^2+\left(x-3\right)\left(2x-1\right)=0\\ \Leftrightarrow\left(2x-1\right)\left(2x-1+x-3\right)=0\\ \Leftrightarrow\left(2x-1\right)\left(3x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{4}{3}\end{matrix}\right.\)

=>2/13x-95/26x=-1/3-1/4

=>-91/26x=-7/12

=>-7/2x=-7/12

hay x=1/6

`2/13 x+1/4 = 95/26 x-1/3`

`<=>95/26x-2/13x=1/4+1/3`

`<=>91/26x=7/12`

`<=>7/2x=7/2`

`x=7/12:7/2`

`x=7/12xx2/7`

`x=1/6`

Vậy pt có nghiệm duy nhất `x=1/6.`

`2/13x+1/4=95/26x-1/3`

`<=>2/13x-95/26x=-1/3-1/4`

`<=>(2/13-95/26)x=-7/12`

`<=>-7/2x=-7/12`

`<=>x=1/6`

a) Ta có: \(\left(x-1\right)^{x+2}-\left(x-1\right)^{x+4}=0\)

\(\Leftrightarrow\left(x-1\right)^x\cdot\left(x-1\right)^2-\left(x-1\right)^x\cdot\left(x-1\right)^4=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\cdot\left[1-\left(x-1\right)^2\right]=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-1=1\\x-1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\\x=0\end{matrix}\right.\)

b) Ta có: \(\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot\dfrac{4}{10}\cdot\dfrac{5}{15}\cdot...\cdot\dfrac{30}{62}\cdot\dfrac{31}{64}=2x\)

\(\Leftrightarrow2x=\dfrac{1}{64}\)

hay \(x=\dfrac{1}{128}\)

a, (x + 9) + (x - 2) + (x + 7) + (x - 4) + (x + 5) + (x - 6) + (x + 3) + (x - 8) + (x + 1) = 95

    x + 9 + x - 2 + x + 7 + x - 4 + x + 5 + x - 6 + x + 3 + x - 8 + x + 1 = 95

    9x + 9 - 2 + 7 - 4 + 5 - 6 + 3 - 8 + 1 = 95

    9x + 5 = 95

     9x       = 95 - 5

     9x       = 90

       x       = 90 : 9

       x       = 10

Vậy x = 10

b, {[(x : 2) - 1/2 ] : 4 - 1/4 } : 5 = 5 + 1/5

    {[(x : 2) - 1/2 ] : 4 - 1/4 } : 5 = 26/5

    {[(x : 2) - 1/2 ] : 4 - 1/4 }      = 26/5 x 5

    [(x : 2) - 1/2 ] : 4 - 1/4         = 26

    [(x : 2) - 1/2 ] : 4                 = 26 + 1/4

    [(x : 2) - 1/2 ] : 4                 = 105/4

     (x : 2) - 1/2                        = 105/4 x 4

     (x : 2) - 1/2                        = 105

      x : 2                                 = 105 + 1/2

      x : 2                                 = 211/2

      x                                      = 211/2 x 2

      x                                      = 211

Vậy x = 211

a)P=9x+5=95=>9x=90=>x=90:9=10                                                                                                                                                    vay x = 10

mk chả hỉu mô tê j cả làm chi tiết đi!!

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