a: \(A=\left[111\cdot\left(38\cdot3-133\right)\right]\cdot2018\)

\(=111\cdot\left(-19\right)\cdot2018=-4255962\)

b: \(B=\left[25\left(1+3\cdot3-5\cdot2\right)\right]:20182019\)

\(=25\left(1+9-10\right):20182019=0\)

c: \(C=\dfrac{\left[244\left(395-195\right)\right]}{122\cdot200}=\dfrac{244}{122}=2\)

d: \(D=\dfrac{355\cdot45\cdot55}{11\cdot9\cdot7}=\dfrac{355\cdot5\cdot5}{7}=\dfrac{8875}{7}\)

\(\frac{244\times395-151}{244+395\times243}\)

\(=\frac{243\times395+395-151}{243\times395+244}\)

\(=\frac{243\times395+244}{243\times395+244}\)

\(=1\)

[ ( x + 54 ) - 32 ] x 2 = 244 

( x + 54 ) - 32 = 244 : 2 =122

x + 54 = 122 + 32 =154

x = 154 - 54 =100

=> (x+54)-32=244:2

=> (x+54)-32=122

=> x+54=122+32

=>x+54=154

=> x=154-54=100

t i c k cho mình nha cãm ơn

[ ( x + 54 ) - 32 ] x 2 = 244 

( x + 54 ) - 32 = 244 : 2 =122

x + 54 = 122 + 32 =154

x = 154 - 54

x =100

[(x^2+54)-32]*2=244
(x^2+54)-32=244/2
(x^2+54)-32=122
x^2+54=122+32
x^2+54=154
x^2=154-54
x^2=100
=> x=10 hoặc x=-10

[(x²+54)-32]*2=244

(x²+54)-32=244/2

(x²+54)-32=122

x²+54=122+32

x²+54=154

x²=154-54

x²=100=10²

=>x=10

`60 + 2 . ( x + 3 ) = 244`

`2 . (x + 3 ) = 244 - 60`

`2. ( x + 3 ) = 184`

`x + 3 = 184 : 2`

`x + 3 = 92`

`x = 92 - 3`

`x = 89`

\(60+2\cdot\left(x+3\right)=244\\ 2\cdot\left(x+3\right)=244-60\\ 2\cdot\left(x+3\right)=184\\ x+3=184:2\\ x+3=92\\ x=92-3\\ x=89.\)

\(60+2\cdot(x+3)=244\\\Rightarrow 2 \cdot(x+3)=244-60\\\Rightarrow 2\cdot(x+3)=184\\\Rightarrow x+3=184:2\\\Rightarrow x+3=92\\\Rightarrow x=92-3\\\Rightarrow x=89\)

Vậy \(x=89\)
#\(Toru\)

[ 2. ( 70 - x ) + 72 ]: 2 =46

2. ( 70 - x ) + 72 = 46.2

2. ( 70 - x ) + 72 = 92

2. ( 70 - x ) =92-72

2. ( 70 - x ) =20

70-x=20:2

70-x=10

x=70-10

x=60

[ ( 2.x + 54 ) - 32 ] . 2 = 244 

 ( 2.x + 54 ) - 32 = 244:2

( 2.x + 54 ) - 32 = 122

2.x + 54 = 122+32

2.x + 54 = 154

2.x =154-54

2x=100

x=100:2

x=50

\(=243^2-3^2-244^2=-496\)

224x395-151=223x395+395-151=223x395+224

nên: (244x395-151)/(224+395x243)=1

1 la dung do