1. No, I didn't lose any money last week.

2. I went to school last Tuesday.

3. Yes, I broke a glass last week.

4. Yes, I did a lot of homework last week.

5. I saw three films last month.

6. No, I didn't buy any presents last month.

7. Yes, I went on holiday last year.

8. I went to Ha Long Bay last year.

9. Yes, I made a lot of friends last year.

10. No, I didn't buy any bicycles last year.

\(10.13x=13x0\)

\(x\times3+8=20\\ x\times3=12\\ x=4\)

\(x\) \(\times\) 3 + 8 = 20

\(x\) \(\times\) 3       = 20 - 8

\(x\) \(\times\) 3      = 12

\(x\)             = 12: 3

\(x\)             = 4

x = 4

3:

ΔAHB vuông tại H có HM là đường cao

nên AM*AB=AH^2

ΔAHC vuông tại H có HN là đường cao

nên AN*AC=AH^2

=>AM*AB=AN*AC

\(3^x+4\cdot3^{x-2}=333\)

\(\Rightarrow3^{x-2+2}+4\cdot3^{x-2}=333\)

\(\Rightarrow3^{x-2}\cdot\left(3^2+4\right)=333\)

\(\Rightarrow3^{x+2}\cdot\left(9+4\right)=333\)

\(\Rightarrow3^{x+2}\cdot13=333\)

\(\Rightarrow3^{x+2}=333:13\)

\(\Rightarrow3^{x+2}=\dfrac{333}{13}\)

Không có x nào thỏa mãn

⇒ x ∈ ∅

Mk cần gấp á. Ai hỗ trợ mk với

1D

4A

\(\dfrac{1}{2}\left(x-2\right)+\dfrac{1}{3}\left(2-x\right)=x\\ \Leftrightarrow\dfrac{1}{2}\left(x-2\right)-\dfrac{1}{3}\left(x-2\right)=x\\ \Leftrightarrow\left(x-2\right).\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=x\\ \Leftrightarrow\left(x-2\right).\left(\dfrac{3-2}{6}\right)=x\\ \Leftrightarrow\left(x-2\right).\dfrac{1}{6}=x\\ \Leftrightarrow\dfrac{1}{6}x-\dfrac{1}{3}-x=0\\ \Leftrightarrow\left(\dfrac{1}{6}-1\right)x=\dfrac{1}{3}\\ \Leftrightarrow\left(\dfrac{1-6}{6}\right)x=\dfrac{1}{3}\\ \Leftrightarrow\dfrac{-5}{6}x=\dfrac{1}{3}\\ \Leftrightarrow x=\dfrac{1}{3}:\left(-\dfrac{5}{6}\right)\\ \Leftrightarrow x=-\dfrac{2}{5}\)

Vậy \(x=-\dfrac{2}{5}\)

x= \(\dfrac{7\pm\sqrt{37}}{3}\) nha

x = 2/5