\(a,=4\cdot3-\left(1+1\right):2=12-2:2=12-1=11\\ b,=\left[47-\left(736:2^4\right)\right]\cdot2013=\left(47-736:16\right)\cdot2013=\left(47-46\right)\cdot2013=2013\)

f: =-46-64-91+220

=220-110-91

=110-91=19

g: =4-2:2=3

h: ={47-736:2^4}*2013

=2013(47-184)

=-137*2013=-275781

a: \(\left[600-\left(40:2^3+3\cdot5^3\right)\right]:5\)

\(=\left[600-5-375\right]:5\)

\(=44\)

b: \(16\cdot12^2-\left(4\cdot23^2-59\cdot4\right)\)

\(=16\cdot144-4\cdot\left(23^2-59\right)\)

\(=2304-4\cdot470\)

\(=424\)

c: Ta có: \(2^{100}-\left(1+2+2^2+2^3+...+2^{99}\right)\)

\(=2^{100}-2^{100}+1\)

=1

d: Ta có: \(169\cdot2011^0-17\cdot\left(83-1702:23+1^{2012}\right)+2^7:2^4\)

\(=169-17\cdot\left(83-74+1\right)+2^3\)

\(=177-17\cdot10\)

=7

\(2011-5.5^2-\left(7^3:7+2012^0\right)\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50=1836\)

\(120:520:\left(500-5^3+35.7\right)\\ =120:520:\left(500-125+245\right)\\ =120:520:620=\dfrac{3}{8060}\)

\(2011-5\times5^2-\left[7^3:7+2012^0\right]\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50\\ =1836\\ 120:520:\left[500-5^3+35\times7\right]\\ =120:520:\left[500-125+35\times7\right]\\ =120:520:620\\ =\dfrac{3}{8060}\)

a: \(2011-5\cdot5^2-\left[7^3:7+2012^0\right]\)

\(=2011-125-\left(7^2+1\right)\)

\(=1836\)

b: \(120:520:\left[500-5^3+35\cdot7\right]\)

\(=120:520:620\)

\(=\dfrac{3}{8060}\)

13.(23+22)-3.(17+28)

=13.45-3.45

=45.(13-3)

=45.10

=450.

Lời giải:
$A=2^{50}-2^{49}-...2^2-2$

$-A=2+2^2+2^3+...+2^{49}-2^{50}$

$-2A=2^2+2^3+2^4+...+2^{50}-2^{51}$

$-A-(-2A)=(2-2^{50})-(2^{50}-2^{51})$

$A=2-2^{50}-2^{50}+2^{51}=2-2^{51}+2^{51}=2$

26{2-[5-(22-18)^2]}=26                                                              (59-5^30)-(59+3^3-5^30)=0

a) \(3.5^2+15.2^2-26\div2\)

= 3.25 + 15.4 - 13

= 75 + 60 - 13

= 135 - 13

= 122

b) \(5^3.2-100\div4+2^3.5\)

= 125.2 - 25 + 8.5

= 250 - 25 + 40

= 225 + 40

= 265

c)\(6^2\div9+50.2-3^3.33\)

= 36 : 9 + 100 - 9.33

= 4 + 100 - 297

= 104 - 297

= -193

d)\(3^2.5+2^3.10-81\div3\)

= 9.5 + 8.10 - 27

= 45 + 80 - 27

= 125 - 27

= 98

e) \(5^{13}\div5^{10}-25.2^2\)

= 5³ - 25.4

= 125 - 100

= 25

f) \(20\div2^2+5^9\div5^8\)

= 20 : 4 + 5

= 5 + 5

= 10

a: \(61\cdot45+61\cdot23-68\cdot51\)

\(=61\left(45+23\right)-68\cdot51\)

\(=68\cdot61-68\cdot51\)

\(=68\left(61-51\right)=68\cdot10=680\)

b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)

\(=75-75+4\cdot8\)

\(=4\cdot8=32\)

c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)

\(=\dfrac{36}{20-30+4^2}\)

\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)

d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)

\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)