\((-12:3)(x:x)(y:y)\)
2/ Tìm y:
y + \(\dfrac{1}{3}\) x 4 = 12 \(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)
\(y=12-\left(\dfrac{1}{3}\times4\right)=12-\dfrac{4}{3}=\dfrac{32}{3}\)
\(y=\left(\dfrac{12}{35}\times\dfrac{14}{9}\right)-\dfrac{2}{5}=\dfrac{8}{15}-\dfrac{2}{5}=\dfrac{2}{15}\)
a) \(y+\dfrac{1}{3}\times4=12\)
\(y+\dfrac{1}{3}=12:4\)
\(y+\dfrac{1}{3}=3\)
\(y=3-\dfrac{1}{3}\)
\(y=\dfrac{8}{3}\)
b) \(\dfrac{2}{5}+y=\dfrac{12}{35}\times\dfrac{14}{9}\)
\(\dfrac{2}{5}+y=\dfrac{8}{15}\)
\(y=\dfrac{8}{15}-\dfrac{2}{5}\)
\(y=\dfrac{2}{15}\)
If the average of y:y + 2 and y + 4 is 12.Then y =
tìm x:
x^2+x=12
\(x^2+x=12\)
\(\Rightarrow x^2+x-12=0\)
\(\Rightarrow x\left(x-3\right)+4\left(x-3\right)=0\Rightarrow\left(x-3\right)\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
Tìm x:
x-4/12=-5/6
\(x-\dfrac{4}{12}=-\dfrac{5}{6}\)
⇔\(x-\dfrac{1}{3}=-\dfrac{5}{6}\)
⇔\(x=-\dfrac{1}{2}\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
=>(x-4).6=12.(-5)
=>6x-24=-60
=>6x=-36
=x=-6
Tìm x:x-\(\frac{x}{3}\)=\(\frac{3}{57}\):\(\frac{12}{19}\)
\(x-\frac{x}{3}=\frac{3}{57}:\frac{12}{19}\)
\(x-\frac{x}{3}=\frac{3}{57}\times\frac{19}{12}\)
\(x-\frac{x}{3}=\frac{1}{12}\)
\(\Rightarrow12x-4x=1\)
\(\Rightarrow8x=1\)
\(\Rightarrow x=\frac{1}{8}\)
Bài 3:Tìm y:y+19₫84 36-y₫14
em viết anh ko hiểu nổi
tìm x
x:0,125+x:0,25+x:0,2=190
0,2.x:x+0,4.x=12
x-2/3.(x+9)=1
Biểu thức P = x − 1 2 − x : x − 1 x + 2 . x − 2 4 − x 2 có kết quả rút gọn là:
A. 1 2 − x
B. x + 2 x − 2
C. x + 2 2 − x
D. 1 x − 2
Biểu thức P = x − 1 2 − x : x − 1 x + 2 . x − 2 4 − x 2 có kết quả rút gọn là:
A. 1 2 − x
B. x + 2 x − 2
C. x + 2 2 − x
D. 1 x − 2
y:y= bao nhiêu
y:y=\(\frac{y}{y}=1\)
học tốt nha
bạn Ngô Phương Thảo