Question

2/ Tìm y:

y + \(\dfrac{1}{3}\) x 4 = 12                                         \(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)

Answer 1

\(y=12-\left(\dfrac{1}{3}\times4\right)=12-\dfrac{4}{3}=\dfrac{32}{3}\)

\(y=\left(\dfrac{12}{35}\times\dfrac{14}{9}\right)-\dfrac{2}{5}=\dfrac{8}{15}-\dfrac{2}{5}=\dfrac{2}{15}\)

Answer 2

a) \(y+\dfrac{1}{3}\times4=12\)

\(y+\dfrac{1}{3}=12:4\)

\(y+\dfrac{1}{3}=3\)

\(y=3-\dfrac{1}{3}\)

\(y=\dfrac{8}{3}\)

b) \(\dfrac{2}{5}+y=\dfrac{12}{35}\times\dfrac{14}{9}\)

    \(\dfrac{2}{5}+y=\dfrac{8}{15}\)

           \(y=\dfrac{8}{15}-\dfrac{2}{5}\)

          \(y=\dfrac{2}{15}\)

Answer 3

2/15

Answer 4

\(y+\dfrac{1}{3}=12:4\)

\(y+\dfrac{1}{3}=3\)

\(y=3-\dfrac{1}{3}\)

\(y=\dfrac{2}{3}\)

 

\(\dfrac{2}{5}+y=\dfrac{12}{35}\cdot\dfrac{14}{9}\)

\(\dfrac{2}{5}+y=\dfrac{8}{15}\)

\(y=\dfrac{8}{15}-\dfrac{2}{5}\)

\(y=\dfrac{8}{15}-\dfrac{6}{15}\)

\(y=\dfrac{2}{15}\)

Answer 5

Y+1/3×4=12

Y+4/3=12

Y         =12-4/3

 Y       =32/3

2/5 +y=12/35 ×14/9

2/5 +y=8/15

         Y=8/15-2/5

         Y    =2/15

 

Answer 6

y + 1/3 x 4 = 12

y               = 12 : 4 - 1/3

y                =     8/3

 

Answer 7

y + \(\dfrac{1}{3}\) x 4 = 12

y + \(\dfrac{4}{3}\) = 12

y        = 12 - \(\dfrac{4}{3}\)

y        = \(\dfrac{32}{3}\) 

__________________________

\(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)

\(\dfrac{2}{5}\) + y = \(\dfrac{168}{315}\)

       y  = \(\dfrac{168}{315}\) - \(\dfrac{2}{5}\)

       y  = \(\dfrac{210}{1575}\)