Bài làm

\(\frac{5}{9}x\frac{8}{17}+\frac{4}{9}x\frac{8}{17}\)

\(=\frac{8}{17}x\left(\frac{5}{9}+\frac{4}{9}\right)\)

\(=\frac{8}{17}x\frac{9}{9}\)

\(=\frac{8}{17}x1\)

\(=\frac{18}{7}\)

# Chúc bạn học tốt #

\(\frac{5}{9}.\frac{8}{17}+\frac{4}{9}.\frac{8}{17}\)

\(=\frac{8}{17}\left(\frac{5}{9}+\frac{4}{9}\right)\)

\(=\frac{8}{17}.1=\frac{8}{17}\)

\(\frac{5}{9}\cdot\frac{8}{17}+\frac{4}{9}\cdot\frac{8}{17}\)

\(=\frac{8}{17}\cdot\left(\frac{5}{9}+\frac{4}{9}\right)\)

\(=\frac{8}{17}\cdot1\)

\(=\frac{8}{17}\)

Câu 1

\(a,\dfrac{2}{5}\times x=4\\ x=4:\dfrac{2}{5}=10\\ b,7:x=\dfrac{4}{5}\\ x=\dfrac{4}{5}\times7=\dfrac{28}{5}\) 

Câu 2

\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\times\dfrac{8}{17}=1\times\dfrac{8}{17}=\dfrac{8}{17}\)

Câu 1: Tìm x:

a)  2/5× x = 4

x=4 : 2/5

x=10

 8/7: x =4/5 

x=8/7:4/5

x=10/7

Câu 2: Tính bằng cách thuận tiện nhất

5/9× 8/17 + 4/9 × 8/17

=(5/9+4/9)x8/17

=1x8/17=8/17

\(5/9× 8/17 + 4/9 × 8/17 =>(5/9+4/9)×8/17 =>1 ×8/17=8/17\)

Câu 2:Đáp số là 8/17 nhé

(5/9+4/9)x8/17

=>1x8/17=8/17

Câu 1: Tìm x:

a)  2/5× x =(thiếu đề)

 8/7: x =4/5 

x=8/7:4/5

x=10/7

Câu 2: Tính bằng cách thuận tiện nhất

5/9× 8/17 + 4/9 × 8/17

=(5/9+4/9)x8/17

=1x8/17=8/17

4⁹

8¹⁶

2⁴.21

bài 1

\(\frac{2}{5}+x=4\)                          ,                    \(\frac{8}{7}:x=\frac{4}{5}\)

\(\Rightarrow\)\(x=4-\frac{2}{5}\)              ,               \(\Rightarrow\)\(x=\frac{8}{7}:\frac{4}{5}\)

\(\Rightarrow\)\(x=\frac{18}{5}\)                      ,             \(\Rightarrow\) \(x=\frac{10}{7}\)

tính cách thuận  tiện là  dấu = là x vì viết nhầm

1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)

\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)

=0

2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)

\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)

\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)

3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)

\(=\dfrac{52546}{15}\)

4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)

\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)

\(=\dfrac{4}{7}\)

1) Tính biểu thức:

Bài 1: 

\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot5^n\)

\(\Leftrightarrow2^n=2\cdot5^n\)

\(\Leftrightarrow2^{n-1}=5^n\)

Bài 2: 

a: \(A=\dfrac{2^8+3^8}{2^8}=1+\dfrac{3^8}{2^8}\)

b: \(B=\left(2^{17}+17^2\right)\cdot\left(9^{15}-15^9\right)\cdot\left(16-16\right)=0\)

123 x X = 615

X          =615 : 123

X          =5

24 + 25 + 9 = 49 + 9 = 58

X=5

24+25+9=58

24+25+9=58

`a) x - 24/8 = 8`

    `x           = 8 + 24/8`

    `x           = 11`

`b) 76/18 - x × 17/3 = 4/9`

                `x × 17/3 = 76/18 - 4/9`

                `x × 17/3 = 34/9`

                `x            = 34/9 : 17/3`

                `x            = 2/3`

a, X = 8 + 24/8

X = 11

b, X x 17/3 = 76/18 - 4/9

X x 17/3 = 34/9

X = 34/9 : 17/3

X = 2/3