\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=?\)
➝ https://hoc24.vn/hoi-dap?grade=4
a)\(\dfrac{-1}{4}.13\dfrac{9}{11}-0,25.6\dfrac{2}{11}\)
b)\(\dfrac{4}{9}:\left(\dfrac{-1}{7}\right)+6\dfrac{5}{9}:\left(\dfrac{-1}{7}\right)\)
Các bạn giúp mik nha mik sẽ tick và kết bạn. Thank you
a)\(\dfrac{-1}{4}\cdot13\dfrac{9}{11}-0,25\cdot6\dfrac{2}{11}\)
\(=\dfrac{-1}{4}\cdot\dfrac{152}{11}-\dfrac{1}{4}\cdot\dfrac{68}{11}\)
=\(\dfrac{1}{4}\cdot\left(\dfrac{-152}{11}-\dfrac{68}{11}\right)\)
\(=\dfrac{1}{4}\cdot\dfrac{-220}{11}=-5\)
b)\(\dfrac{4}{9}:\left(\dfrac{-1}{7}\right)+6\dfrac{5}{9}:\left(\dfrac{-1}{7}\right)\)
\(=\dfrac{4}{9}\cdot-7+\dfrac{59}{9}\cdot-7\)
\(=-7\cdot\left(\dfrac{4}{9}+\dfrac{59}{9}\right)\)\(=-7\cdot7=-49\)
thực hiện phép tính
a,\(\dfrac{2}{3}-\dfrac{3}{5}\div\left(-1\dfrac{1}{5}\right)+\left(\dfrac{-2}{3}\right)\times\dfrac{3}{8}\)
b,\(17\dfrac{11}{9}-\left(6\dfrac{3}{13}+7\dfrac{11}{19}\right)+\left(10\dfrac{3}{13}-5\dfrac{1}{4}\right)\)
c,\(\left(\dfrac{-3}{2}\right)^2-\left[-2\dfrac{1}{3}-\left(\dfrac{3}{4}+\dfrac{1}{3}\right)\div2\dfrac{3}{5}\right]\times\left(\dfrac{-3}{4}\right)\)
d,\(\dfrac{21}{33}\div\dfrac{11}{5}-\dfrac{13}{33}\div\dfrac{11}{5}+\dfrac{25}{33}\div\dfrac{11}{5}+\dfrac{6}{11}\)
giúp mình nhé
a)\(\dfrac{2}{3}-\dfrac{3}{5}:\left(-1\dfrac{1}{5}\right)+\left(\dfrac{-2}{3}\right)\cdot\dfrac{3}{8}\)
\(=\dfrac{2}{3}-\dfrac{3}{5}\cdot\dfrac{-5}{6}+\left(\dfrac{-1}{4}\right)=\dfrac{5}{12}+\dfrac{1}{2}=\dfrac{11}{12}\)
b)\(17\dfrac{11}{9}-\left(6\dfrac{3}{13}+7\dfrac{11}{19}\right)+\left(10\dfrac{3}{13}-5\dfrac{1}{4}\right)=\dfrac{164}{9}-\left(\dfrac{81}{13}+\dfrac{144}{19}\right)+\left(\dfrac{133}{13}-\dfrac{21}{4}\right)=\dfrac{164}{9}-\dfrac{3411}{247}+\dfrac{259}{52}=\dfrac{6425}{684}\)
c)\(\left(\dfrac{-3}{2}\right)^2-\left[-2\dfrac{1}{3}-\left(\dfrac{3}{4}+\dfrac{1}{3}\right):2\dfrac{3}{5}\right]\cdot\left(\dfrac{-3}{4}\right)=\dfrac{9}{4}-\left[\dfrac{-7}{3}-\dfrac{13}{12}\cdot\dfrac{5}{13}\right]\cdot\left(\dfrac{-3}{4}\right)=\dfrac{9}{4}-\left(\dfrac{-11}{4}\right)\cdot\left(\dfrac{-3}{4}\right)=\dfrac{3}{16}\)
d)\(\dfrac{21}{33}:\dfrac{11}{5}-\dfrac{13}{33}:\dfrac{11}{5}+\dfrac{25}{33}:\dfrac{11}{5}+\dfrac{6}{11}=\dfrac{5}{11}\cdot\left(\dfrac{21}{33}-\dfrac{13}{33}+\dfrac{25}{33}\right)+\dfrac{6}{11}=\dfrac{5}{11}\cdot1+\dfrac{6}{11}=1\)
\(a)\dfrac{2}{3}-\dfrac{3}{5}:\left(-1\dfrac{1}{5}\right)+\left(\dfrac{-2}{3}\right).\dfrac{3}{8}\)
\(=\dfrac{2}{3}-\dfrac{3}{5}:\left(\dfrac{-6}{5}\right)+\left(\dfrac{-2}{3}\right).\dfrac{3}{8}\)
\(=\dfrac{2}{3}-\dfrac{-1}{2}+\left(\dfrac{-2}{3}\right).\dfrac{3}{8}\)
\(=\dfrac{2}{3}-\dfrac{-1}{2}+\dfrac{-1}{4}\)
\(=\dfrac{7}{6}+\dfrac{-1}{4}\)
\(=\dfrac{11}{12}\)
\(b)17\dfrac{11}{9}-\left(6\dfrac{3}{13}+7\dfrac{11}{19}\right)+\left(10\dfrac{3}{13}-5\dfrac{1}{4}\right)\)
\(=\dfrac{164}{9}-\left(\dfrac{81}{13}-\dfrac{144}{19}\right)+\left(\dfrac{133}{13}-\dfrac{21}{4}\right)\)
\(=\dfrac{164}{9}-\dfrac{-333}{247}+\dfrac{259}{52}\)
\(=19,57040036+\dfrac{259}{52}\)
\(=24,55116959\)
áp dụng tính chất phép tính và quy tắc phép tính và quy tắc dấu ngoặc để tính
\(A=11\dfrac{3}{13}-\left(3\dfrac{4}{7}+6\dfrac{3}{13}\right)=\)
\(B=\left(7\dfrac{4}{9}+3\dfrac{8}{13}\right)-5\dfrac{4}{9}\)=
\(C=\dfrac{-2}{7}.\dfrac{5}{11}+\dfrac{-2}{7}\dfrac{6}{11}+5\dfrac{4}{7}\)=
\(D=0,7.1\dfrac{3}{5}.30.0,375.\dfrac{4}{7}\)
GIÚP MÌNH VỜI
nhưng mà mk hông biết cánh viết hỗn số
chỉ mk cách viết rùi mk làm cho
\(A=\dfrac{10}{7}\)
\(B=\dfrac{73}{13}\)
\(D=\dfrac{1278}{175}\)
a) \(\dfrac{ 3}{ 4 }\)+\(\dfrac{ -7 }{ 5 }\)+\(\dfrac{ 1 }{ 4 }\)+\(\dfrac{ -3 }{ 5 }\) b) \(\dfrac{ 4 }{ 9 }.\dfrac{7 }{ 11 }-\dfrac{4 }{ 11 }.\dfrac{ 2 }{9 } + \dfrac{ 6 }{ 11 }.\dfrac{ 4 }{ 9 }\)
a) 3/4 + (-7/5) + 1/4 + (-3/5)
= (3/4 + 1/4) + (-7/5 - 3/5)
= 1 - 2
= -1
b) 4/9 . 7/11 - 4/11 . 2/9 + 6/11 . 4/9
= 4/9 . (7/11 - 2/11 + 6/11)
= 4/9 . 1
= 4/9
a)
\(\dfrac{3}{4}+\dfrac{-7}{5}+\dfrac{1}{4}+\dfrac{-3}{5}\)
\(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{-7}{5}-\dfrac{3}{5}\right)\)
\(=1-2\)
\(=-1\)
b)
\(\dfrac{4}{9}.\dfrac{7}{11}-\dfrac{4}{11}.\dfrac{2}{9}+\dfrac{6}{11}.\dfrac{4}{9}\)
\(=\dfrac{28}{99}-\dfrac{8}{99}+\dfrac{24}{99}\)
\(=\dfrac{28-8+24}{99}\)
\(=\dfrac{44}{99}\)
\(=\dfrac{4}{9}\)
\(\dfrac{1}{3}\)+\(\dfrac{5}{4}\) -\(\dfrac{7}{12}\) \(\dfrac{11}{14}\)x \((-\dfrac{4}{11})\)-\(\dfrac{5}{4}\):\(\dfrac{11}{4}\) 1.6x2\(\dfrac{1}{4}\) -1.6x3\(\dfrac{1}{2}\) giúp mình 3 câu này vs pls mai mình ktra rồi :<
1, \(\dfrac{-5}{7}\) . \(\dfrac{2}{11}\) + \(\dfrac{-5}{7}\) . \(\dfrac{9}{11}\) + \(1\dfrac{5}{7}\)
2,\(-3\dfrac{4}{13}\) . \(15\dfrac{3}{41}\) + \(3\dfrac{4}{13}\) . \(2\dfrac{3}{41}\)
3, \(\dfrac{4}{5}\) . \(15\dfrac{1}{4}\) - \(\dfrac{4}{5}\) . \(15\dfrac{1}{3}\) + \(\dfrac{11}{30}\)
4,\(\dfrac{4}{20}\) + \(\dfrac{16}{42}\) + \(\dfrac{6}{15}\) - \(\dfrac{3}{5}\) + \(\dfrac{2}{21}\) - \(\dfrac{10}{21}\) + \(\dfrac{3}{10}\)
Giúp mik nha. Cảm ơn
Tính nhanh:
a)A=(19\(\dfrac{5}{8}\):\(\dfrac{7}{12}\)-13\(\dfrac{1}{4}\):\(\dfrac{7}{2}\))x\(\dfrac{4}{5}\)
b)B=(9\(\dfrac{30303}{80808}\)+7\(\dfrac{303030}{808080}\))+4.03
Tìm x:
5\(\dfrac{18}{17}\): x+(-\(\dfrac{4}{17}\)) : x + \(3\dfrac{1}{7}\):\(17\dfrac{1}{3}\)=\(\dfrac{4}{11}\)
Mấy bạn ơi cố giúp mik nha ai xong đầu mik tích hộ cho
Chỉ có những ai xong đầu mới được tích thôi à
A=\(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{13}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0.9}{\dfrac{7}{91}+0.2-\dfrac{3}{10}}\)
giúp mk nha
A= \(\dfrac{5\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}{13\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}\)+ \(\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-\dfrac{9}{10}}{\dfrac{1}{13}+\dfrac{1}{5}-\dfrac{3}{10}}\)
A= \(\dfrac{5}{13}\)+ \(\dfrac{3\left(\dfrac{1}{5}+\dfrac{1}{3}-\dfrac{3}{10}\right)}{1\left(\dfrac{1}{5}+\dfrac{1}{3}-\dfrac{3}{10}\right)}\)
A= \(\dfrac{5}{13}+3\) = \(\dfrac{44}{13}\)
\((\dfrac{-1}{4}+\dfrac{7}{33}-\dfrac{5}{3})-\left(\dfrac{-15}{12}+\dfrac{6}{11}-\dfrac{48}{49}\right)\) Giúp mình nha mấy bạn . Ai đúng mình sẽ tick cho
\(=\dfrac{-1}{4}+\dfrac{7}{33}-\dfrac{5}{3}+\dfrac{5}{4}-\dfrac{6}{11}+\dfrac{48}{49}\)
\(=1+\dfrac{7}{33}-\dfrac{18}{33}-\dfrac{5}{3}+\dfrac{48}{49}\)
\(=\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{48}{49}=\dfrac{48}{49}-1=-\dfrac{1}{49}\)