\(\left\{{}\begin{matrix}x=5-y\\y\left(5-y\right)=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=1\\y=4\end{matrix}\right.\\\left\{{}\begin{matrix}x=4\\y=1\end{matrix}\right.\end{matrix}\right.\)

All the paper was blown away by the wind.

Dozens of trees were destroyed by the storm.

Nancy a pay increase was offered (by them)

a) Thay m = -2 vào (P) ta có:

\(y=\left(-2-3\right)x+\left(-2\right).\\ \Leftrightarrow y=-5x-2.\)

i) + \(y=-5x-2.\)

\(Cho\) \(x=0.\Rightarrow y=-2.\)

\(Cho\) \(y=0.\Rightarrow x=\dfrac{-2}{5}.\)

+ \(y=2x^2.\)

Bài 5: 

a: Để đây là hàm số bậc nhất thì m+5<>0

hay m<>-5

ĐKXĐ: x>=-3/2

\(2x-3\sqrt{2x+3}-7=0\)

=>\(2x+3-3\sqrt{2x+3}-10=0\)

=>\(2x+3-5\sqrt{2x+3}+2\sqrt{2x+3}-10=0\)

=>\(\sqrt{2x+3}\left(\sqrt{2x+3}-5\right)+2\left(\sqrt{2x+3}-5\right)=0\)

=>\(\left(\sqrt{2x+3}-5\right)\left(\sqrt{2x+3}+2\right)=0\)

=>\(\sqrt{2x+3}-5=0\)

=>\(\sqrt{2x+3}=5\)

=>2x+3=25

=>2x=22

=>\(x=\dfrac{22}{2}=11\)

Câu 4:

a, \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)

\(4K+O_2\underrightarrow{t^O}2K_2O\)

b, \(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)

c, \(2K+2H_2O\rightarrow2KOH+H_2\)

\(CaO+H_2O\rightarrow Ba\left(OH\right)_2\)

\(SO_3+H_2O\rightarrow H_2SO_4\)