\(x^2-2xy+x-2y=x\left(x-2y\right)+x-2y=\left(x-2y\right)\left(x+1\right)\)

\(3x^3+6x+3-3y^2=3\left[\left(x^2+2x+1\right)-y^2\right]=3\left[\left(x+1\right)^2-y^2\right]=3\left(x-y+1\right)\left(x+y+1\right)\)

a) \(7x^2+34x-5=7x\left(x+5\right)-1\left(x+5\right)\)

\(=\left(x+5\right)\left(7x-1\right)\)

b) \(12a^2-3ab+8ac-2bc=3a\left(4a-b\right)+2c\left(4a-b\right)\)

\(=\left(4a-b\right)\left(3a+2c\right)\)

\(a,=7x^2-x+35x-5=x\left(7x-1\right)+5\left(7x-1\right)=\left(x+5\right)\left(7x-1\right)\\ b,=3a\left(4a-b\right)+2c\left(4a-b\right)=\left(3a+2c\right)\left(4a-b\right)\)

Phân tích đa thức thành phân tử:

a) 

b) 

bạn bấm vào đúng 0 sẽ ra kết quả 

mình làm bài này rồi

Bạn hướng dẫn giúp yk rồi mình bấm cho

=6a⁴-12a³+19a³-38a²+a-2a-6a+12

=6a³(a-2)+19a²(a-2)+a(a-2)-6(a-2)

=(a-2)(6a³+19a²+a-6)

=(a-2)(6a³+18a²+a²+3a-2a-6)

=(a-2)(6a²(a+3)+a(a+3)-2(a+3)

=(a-2)(a+3)(6a²+a-2)

=(a-2)(a+3)(a-1/2)(a+2/3)

a) \(25a^2-b^2=\left(5a-b\right)\left(5a+b\right)\)

b) \(z^2+z-mz-m=z\left(z+1\right)-m\left(z+1\right)=\left(z+1\right)\left(z-m\right)\)

a , 25a² - b² 

^{= (5a -b ) ( 5a+ b )}

b , z²  + z - m z -m 

= z ( z + 1) - m( z + 1 )

= ( z + 1 ) ( z - m )

a. 3x - 3 + 5(x - 1)

= 3(x - 1) + 5(x - 1)

= (3 + 5)(x - 1)

= 8(x - 1)

b. x² - 25 + y² - 2xy

= (x² - 2xy + y²) - 25

= (x - y)² - 5²

= (x - y + 5)(x - y - 5)

c. x² + 2xy - 16a² + y²

= (x² + 2xy + y²) - 16a²

= (x + y)² - (4a)²

= (x + y + 4a)(x + y - 4a)

a) \(7\left(3x-2\right)+y\left(3x-2\right)=\left(3x-2\right)\left(7+y\right)\)

b) \(x\left(y-x\right)-3\left(x-y\right)=x\left(y-x\right)+3\left(y-x\right)=\left(y-x\right)\left(x+3\right)\)

c) \(x^2-6xy+9y^2=\left(x-3y\right)^2\)

a. (3x - 2)(7+y)

b. (x - y)(x - 3)

c. (x-3y)²

a. 7(3x - 2) + y(3x - 2)

= (7 + y)(3x - 2)

b. x(y - x) - 3(x - y)

= x(y - x) + 3(y - x)

= (x + 3)(y - x)

c. x² - 6xy + 9y²

= x² - 3y.x.2 + (3y)²

= (x - 3y)²

\(a,=\left(2y^2-1\right)\left(2y^2+1\right)\\ b,=\left(x+y\right)^2-9=\left(x+y+3\right)\left(x+y-3\right)\)

Lời giải:
a. $4y^4-1=(2y^2)^2-1^2=(2y^2-1)(2y^2+1)$

b. $x^2+2xy-9+y^2=(x^2+2xy+y^2)-9$

$=(x+y)^2-3^2=(x+y-3)(x+y+3)$

\(a,Sửa:x^2-xy-13x+13y=x\left(x-y\right)-13\left(x-y\right)=\left(x-13\right)\left(x-y\right)\\ b,=\left(x+y\right)^2-\left(2z\right)^2=\left(x+y-2z\right)\left(x+y+2z\right)\\ c,=\left(x^2-2x\right)-\left(3x-6\right)=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)