Question

Phân tích đa thức thành nhân tử

a, 7.(3x-2)+y(3x-2)

b,x(y-x)-3(x-y)

c, x\(^2\)-6xy+9y\(^2\)

Answer 1

a) \(7\left(3x-2\right)+y\left(3x-2\right)=\left(3x-2\right)\left(7+y\right)\)

b) \(x\left(y-x\right)-3\left(x-y\right)=x\left(y-x\right)+3\left(y-x\right)=\left(y-x\right)\left(x+3\right)\)

c) \(x^2-6xy+9y^2=\left(x-3y\right)^2\)

Answer 2

a. (3x - 2)(7+y)

b. (x - y)(x - 3)

c. (x-3y)²

Answer 3

a. 7(3x - 2) + y(3x - 2)

= (7 + y)(3x - 2)

b. x(y - x) - 3(x - y)

= x(y - x) + 3(y - x)

= (x + 3)(y - x)

c. x² - 6xy + 9y²

= x² - 3y.x.2 + (3y)²

= (x - 3y)²