Xếp các hỗn số sau theo thứ tự từ bé đến lớn:
4\(\dfrac{14}{15}\) ; 3\(\dfrac{11}{15}\); 4\(\dfrac{11}{12}\); 3\(\dfrac{13}{15}\)
\(4\dfrac{14}{15}=\dfrac{74}{15}\)
\(3\dfrac{11}{15}=\dfrac{56}{15}\)
\(4\dfrac{11}{12}=\dfrac{59}{12}\)
\(3\dfrac{13}{15}=\dfrac{58}{15}\)
Do đó: \(3\dfrac{11}{15}< 3\dfrac{13}{15}< 4\dfrac{11}{12}< 4\dfrac{14}{15}\)
Câu 1: Trong các phân số \(\dfrac{-11}{12}\) ; \(\dfrac{-20}{23}\) ; \(\dfrac{-27}{360}\); \(\dfrac{-5}{-7}\) phân số lớn nhất là:
A. \(\dfrac{-11}{12}\) ; B. \(\dfrac{-20}{23}\) ; C. \(\dfrac{-27}{360}\) ; D. \(\dfrac{-5}{-7}\)
Giúp mik với!!!!!!!!!!!!!!!
`D.(-5)/(-7)`
Do `(-5)/(-7)=5/7>0`
Mà các cái còn lại <0
\(\dfrac{-5}{-7}=\dfrac{5}{7}>1\\ \dfrac{-11}{12}< 0\\ \dfrac{-20}{23}< 0\\ \dfrac{-27}{360}< 0\)
Phân số lớn nhất là \(\dfrac{-5}{-7}\). Chọn D
Phân số lớn nhất trong các phân số \(\dfrac{12}{15};\dfrac{0}{-6};\dfrac{11}{5};\dfrac{-4}{-5};\dfrac{0}{9}\)
a. \(\dfrac{11}{5}\)
b.\(\dfrac{0}{9}\)
c.\(\dfrac{12}{15}\)
d.\(\dfrac{-4}{-5}\)
Giá trị của tích \(\dfrac{1}{11}\) . \(\dfrac{1}{12}\)bằng giá trị của biểu thức nào sau đây?
A.\(\dfrac{1}{12}\)-\(\dfrac{1}{11}\) B.\(\dfrac{1}{23}\) C.\(\dfrac{1}{11}\)+\(\dfrac{1}{12}\) D.\(\dfrac{1}{11}\)-\(\dfrac{1}{12}\)
Phân số nào bé hơn 1
A.\(\dfrac{2}{11}\)
B.\(\dfrac{11}{11}\)
C.\(\dfrac{12}{11}\)
D.\(\dfrac{11}{2}\)
Quy đồng mẫu các phân số sau
\(a,\dfrac{5}{7}và\dfrac{9}{11}\) \(b,\dfrac{36}{42}và\dfrac{-12}{54}\)
\(c,\dfrac{-11}{30}và\dfrac{-17}{-40}\) \(d,\dfrac{36}{42}và\dfrac{-12}{36}\)
a: \(\dfrac{5}{7}=\dfrac{5\cdot11}{7\cdot11}=\dfrac{55}{77}\)
\(\dfrac{9}{11}=\dfrac{9\cdot7}{11\cdot7}=\dfrac{63}{77}\)
b: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot9}{7\cdot9}=\dfrac{54}{63}\)
\(-\dfrac{12}{54}=\dfrac{-2}{9}=\dfrac{-2\cdot7}{9\cdot7}=-\dfrac{14}{63}\)
c: \(\dfrac{-11}{30}=\dfrac{-11\cdot4}{30\cdot4}=\dfrac{-44}{120}\)
\(\dfrac{-17}{-40}=\dfrac{17}{40}=\dfrac{17\cdot3}{40\cdot3}=\dfrac{51}{120}\)
d: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot3}{7\cdot3}=\dfrac{18}{21}\)
\(\dfrac{-12}{36}=\dfrac{-1}{3}=\dfrac{-1\cdot7}{3\cdot7}=\dfrac{-7}{21}\)
Tính:
\(\dfrac{5}{12}.\dfrac{4}{11}-\dfrac{4}{11}+\dfrac{7}{12}.\dfrac{4}{11}\)
\(=\dfrac{4}{11}\left(\dfrac{5}{12}-1+\dfrac{7}{12}\right)=\dfrac{4}{11}\cdot0=0\)
\(\dfrac{5}{12}.\dfrac{4}{11}-\dfrac{4}{11}+\dfrac{7}{12}.\dfrac{4}{11}\)
\(=\dfrac{4}{11}.\left(\dfrac{5}{12}-1+\dfrac{7}{12}\right)\)
\(=\dfrac{4}{11}.\left(\dfrac{5}{12}-\dfrac{12}{12}+\dfrac{7}{12}\right)\)
\(=\dfrac{4}{11}.\left(\dfrac{-7}{12}+\dfrac{7}{12}\right)\)
\(=\dfrac{4}{11}.\dfrac{0}{12}\)
\(=\dfrac{4}{11}.0\)
\(=0\)
\(a,\dfrac{-6}{11}:\left(\dfrac{3}{5}:\dfrac{4}{11}\right)\) b,\(\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{11}{36}\)
\(c,\left(\dfrac{4}{5}+\dfrac{1}{2}\right):\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\) \(d,\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}-1-\dfrac{7}{11}\right)\)
Giúp mik nha:>>
a: \(=\dfrac{-6}{11}:\dfrac{3\cdot11}{4\cdot5}=\dfrac{-6}{11}\cdot\dfrac{20}{33}=\dfrac{-2}{11}\cdot\dfrac{20}{11}=\dfrac{-40}{121}\)
b: \(=\dfrac{7}{12}+\dfrac{5}{72}-\dfrac{11}{36}=\dfrac{42}{72}+\dfrac{5}{72}-\dfrac{22}{72}=\dfrac{25}{72}\)
c: \(=\dfrac{13}{10}:\dfrac{-5}{13}=\dfrac{-169}{50}\)
Không quy đồng ,hãy so sánh hai phân số
a \(\dfrac{19}{10}và\dfrac{10}{11}\)
b \(\dfrac{11}{10}và\dfrac{12}{11}\)
c \(\dfrac{9}{10}và\dfrac{10}{11}\)
a. 19/10 > 10/11
b. 11/10 = 12/11
c. 9/10 = 10/11
a)\(\dfrac{19}{10}>\dfrac{10}{11}\)
b)\(\dfrac{11}{10}=\dfrac{12}{11}\)
c)\(\dfrac{9}{10}< \dfrac{10}{11}\)
