( 2600 + 6400 ) – 3 × x = 1200
( 2600 + 6400 ) - 3 . x = 1200
( 2600 + 6400 ) - 3 . x = 1200
9000 -3x =1200
3x = 9000-1200= 7800
x = 7800 : 3
x =2600
( 2600 + 6400 ) - 3 . x = 1200
=> 9000 -3x =1200
=> 3x = 9000-1200= 7800
=> x = 7800 : 3
=> x = 2600
9000-3.x=1200
=> 3x= 9000-1200
=>3x=7800
=>x=7800:3=2600
t i c k cho mình nha
(2600+6400)-3.x=1200
(2600 + 6400) - 3.x = 1200
9000 - 3.x = 1200
3.x = 9000 - 1200
3.x = 7800
x = 7800 : 3
x = 2600
<=>9000-3x=1200
<=> 9000-1200=3x
<=>7800=3x
<=>x=260
(2600+6400)-3.x=1200
9000-3.x =1200
3.x =9000 -1200
3.x =7800
x = 7800 :3
x = 2600
Tìm x biết (2600+6400)-3.x=1200
(2600+6400)-3x=1200
10 000-3x=1200
3x=9000-1200
3x=7 800
x=7800/3
x=2600
(2600+6400)-3x=1200
<=>9000-3x=1200
<=>3x=9000-1200
<=>3x=7800
<=>x=2600
[(6.x-72):2-84].28=5628
( 2600+ 6400 ) - 3 . x = 1200
=>9000-3x=1200
=>3x=9000-1200
=>3x=7800
=>x=7800:3
=>x=2600
(2600+6400)-3.x=1200
=>9000-3.x=1200
=>3.x=9000-1200
=>3.x=7800
=>x=7800:3
=>x=2600
Nhanh k hết suất tick nè
(2600 + 6400) - 3 x X = 1200
2p
\(\left(2600+6400\right)-3.X=1200\)
\(9000-3.X=1200\)
\(3.X=9000-1200\)
\(3.X=7800\)
\(X=7800:3\)
\(X=2600\)
(2600+6400)-3xX=1200
⇒ 9000-3xX=1200
⇒ 3xX=9000-1200=7800
⇒ X=7800:3=2600
⇒ X=2600
\(\left(2600+6400\right)-3\times x=1200\)
\(9000-3.x=1200\)
\(3.x=9000-1200\)
\(3.x=7800\)
\(x=7800:3\)
\(x=2600\)
giúp mình với
tìm x biết
(2600-6400)-3x=1200
(3x-1)3=125
\(\left(2600-6400\right)-3x=1200\\ -3800-3x=1200\\ 3x=-3800-1200\\ 3x=-5000\\ x=-5000:3\\ x=\dfrac{-5000}{3}\)
\(\left(3x-1\right)^3=125\\ \left(3x-1\right)^3=5^3\\ 3x-1=5\\ 3x=6\\ x=6:3\\ x=2\)
Tìm số tự nhiên x, biết: (2600 + 6400) – 3x = 1200
(2600 + 6400) – 3x = 1200
9000 – 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 7800 : 3
x = 2600
Vậy x = 2600
tìm số tự nhiên x
a, (2600+6400) - 3 . x = 1200
b,[ (6.x -72 ) : 2 - 84 ] . 28 = 5628
a,(2600+6400)-3 .x = 1200
=> 9000-3 .x= 1200
=> 3.x= 7800
=. x=2600
b, (6.x-72):2-84= 201
(6x-72):2=285
6x-72=570
6x=642
x=107
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
tìm số tư nhiên x
a,(2600+6400)-3-x=1200
b,[(6.x-72):2-84].28=5628
a) \(\left(2600+6400\right)-3-x=1200\)
\(\Rightarrow9000-3-x=1200\)
\(\Rightarrow3-x=9000-1200\)
\(\Rightarrow3-x=7800\)
\(\Rightarrow x=7797\)
b) \(\left[\left(6\cdot x-72\right):2-84\right]\cdot28=5628\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=5628:28\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=201\)
\(\Rightarrow\left(6\cdot x-72\right):2=201+84\)
\(\Rightarrow\left(6\cdot x-72\right):2=285\)
Đến dei bạn tự làm, ý b mình không chắc chắn lắm