lười làm quá, bạn làm hết cũng siêng ấy

2^2x+1+4^x+3=264

2^2x+1+2^2x+1*32=264

2^2x+1(1+32)=264

2^2x+1*33=264

2^2x+1=264/33=8=2³

=>2x+1=3

2x=3-1

2x=2

x=2/2

x=1

\(x\div6\times7,2+1,3\times x+x\div2+15=19,95\)

\(\Leftrightarrow x\times\frac{1}{6}\times7,2+1,3\times x+x\times\frac{1}{2}=19,95-15\)

\(\Leftrightarrow x\times1,2+x\times1,3+x\times\frac{1}{2}=4,95\)

\(\Leftrightarrow x\times\left(1,2+1,3+\frac{1}{2}\right)=4,95\)

\(\Leftrightarrow x\times3=4,95\)

\(\Leftrightarrow x=4,95\div3\)

\(\Leftrightarrow x=1,65\)

Vậy x = 1,65

\(2^{x+1}.3^x-6^x=216\)

\(\Leftrightarrow2^x2.3^x-2^x.3^x=216\)

\(\Leftrightarrow\left(2.3\right)^x\left(2-1\right)=216\)

\(\Leftrightarrow6^x=216\)

\(\Leftrightarrow6^x=6^3\)

\(\Leftrightarrow x=3\)

\(2^{x+1}.3^x-6^x=216\)

\(=>2^x.2.3^x-6^x=216\)

\(=>\left(2.3\right)^x.2-6^x=216\)

\(=>6^x.2-6^x=216\)

\(=>6^x.\left(2-1\right)=216\)

\(=>6^x.1=216\)

\(=>6^x=216:1=216\)

\(=>6^x=6^3\)

\(=>x=3\)

Vậy...

\(#NqHahh\)

\(2^{x+1}\cdot3^x-6^x=216\\\Rightarrow2^x\cdot2^1\cdot3^x-6^x=216\\\Rightarrow6^x\cdot2-6^x=216\\\Rightarrow6^x\cdot(2-1)=216\\\Rightarrow6^x=216\\\Rightarrow6^x=6^3\\\Rightarrow x=3\)

thôi,ai giải đc thì giải,hết mẹ hạn r

\(\dfrac{5}{8}x-\dfrac{1}{3}x-\dfrac{1}{6}x=15\)

\(\Rightarrow x\left(\dfrac{5}{8}-\dfrac{1}{3}-\dfrac{1}{6}\right)=15\)

\(\Rightarrow x\left(\dfrac{15}{24}-\dfrac{8}{24}-\dfrac{4}{24}\right)=15\)

\(\Rightarrow x.\dfrac{3}{24}=15\)

\(\Rightarrow x.\dfrac{1}{8}=15\Rightarrow x=15:\dfrac{1}{8}=15.\dfrac{8}{1}=120\)