\(\left|2x+1\right|-x=5\)

\(\Rightarrow2x+1-x=5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=5-1\)

\(\Rightarrow x=4\)

chịu k mk đi mk kban

\(2VT=2^{x+1}+2^{x+2}+2^{x+3}+...+...+2^{x+2016}\)

\(VT=2VT-VT=2^{x+2016}-2^x=2^{2016}.2^x+2^x=2^x\left(2^{2016}+1\right)\)

\(VP=2^{2019}-2^3=2^3\left(2^{2016}-1\right)\)

\(\Rightarrow2^2\left(2^{2016}-1\right)=2^3\left(2^{2016}-1\right)\)

\(\Rightarrow2^x=2^3\Rightarrow x=3\)

\(2^x+2^{x+1}+2^{x+2}+2^{x+2015}=2^{2019}-8\left(1\right)\)

Đặt \(S=2^x+2^{x+1}+2^{x+2}+2^{x+2015}\)

\(\Rightarrow S+\left(1+2^2+...2^{x-1}\right)=\left(1+2^2+...2^{x-1}\right)+2^x+2^{x+1}+2^{x+2}+2^{x+2015}\)

\(\Rightarrow S+\dfrac{2^{x-1+1}-1}{2-1}=1+2^2+...2^{x-1}+2^x+2^{x+1}+2^{x+2}+2^{x+2015}\)

\(\Rightarrow S+2^x-1=\dfrac{2^{x+2015+1}-1}{2-1}\)

\(\Rightarrow S+2^x-1=2^{x+2016}-1\)

\(\Rightarrow S=2^{x+2016}-2^x\)

\(\left(1\right)\Rightarrow2^{x+2016}-2^x=2^{2019}-8=2^{2019}-2^3\)

\(\Rightarrow2^x\left(2^{2016}-1\right)=2^3\left(2^{2016}-1\right)\)

\(\Rightarrow2^x=2^3\Rightarrow x=3\)

(2x-1)⁵=(2x-1)⁷

=>x=0;1;\(\frac{1}{2}\)

(x-2)².(y-3)²=4

phân tích rồi kẻ bảng ra

(1-x)(x^2+1)=0 chắc chắn sẽ không nhận x=-1 hoặc x=5 làm nghiệm rồi

(2x^2+7)(8-mx)=0

=>8-mx=0

Nếu 8-mx=0 nhận x=-1 làm nghiệm thì m+8=0

=>m=-8

Nếu 8-mx=0 nhận x=5 làm nghiệm thì 8-5m=0

=>m=8/5