\(2\dfrac{1}{6}+\dfrac{5}{6}\div3-0,125\times\left(-2\right)^2\)
2\(\dfrac{1}{6}\)\(+\dfrac{5}{6}:3-0,125\times\left(-2\right)^2\)
\(2\dfrac{1}{6}+\dfrac{5}{6}:3-0,125\times\left(-2\right)^2\)
\(=\dfrac{13}{6}+\dfrac{5}{18}-0,125\times4\)
\(=\dfrac{22}{9}-0,5\)
\(=\dfrac{35}{18}\)
\(\left(\dfrac{-5}{8}\right)-x\div3\dfrac{5}{6}+7\dfrac{3}{4}=-2\)
Ta có: \(\left(-\dfrac{5}{8}\right)-x:3\dfrac{5}{6}+7\dfrac{3}{4}=-2\)
\(\Leftrightarrow\dfrac{-5}{8}-x:\dfrac{23}{6}+\dfrac{31}{4}+2=0\)
\(\Leftrightarrow x:\dfrac{-23}{6}+\dfrac{73}{8}=0\)
\(\Leftrightarrow x\cdot\dfrac{-6}{23}=-\dfrac{73}{8}\)
\(\Leftrightarrow x=-\dfrac{73}{8}:\dfrac{-6}{23}=\dfrac{-73}{8}\cdot\dfrac{23}{-6}\)
hay \(x=\dfrac{1679}{48}\)
Vậy: \(x=\dfrac{1679}{48}\)
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)
\(A=\dfrac{1}{2}-\dfrac{1}{4}\)
\(A=\dfrac{2}{4}-\dfrac{1}{4}\)
\(A=\dfrac{1}{4}\)
\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)
\(D=\dfrac{77}{39}+\dfrac{3}{2}\)
\(D=\dfrac{271}{78}\)
\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)
\(C=\dfrac{5}{2}-\dfrac{3}{2}\)
\(C=1\)
Giúp mình với
1. Thực hiện phép tính (Tính nhanh nếu có thể):
a) \(\left(\dfrac{3}{8}+\dfrac{-4}{3}+\dfrac{7}{12}\right)\div\dfrac{5}{6}+\dfrac{1}{2}\)
b) \(0,5\times11\dfrac{1}{3}\times75\%\div\dfrac{2}{5}+\dfrac{3}{5}\)
c) \(-5^2-4\dfrac{1}{2}\left(10,6-1\dfrac{3}{5}\right)+75\%\)
d) \(\left(-3,2\right)\times\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{15}\right)\div3\dfrac{2}{3}\)
e) \(\dfrac{-3}{5}\times\dfrac{2}{7}+\dfrac{-3}{5}\times\dfrac{5}{7}+2\dfrac{3}{5}\)
e) \(\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}.\dfrac{5}{7}+2\dfrac{3}{5}\)
= \(\dfrac{-3}{5}.\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{13}{5}\)
= \(\dfrac{-3}{5}.1+\dfrac{13}{5}\)
= \(\dfrac{-3}{5}+\dfrac{13}{5}\)
= 2
\(\dfrac{4^{10}\times9^6+3^{12}\times8^5}{6^{13}\times4-2^{16}\times3^{12}}\)
\(\dfrac{2^4\times2^6}{\left(2^5\right)^2}-\dfrac{2^5\times15^3}{6^3\times10^2}\)
\(\dfrac{\left(-2\right)^{10}\times3^{31}+2^{40}\times\left(-3\right)^6}{\left(-2\right)^{11}\times\left(-3\right)^{31}+2^{41}\times3^6}\)
giải chi tiết giúp mình nhé
A = \(\dfrac{-19}{9}\times\dfrac{1}{2}-\dfrac{4}{11}\times\dfrac{-11}{9}+\left(-\dfrac{2}{3}\right)\)
B = \(\left(-\dfrac{15}{6}\right)\div\dfrac{-1}{2}+\dfrac{7}{-12}-\dfrac{1}{3}\times\dfrac{-11}{2}\)
C = \(\dfrac{3}{4}\times\left(-8\right)-\dfrac{1}{3}\times\dfrac{-7}{2}-\dfrac{5}{18}\)
\(A=\dfrac{-19}{9}.\dfrac{1}{2}-\dfrac{4}{11}.\dfrac{-11}{9}+\left(-\dfrac{2}{3}\right)=-\dfrac{23}{18}\)
\(B=\left(-\dfrac{15}{6}\right):\dfrac{-1}{2}+\dfrac{7}{-12}-\dfrac{1}{3}.\dfrac{-11}{2}=\dfrac{25}{4}\)
\(C=\dfrac{3}{4}.\left(-8\right)-\dfrac{1}{3}.\dfrac{-7}{2}-\dfrac{5}{18}=-\dfrac{46}{9}\)
\(A=\dfrac{-19}{18}+\dfrac{4}{9}-\dfrac{2}{3}=\dfrac{-19}{18}+\dfrac{8}{18}-\dfrac{12}{18}=\dfrac{-23}{18}\)
\(B=\dfrac{-5}{2}\cdot\dfrac{-2}{1}-\dfrac{7}{12}+\dfrac{11}{6}=\dfrac{5\cdot12-7+22}{12}=\dfrac{75}{12}=\dfrac{25}{4}\)
Tính.
a) \(\dfrac{3}{22}\times\dfrac{3}{11}\times22\) b) \(\left(\dfrac{1}{3}+\dfrac{1}{6}\right)\times\dfrac{2}{5}\)
a) \(\dfrac{3}{22}\times\dfrac{3}{11}\times22\)
\(=\dfrac{3}{22}\times\dfrac{3}{11}\times\dfrac{22}{1}\)
\(=\dfrac{3\times3\times22}{22\times11\times1}\)
\(=\dfrac{9}{11}\)
b) \(\left(\dfrac{1}{3}+\dfrac{1}{6}\right)\times\dfrac{2}{5}\)
\(=\left(\dfrac{2}{6}+\dfrac{1}{6}\right)\times\dfrac{2}{5}\)
\(=\dfrac{3}{6}\times\dfrac{2}{5}\)
\(=\dfrac{1}{2}\times\dfrac{2}{5}\)
\(=\dfrac{2}{10}\)
\(=\dfrac{1}{5}\)
a: =3/22*22*3/11
=3*3/11
=9/11
b: =(2/6+1/6)*2/5
=1/2*2/5
=1/5
bài 1 tìm x
a\(\left(3x-15\right)=3^7\div3^5\)
b\(\left(4x+32\right)=43\times2^2\)
c \(6^{2x-7}=216\)
d \(5^x+5^{x+2}=650\)
e\(\left(3x-7\right)^4=81\)
bài 2 tính a ,b,c, biết
a, \(a+b=12,b+c=18,c+a=-4\)
b,\(a\times b=\dfrac{5}{6},b\times c=\dfrac{6}{7},c\times a=\dfrac{5}{7}\)
c,\(2a-3b+4c=24\)và\(1a=\dfrac{3}{4}b=\dfrac{1}{3}c\)
giúp mình nhé mình đang cần gấp
Câu 1:
a: \(\left(3x-15\right)=3^7:3^5\)
=>3x-15=9
=>3x=24
hay x=8
b: \(\left(4x+32\right)=43\cdot2^2\)
=>4x+32=172
=>4x=140
hay x=35
c: \(6^{2x-7}=216\)
=>2x-7=3
=>2x=10
hay x=5
d: \(5^x+5^{x+2}=650\)
\(\Leftrightarrow5^x\cdot26=650\)
\(\Leftrightarrow5^x=25\)
hay x=2
Tính hợp lí: \(\left(\dfrac{3}{7}\right)^5\times\left(\dfrac{7}{3}\right)^{-1}\times\left(\dfrac{5}{3}\right)^6\div\left(\dfrac{343}{625}\right)^{-2}\)
\(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\left(\dfrac{5}{3}\right)^6:\left(\dfrac{625}{343}\right)^2\)
\(=\left(\dfrac{3}{7}\cdot\dfrac{5}{3}\right)^6:\left(\dfrac{625}{343}\right)^2\)
\(=\dfrac{5^6}{7^6}:\dfrac{5^8}{7^6}=\dfrac{1}{25}\)