Giúp tớ tớ cho 1 tick

g: \(x\left(x-5\right)-3\left(x-5\right)=\left(x-5\right)\left(x-3\right)\)

h: \(x\left(x-y\right)-2\left(y-x\right)=\left(x-y\right)\left(x+2\right)\)

i: \(x\left(x+3\right)+5\left(x+3\right)=\left(x+3\right)\left(x+5\right)\)

k: \(m\left(x-3\right)-n\left(x-3\right)=\left(x-3\right)\left(m-n\right)\)

l: \(5x-10=5\left(x-2\right)\)

\(a)5m-5n=5(m-n)\\b) -2x-2y=-2(x+y)\\c)-7+7y=-7(1-y)\\d)10x^3-15x^2=5x^2(2x-3)\\e) x^2-xy=x(x-y)\\f)9x^4-6x^2=3x^2(3x^2-2)\\g)x(x-5)-3(x-5)=(x-3)(x-5)\\h)x(x-y)-2(y-x)=x(x-y)+2(x-y)=(x+2)(x-y)\\i)x(x+3)+5(3+x)=(x+5)(x+3)\\k)m(x-3)+n(3-x)=m(x-3)-n(x-3)=(m-n)(x-3)\\l)5x-10=5(x-2) \)

giúp tớ với, tớ đang cần gấp lắm ạ.

à sai ả ?

Sửa lại !

0,15dam = 15dm vì 0,15dam = 1,5m = 15dm

giờ đúng rồi nhá !

HT

0,15 dam = 1500 dm

@Duy

HT

ta có: \(\sqrt{x^2+4x+2m}=2x-5 \) (x\(\ge\frac{5}{2}\))

<=>\(x^2+4x+2m=4x^2-20x+25\)

<=>\(3x^2-24x+25-2m\)

để pt có 1 nghiệm => \(\Delta'=12^2-(25-2m)3\)=0

<=>144-75+6m=0

<=>69+6m=0

<=>6m=-69

<=>m=\(\frac{-23}{2}\)

Bạn xem tại đây nha

https://hoc24.vn/ly-thuyet/da-dang-lop-thu-bo-an-sau-bo-bo-gam-nham-bo-an-thit.3819/

a) is drinking
b) went
c) sit
d) watches
e) played
f) catch
g) has
h) get - read
I) are
j) didn't listen

a.is drinking

b.went

c.sit

d.watches

e.played

f.catch

g.is having

h.get/are reading

i.are

j.didn't listen

is drinking

went

sit

watches

played

catch

is having

get - are reading

are

didn't listen

K phải là đề sai mak là bạn làm sai.

Mọi người giúp dới, lẹ đi~