2.3x + 4.52= 154
24x-3+ 74 = 106
Tìm X
2^4.x-3 + 74 = 106
Tính giá trị của biểu thức.
a) 3 054 : 6 × 74 105 × 9 : 5 b) 5 106 × (27 : 3)24 048 : (4 × 2)
a) 3 054 : 6 × 7 = 509 × 7 = 3563
|
4105 × 9 : 5 = 36945 : 5 = 7389 |
b) 5106 × (27 : 3) = 5106 × 9 = 45954 |
24 048 : (4 × 2) = 24 048 : 8 = 3006 |
Tìm x biết (x-2) (x-5) > 0
2^4x-3 +74 =106
1) x={6;7;8;...} hoặc x={0;-1;-2;...}
2) 2^4x-3+74=106
16x-3+74=106
16x=35
x=35/16
thử lại câu 1 mik ko chắc
sai thì chỉ giùm
17.64 - 4.52 -3. 12
17.64-4.52-3.12=1008-208-36=764
#Monster
2.3x+3=10.312 + 8.312
\(2.3^{x+3}=10.3^{12}+8.3^{12}\)
\(\Leftrightarrow2.3^{x+3}=18.3^{12}\)
\(\Leftrightarrow3^{x+3}=9.3^{12}\)
\(\Leftrightarrow3^{x+3}=3^{14}\)
\(\Leftrightarrow x+3=14\Leftrightarrow x=11\)
\(\Leftrightarrow2\cdot3^{x+3}=3^{12}\cdot18\\ \Leftrightarrow2\cdot3^{x+3}=3^{14}\cdot2\\ \Leftrightarrow x+3=14\Leftrightarrow x=11\)
2.3x+3=10.312+8.3122.3x+3=10.312+8.312
=2.3x+3=18.312⇔2.3x+3=18.312
=3x+3=9.312⇔3x+3=9.312
=3x+3=314⇔3x+3=314
=x+3=14⇔x=11
Tìm x thuộc N :
Câu 1 : ( x - 41 ) nhân 109 = 74 nhân 215 -74 nhân 106
Các bạn giúp mình nha .Mình cảm ơn các bạn nhiều nha .
( x - 41 ) . 109 = 74 . 215 - 74 . 106
( x - 41 ) . 109 = 74 . ( 215 - 106 )
( x - 41 ) . 109 = 74 . 109
x - 41 = 74 . 109 : 109
x - 41 = 74
x = 74 + 41
x = 115
Vậy x = 115
=))
\(\left(x-41\right)\times109=74\times215-74\times106\)
\(\left(x-41\right)\times109=74\left(215-106\right)=74.109\)
Chia cả hai vế cho 109 \(\Rightarrow x-41=74\)
\(x=74-41=34\)
(x - 41) x 109 = 74 x 215 - 74 x 106
(x - 41) x 109 = 74 x (215 - 106)
(x - 41) x 109 = 74 x 109
=> x - 41 = 74
=> x = 74 + 41
=> x = 115.
Bạn k mik nha !!!
Giải bất phương trình 9 x ≤ 2 . 3 x + 3
A. 1/3 ≤ x ≤ 1
B. 1/3 ≤ x ≤ 3
C. x ≤ 1
D. -1 ≤ x ≤3
-1/2.3x+3/4=-2,25
-1/2.3x+3/4=-2.25
-1/2.3x+3/4=9/4
-1/2.3x =9/4-3/4
-1/2.3x =3/2
3x =3/2:-1/2
3x =-3
x =-3:3
x =-1
vậy x=-1
\(-\frac{1}{2}.3x+\frac{3}{4}=-2,25\)
\(\Rightarrow\frac{1}{2}.(-3).x+\frac{1}{2}.\frac{3}{2}=\frac{9}{4}\)
\(\Rightarrow\frac{1}{2}.\left(-3x+\frac{3}{2}\right)=\frac{9}{4}\)
\(\Rightarrow-3x+\frac{3}{2}=\frac{9}{4}:\frac{1}{2}\)
\(\Rightarrow-3x+\frac{3}{2}=\frac{9}{2}\)
\(\Rightarrow-3x=3\)
\(\Rightarrow x=-1\)
(2x-5)3=152-4.52
(x-2)(15-3x)=0
(x-5)-(2x+7)= -8
a: \(\Leftrightarrow\left(2x-5\right)^3=225-4\cdot100=125\)
=>2x-5=5
=>2x=10
hay x=5
b: \(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)
hay \(x\in\left\{2;5\right\}\)
c: =>x-5-2x-7=-8
=>-x-12=-8
=>x+12=8
hay x=-4
\(\left(2x-5\right)^3=15^2-4.5^2\)
\(\Leftrightarrow\left(2x-5\right)^3=125\)
\(\Leftrightarrow2x-5=5\)
\(\Leftrightarrow x=5\)
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\(\left(x-2\right)\left(15-3x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\15-3x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
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\(\left(x-5\right)-\left(2x+7\right)=-8\)
\(\Leftrightarrow x-5-2x-7=-8\)
\(\Leftrightarrow-x=4\)
\(\Leftrightarrow x=-4\)