`@` `\text {Ans}`

`\downarrow`

`a)`

\(x \times 27 + x \times 83 = 23400\)

`x \times (27 + 83) = 23400`

`x \times 110 = 23400`

`x = 23400 \div 110`

`x = 2340/11`

Vậy, `x = 2340/11`

`b)`

`x \times 153 - x \times 53 = 7600`

`x \times (153 - 53) = 7600`

`x \times 100 = 7600`

`x = 7600 \div 100`

`x = 76`

Vậy, `x = 76.`

a: =>x*110=23400

=>x=2340/11

b: =>100x=7600

=>x=76

a) \(x\times27+x\times83=23400\)

\(x\times\left(27+83\right)=23400\)

\(x\times110=23400\)

\(x=23400:110\)

\(x=\dfrac{2340}{11}\)

b) \(x\times153-x\times53=7600\)

\(x\times\left(153-53\right)=7600\)

\(x\times100=7600\)

\(x=7600:100\)

\(x=76\)

327

= 327

= ( 153 + 47 ) + ( 64 + 36 ) + 27

= 200 + 100 + 27

= 327

a) x-73=(57-x)-467

<=>x+x=57+73-467

<=>2x=-337

<=>x=-337/2

vậy ....

b) -(x - 3 - 84) = 70 - (-27) - 115

<=> -x + 3 + 84 = 70 +27 - 115

<=>-x=-105

<=>x=105

vậy ...

c) 231 - x + 62 = 46 + (x - 21)

<=> - x = 46 + x - 21-231-62

<=>-2x=-268

<=> x=134

vậy ...

d) -18 + x = -63 - (-33)

<=>x=-63+33+18

<=>x=-12

vậy ...

e) (x - 153) - (48 - 193) = 1 - 2 - 3 - 4

<=>x - 153 - 48 +193 = 1 - 2 - 3 - 4

<=> x= 0

vậy ...

\(S=\left(15+17-19-21\right)+\left(23+25-27-29\right)+.....+\left(143+145-147-149\right)+151+153-155\\ =\left(-8\right)+\left(-8\right)+....+\left(-8\right)+149\\ =\left(-8\right).17+149=13\)

never gonna give you up

never gonna let you down

never gonna run around

desert you

never gonna make you cry

never gonna say goodbye

never gonna tell a lie 

and hurt you :)

SOS

Có sai đề ko v ạ :)?

ko sai nha

a: \(1968\cdot15+1968\cdot84+1968\)

\(=1968\left(15+84+1\right)\)

\(=1968\cdot100=196800\)

b: \(6412+5378+3582+4628\)

\(=\left(6412+4628\right)+\left(5378+3582\right)\)

\(=11040+8960=20000\)

c: \(178\cdot101-178\)

\(=178\cdot101-178\cdot1\)

\(=178\left(101-1\right)=178\cdot100=17800\)

d: \(153\cdot8+153+153\)

\(=153\left(8+1+1\right)\)

\(=153\cdot10=1530\)