\(\dfrac{2^{15}\cdot9^4}{6^6\cdot8^3}=\dfrac{2^{15}\cdot3^8}{2^6\cdot3^6\cdot2^9}=3^2=9\)

nhanh lên mình xin đấy

a) \(2900\times94+2900\times5+2900\)
\(=2900\times\left(94+5+1\right)\)
\(=2900\times100\)
\(=290000\)
b) \(34000:125:8\)
\(=34000:\left(125\times8\right)\)
\(=34000:1000\)
\(=34\)

a) 2900 x 94 + 2900 x 5 + 2900

= 2900 x ( 94 + 1 + 5 )

= 2900 x 100

290000

a) 0,8* 0,4 * 1,25 * 25 + 0,725 + 0,275

=(0,8*1,25) * (0,4*25) + 0,725 + 0,275

=10 * 10 + 0,725+ 0,275

=100+(0,725+0,275)

=100+1=101

b) 1,25*4*8*25

=(1,25*8)*(4*25)

=10*100=1000

(lưu ý, * là dấu nhân)

0,8 x 0,4 x 1,25 x 25 + 0,725 + 0,275                                          1,25 x 4 x 8 x 25 

= ( 0,8 x 1,25 ) x ( 0,4 x 25 ) + ( 0,725 + 0,275 )                           = ( 1,25 x 8 ) x ( 4 x 25 )

= 10 x 10 + 1                                                                            = 10 x 100

= 100 + 1                                                                                 = 1000

= 101

​tick mình nha Trịnh Minh Tâm

x + x : 2 + x : 4 + x : 8 = 37,725 giúp mình nhanh vs mình cần gấp

45^10*5^20/75^15

=5^10*9^10*5^20/(5^2)^15

=5^10*5^20*9^10/5^30

=9^10

(0.8)^5/(0.4)^6

=(0.4)^5*2^5/(0.4)^6

=2^5/(0.4)

=32/(0.4)

=80

2^15*9^4/6^6*8^3

=2^15*(3^2)^4/2^6*3^6*(2^3)^3

=2^15*3^8/2^6*3^6*2^9

=3^2

=9

\(\frac{45^{10}.5^{20}}{75^{15}}=\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(3.5^2\right)^{15}}=\frac{3^{20}.5^{10}.5^{20}}{3^{15}.5^{30}}=\frac{3^{20}.5^{30}}{3^{15}.5^{30}}=3^5=243\)

\(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}=\frac{\left(0,4.2\right)^5}{\left(0,4\right)^6}=\frac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}=\frac{2^5}{0,4}=\frac{32}{\frac{2}{5}}=32.\frac{5}{2}=80\)

\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)

= ( 0,8 x 1,25 ) x (0,4 x 25 ) + ( 0,725 + 0,275 )

=  01 x  10 + 1

= 10 + 1

=11

1,25 x 4 x 8 x 2

1,25 x 8 x ( 4 x 2 )

10 x 8

80

cậu giải ra nhé minh tick cho

mình đồng ý với cách làm của bạn đỗ văn nguyên

\(n_{K_2O}=\dfrac{9.4}{94}=0.1\left(mol\right)\)

\(K_2O+H_2O\rightarrow2KOH\)

\(0.1.........................0.2\)

\(C_{M_{KOH}}=\dfrac{0.2}{0.5}=0.4\left(M\right)\)

\(C\)

Ta có: \(n_{K_2O}=\dfrac{9,4}{94}=0,1\left(mol\right)\)

PTHH: K₂O + H₂O ---> 2KOH

Theo PT: \(n_{KOH}=2.n_{K_2O}=2.0,1=0,2\left(mol\right)\)

\(\Rightarrow C_{M_{KOH}}=\dfrac{0,2}{500:1000}=0,4M\)

Chọn C

C bạn trẻ

\(70-5\cdot\left(x-3\right)=45\)

\(\Rightarrow5\cdot\left(x-3\right)=70-45\)

\(\Rightarrow5\cdot\left(x-3\right)=25\)

\(\Rightarrow x-3=\dfrac{25}{5}\)

\(\Rightarrow x-3=5\)

\(\Rightarrow x=5+3=8\)

==============

\(10+2\cdot x=4^5:4^3\)

\(\Rightarrow10+2\cdot x=4^2\)

\(\Rightarrow10+2\cdot x=16\)

\(\Rightarrow2\cdot x=16-10\)

\(\Rightarrow2\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{2}=3\)

=============

\(2\cdot x-138=2^3\cdot3^2\)

\(\Rightarrow2\cdot x-138=72\)

\(\Rightarrow2\cdot x=72+138\)

\(\Rightarrow2\cdot x=210\)

\(\Rightarrow x=\dfrac{210}{2}=105\)

==============

\(231-\left(x-6\right)=1339:12\)

\(\Rightarrow231-x+6=1339:12\)

\(\Rightarrow237-x=\dfrac{1339}{12}\)

\(\Rightarrow x=237-\dfrac{1339}{12}\)

\(\Rightarrow x=\dfrac{1505}{12}\)

14x6=