bn  nhớ tick cho mình nha 

7a 

bn ko chụp câu 8

9a

10c

11b

12d

13a

1 plays

2 are reading

3 sing

4 do - do, help

5 is teaching

7 visited

8 doesn't like

9 watch

10 gets - has - brushes - goes - has

11 played - was

12 met

13 are going to have

14 did - do , planted

15 didn't come

16 paint

17 taught

18 have never been

19 takes

20 have - had 

21 received

22 is going to invite

23 is waiting

24 talked

25 is going to travel

26 went - didn't buy

27 doesn't learn - will fail

28 washes

29 will be - watches

30 will phone

2 are reading

3 sings

4 do - do - help

5 is teaching

7 visited 

8 doesn't like

9 watch

10 gets - has

6. 10 brushes - goes

6. 30 has

11 played - was

12 met

13 will have

14 did - do - planted

15 didn't come

16 paint

17 taught

1 plays

2 are reading

3 sing

4 do - do, help

5 is teaching

7 visited

8 doesn't like

9 watch

10 gets - has - brushes - goes - has

11 played - was

12 met

13 are going to have

14 did - do , planted

15 didn't come

16 paint

17 taught

18 have never been

19 takes

20 have - had 

21 received

22 is going to invite

23 is waiting

24 talked

25 is going to travel

26 went - didn't buy

27 doesn't learn - will fail

28 washes

29 will be - watches

30 will phone

a: AK<AQ
=>K nằm giữa A và Q

=>AK+KQ=AQ
=>KQ=1cm

b: AK và AC là hai tia đối nhau

=>A nằm giữa K và C

mà AK=AC

nen A là trung điểm của KC

c: BK=1,5+3=4,5cm>AQ

Cách làm ngắn gọn: \(5=\dfrac{5\left(x-1\right)}{x-1}=\dfrac{5x-5}{x-1}=\dfrac{5x+5-10}{x-1}\)

Do đó chọn \(f\left(x\right)=5x+5\) thế vào nhanh chóng tính ra kết quả giới hạn

Còn cách khác phức tạp hơn (có thể sử dụng cho tự luận):

Do \(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-10}{x-1}=5\) hữu hạn nên \(f\left(x\right)-10=0\) có nghiệm \(x=1\)

\(\Rightarrow f\left(1\right)-10=0\Rightarrow f\left(1\right)=10\)

Do đó:

\(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-10}{\left(\sqrt{x}-1\right)\left(\sqrt{4f\left(x\right)+9}+3\right)}=\lim\limits_{x\rightarrow1}\dfrac{\left[f\left(x\right)-10\right]\left(\sqrt{x}+1\right)}{\left(x-1\right)\left(\sqrt{4f\left(x\right)+9}+3\right)}\)

\(=\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-10}{x-1}.\dfrac{\sqrt{x}+1}{\sqrt{4f\left(x\right)+9}+3}=5.\dfrac{1+1}{\sqrt{4f\left(1\right)+9}+3}=5.\dfrac{2}{\sqrt{4.10+9}+3}=...\)

Em ghi lại đề đầy đủ, chính xác mới làm được!

em ghi lai r do a

1. A

2. B

3. D

4. A

5. C

1 - A

2 - B

3 - D

4 - A

5 - C

ở đây lp 9 mak cn xưng em =_=