a) \(Q=\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{2\sqrt{x}}{\sqrt{x}+2}+\dfrac{5\sqrt{x}+2}{4-x}\right):\dfrac{3\sqrt{x}-x}{x+4\sqrt{x}+4}\left(đk:x\ge0,x\ne4\right)\)

\(=\dfrac{\left(\sqrt{x}+1\right)\left(\sqrt{x}+2\right)-2\sqrt{x}\left(\sqrt{x}-2\right)-5\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}.\dfrac{\left(\sqrt{x}+2\right)^2}{3\sqrt{x}-x}\)

\(=\dfrac{\left(x+3\sqrt{x}+2-2x+4\sqrt{x}-5\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(3\sqrt{x}-x\right)}\)

\(=\dfrac{\left(-x+2\sqrt{x}\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(3\sqrt{x}-x\right)}=\dfrac{-\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{-\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}=\dfrac{\sqrt{x}+2}{\sqrt{x}-3}\)

b) \(Q=2\Leftrightarrow\dfrac{\sqrt{x}+2}{\sqrt{x}-3}=2\Leftrightarrow2\sqrt{x}-6=\sqrt{x}+2\)

\(\Leftrightarrow\sqrt{x}=8\Leftrightarrow x=64\)

c) \(Q=\dfrac{\sqrt{x}+2}{\sqrt{x}-3}< 0\)

\(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{x}+2>0\\\sqrt{x}-3< 0\end{matrix}\right.\)(do \(\sqrt{x}+2>\sqrt{x}-3\))

\(\Leftrightarrow-2< \sqrt{x}< 3\)

\(\Leftrightarrow0\le x< 9\) và \(x\ne4\)

a: Ta có: \(Q=\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{2\sqrt{x}}{\sqrt{x}+2}+\dfrac{5\sqrt{x}+2}{4-x}\right):\dfrac{3\sqrt{x}-x}{x+4\sqrt{x}+4}\)

\(=\dfrac{x+3\sqrt{x}+2-2x+4\sqrt{x}-5\sqrt{x}-2}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\cdot\dfrac{\left(\sqrt{x}+2\right)^2}{-\sqrt{x}\left(\sqrt{x}-3\right)}\)

\(=\dfrac{-x+2\sqrt{x}}{\sqrt{x}-2}\cdot\dfrac{\sqrt{x}+2}{-\sqrt{x}\left(\sqrt{x}-3\right)}\)

\(=\dfrac{\sqrt{x}+2}{\sqrt{x}-3}\)

b: Để Q=2 thì \(\sqrt{x}+2=2\sqrt{x}-6\)

\(\Leftrightarrow\sqrt{x}=8\)

hay x=64

1 I will be helped by Adam

2 I will be helped with money by him

3 A new phone will be bought by Jenny

4 THe toy will be broken by the baby

5 Will the food be cooked by him

6 The watch won't be stolen by him

7 Why will the bill be paid by him?

8 What will be had for breakfast by you?

9 Her cloth won't be ironed by her

10 THe letter won't be posted by Jack

11 Why will these papers be signed by her?

12 The train will be caught by us

-9/20

có bài làm ko ạ

\(\dfrac{2}{3}x+\dfrac{4}{5}=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{1}{2}-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{5}{10}-\dfrac{8}{10}\)

\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{3}{10}\)

\(\Leftrightarrow x=-\dfrac{3}{10}:\dfrac{2}{3}\)

\(\Leftrightarrow x=-\dfrac{3}{10}.\dfrac{3}{2}\)

\(\Leftrightarrow x=-\dfrac{9}{20}\)

Bài 1: 

a: Xét (O) có 

ΔACB nội tiếp đường tròn

AB là đường kính

Do đó: ΔACB vuông tại C

Xét ΔABC có 

O là trung điểm của AB

H là trung điểm của BC

Do đó: OH là đường trung bình của ΔABC

Suy ra: OH//AC 

hay OH\(\perp\)CB

Suy ra: ΔOHB vuông tại H

(1-5)

1)Light snack

2)reception

3)key

4)shopping

5)viewing

Xin lỗi vì ko làm được câu 6-10 vì bài thiếu thông tin :(

1) light snack

2) reception

3) key

4) shopping

5) viewing

Câu 6 đến 10 cô mình chưa sửa mình chịu