ai giúp mình làm bài này đc k ạ
\(\dfrac{2}{3}x+\dfrac{4}{5}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{1}{2}-\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{5}{10}-\dfrac{8}{10}\)
\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{3}{10}\)
\(\Leftrightarrow x=-\dfrac{3}{10}:\dfrac{2}{3}\)
\(\Leftrightarrow x=-\dfrac{3}{10}.\dfrac{3}{2}\)
\(\Leftrightarrow x=-\dfrac{9}{20}\)
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\(\dfrac{2}{3}x+\dfrac{4}{5}=\dfrac{1}{2}\)
\(\dfrac{2}{3}x=\dfrac{1}{2}-\dfrac{4}{5}\)
\(\dfrac{2}{3}x=-\dfrac{3}{10}\)
\(x=-\dfrac{3}{10}:\dfrac{2}{3}\)
\(x=-\dfrac{9}{20}\)
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