1/5+1/6+.........+1/17 < 2 
Ta có 1/7>1/17 ta thay từ 1/6 đến hết là 1/7 thì 1/5+1/6+.........+1/17<1/5+1/6+1/7+...+1/7
Ta có số số hạng của dãy số 5+6+...17 là (17-5):1+1=13 số 
Vậy 1/5+1/6+...+1/17<1/5+1/6+1/7+...+1/7
13 số 13 số
Ta tính 1/5+1/6+1/7+...+1/7
=(1/5+1/6)+1/7.11
=11/30+11/7=77/210+330/210=407/210 và 407/210<2
Vậy 1/5+1/6+.........+1/17 <1/5+1/6+1/7+...+1/7<2
 1/5+1/6+.........+1/17 < 2 

1 <

2 >

3 <

4 >

5 <

6 <

1)<
2)>
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4)>
5)<
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nhớ k mk nha

a, -5/7+ 1+ 30/-7< x < -1/6+ 1/3 +5/6
<=> -4< x <1
<=> x = -3; -2; -1; 0

a, \(\dfrac{-5}{7}+1+\dfrac{30}{-7}\le x\le\dfrac{-1}{6}+\dfrac{1}{3}+\dfrac{5}{6}\)
<=> -4 \(\le x\le1\)
Do x \(\in Z\Rightarrow x=-4;-3;-2;-1;0;1\)
b, \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< x< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)
<=> -\(\dfrac{1}{12}< x< \dfrac{1}{8}\)
Do x \(\in Z\Rightarrow x=0;1\)
@Mai Tran

c, Do (x - \(\dfrac{1}{2}\))(x + \(\dfrac{3}{4}\)) < 0
=> x - \(\dfrac{1}{2};x+\dfrac{3}{4}\) khác dấu
Có x - \(\dfrac{1}{2}< x+\dfrac{3}{4}\Rightarrow x-\dfrac{1}{2}< 0;x+\dfrac{3}{4}>0\)
=> \(\left[{}\begin{matrix}x-\dfrac{1}{2}< 0\\x+\dfrac{3}{4}>0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x< \dfrac{1}{2}\\x>-\dfrac{3}{4}\end{matrix}\right.\)<=> -\(\dfrac{3}{4}< x< \dfrac{1}{2}\)
Do x \(\in Z\Rightarrow x=0\)
@Mai Tran

>1/4+1/4+1/16+1/16+1/16

=2/4+3/16=11/16=66/96<80/96=5/6

vậy A<5/6

nani?

A = 1/4 +1/9 + 1/16 + 1/25 + 1/36 
   =   ( 1/4 + 1/16 ) + ( 1/9 + 1/36) + 1/25
   =         5/16         +       5/36       + 1/25
   =                       65/144              + 1/25
   = 1769/3600
=> 1769/3600 < 5/6 (hay 1769/3600 < 3000/3600 -quyđồng-)
Vậy A< 5/6
Đúng nhé, tk cho mjk với-số to thiệt nhưng đúng mà-

\(\frac{5}{6}>A\)

A= 1/2²+1/3²+1/4²+1/5²+1/6²< 1/1x2+1/2x3+1/3x4+1/4x5+1/5x6

=> A < 1-1/6=5/6