=14,4833333 phút

(43 x 60 + 27) : 3giây =869 giây=14,4833333333 phút

(43 x 60 + 27) : 3giây =869 giây=14,4833333333 phút

chữ đã đẹp còn mờ nữa :))

`@` `\text {Ans}`

`\downarrow`

`a)`

`-(-18 + 45) - (18 + 55)`

`= 18 - 45 - 18 - 55`

`= (18 - 18) - (45 + 55)`

`= -100`

`b)`

`24. (5 - 178) + 178 . (10 + 24)`

`= 24.5 - 24.178 + 178. 10 + 178. 24`

`= 24.5 + 178.(-24 + 10 + 24)`

`= 24.5 + 178.10`

`=120 + 1780`

`=``1900`

`c)`

`29.(-101)`

`= -2929`

`d)`

\((- 56 + 130) – (43 – 56) – (- 20 – 43)\)

`= -56 + 130 - 43 + 56 + 20 + 43`

`= (56 - 56) + (130 + 20) + (-43+43)`

`= 150`

43 x 95 + 5 x 43 + 43

= 43 x (95 + 5) + 43

= 43 x 100 + 43

= 4300 + 43

= 4343

=-32-9+(-23)+43

=-41+43-23

=2-23=-21

\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\)

\(\Leftrightarrow\dfrac{x+35}{65}+1+\dfrac{x+39}{61}+1=\dfrac{x+43}{57}+1+\dfrac{x+47}{53}+1\)

\(\Leftrightarrow\dfrac{x+100}{65}+\dfrac{x+100}{61}-\dfrac{x+100}{57}-\dfrac{x+100}{53}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\right)=0\Leftrightarrow x=-100\)

Ta có:

\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\\ \Rightarrow\left(\dfrac{x+35}{65}+1\right)+\left(\dfrac{x+39}{61}+1\right)=\left(\dfrac{x+43}{57}+1\right)+\left(\dfrac{x+47}{53}+1\right)\\ \Rightarrow\dfrac{x+100}{53}+\dfrac{x+100}{61}=\dfrac{x+100}{57}+\dfrac{x+100}{53}\\ \Rightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\right)=0\)

Ta thấy:

\(\dfrac{1}{65}< \dfrac{1}{57}\\ \dfrac{1}{61}< \dfrac{1}{53}\\ \Rightarrow\left(\dfrac{1}{65}+\dfrac{1}{62}\right)-\left(\dfrac{1}{57}+\dfrac{1}{53}\right)< 0\)

Hay \(\dfrac{1}{65}+\dfrac{1}{62}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\)

\(\Rightarrow x+100=0\\ \Rightarrow x=0-100\\ \Rightarrow x=-100\)

 Vậy \(x=-100\)

Ta có: \(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\)

\(\Leftrightarrow\dfrac{x+100}{65}+\dfrac{x+100}{61}-\dfrac{x+100}{57}-\dfrac{x+100}{53}=0\)

\(\Leftrightarrow x+100=0\)

hay x=-100

Bài 1:

a) $2(x-2)-3(x-2)=0$

$\Leftrightarrow -(x-2)=0$

$\Leftrightarrow x=2$

b) ĐK: $x\neq \pm 3$

$\frac{5}{x-3}+\frac{4}{x+3}=\frac{x-5}{x^2-9}$

$\Leftrightarrow \frac{5(x+3)+4(x-3)}{x^2-9}=\frac{x-5}{x^2-9}$

$\Leftrightarrow \frac{9x+3}{x^2-9}=\frac{x-5}{x^2-9}$
$\Rightarrow 9x+3=x-5$

$8x=-8$

$x=-1$ (thỏa)

c) 

$(5x+7)(10-5x)=0$

$\Leftrightarrow 5x+7=0$ hoặc $10-5x=0$

$\Leftrightarrow x=-\frac{7}{5}$ hoặc $x=2$

d)

$|2x-3|=5-x$ 

\(\Rightarrow \left\{\begin{matrix} 5-x\geq 0\\ \left[\begin{matrix} 2x-3=5-x\\ 2x-3=x-5\end{matrix}\right.\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=-2\\ x=\frac{8}{3}\end{matrix}\right.\)

Bài 2:

a)

BPT \(\Leftrightarrow \frac{5(4x-1)}{15}-\frac{2-x}{15}\leq \frac{3(10x-3)}{15}\)

\(\Leftrightarrow 5(4x-1)-(2-x)\leq 3(10x-3)\)

\(\Leftrightarrow 9x\geq 2\Leftrightarrow x\geq \frac{2}{9}\)

b) 

\(\frac{1-2x}{4}-2\leq \frac{1-5x}{8}+x+2\Leftrightarrow \frac{1-2x-8}{4}\leq \frac{3x+17}{8}\)

\(\Leftrightarrow 2(-2x-7)\leq 3x+17\)

\(\Leftrightarrow 7x\geq -31\Leftrightarrow x\geq \frac{-31}{7}\)

Bài 3:

Đổi 10 giờ 30 phút thành 10,5 giờ

Theo bài ra ta có:

$\frac{AB}{45}+\frac{AB}{35}=10,5$

$\Leftrightarrow AB.\frac{16}{315}=10,5$

$\Leftrightarrow AB\approx 206,7$ (km)