9/2 +9/4+9/8+....+9/128+9/256
9 + 9/2 + 9/4 + 9/8 + ... + 9/128 + 9/256
Dấu gạch chéo là đường kẻ giữa tử và mẫu
Ta có : \(9+\frac{9}{2}+\frac{9}{4}+......+\frac{9}{128}+\frac{9}{256}\)
\(=9\left(1+\frac{1}{2}+\frac{1}{4}+.....+\frac{1}{128}+\frac{1}{256}\right)\)
Đặt \(A=1+\frac{1}{2}+\frac{1}{4}+.....+\frac{1}{128}+\frac{1}{256}\)
=> \(2A=2+1+\frac{1}{2}+\frac{1}{4}+.....+\frac{1}{128}\)
=> \(2A-A=2-\frac{1}{256}\)
=> \(A=\frac{511}{256}\)
Thay A vào ta có : \(9.\frac{511}{256}=\frac{4599}{256}\)
Tính bằng cách thuận tiện nhất :
a) 9+ 9/2 + 9/4 + 9/8 + ... +9/128+ 9/256
b) 5/3 + 5/3x5 + 5/5x7 + ... + 5/101x103
b ) Đặt \(A=\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{101.103}\)
\(\Rightarrow A=\frac{5}{2}\left(\frac{5}{1}-\frac{5}{3}+\frac{5}{3}-\frac{5}{5}+....+\frac{5}{101}-\frac{5}{103}\right)\)
\(\Rightarrow A=\frac{5}{2}\left(5-\frac{5}{103}\right)\)
Bai tap:tinh bang cach thuan tien nhat:
a 1/3+2/3+...+10/3+11/3=
b 9+9/2+9/4+9/8+...+9/128+9/256=
c) 5/3+5/3.5+5/5.7+...+5/101.103=
a) = \(\frac{1+2+3+..+11}{3}=\frac{\left(1+11\right)+\left(2+9\right)+..+\left(5+7\right)+6}{3}=\frac{12.5+6}{3}=\frac{66}{3}=22\)
b) A = \(9+\frac{9}{2}+\frac{9}{4}+\frac{9}{8}+...+\frac{9}{128}+\frac{9}{256}\)
2 x A = 18 + 9 + \(\frac{9}{2}+\frac{9}{4}+\frac{9}{8}+...+\frac{9}{128}\)
Lấy 2 x A - A = 18 - \(\frac{9}{256}\)
A = 4599/256
c) \(B=\frac{5}{1\times3}+\frac{5}{3\times5}+\frac{5}{5\times7}+...+\frac{5}{101\times103}\)
\(B=\frac{5}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{25}{101\times103}\right)\)
\(B=\frac{5}{2}\times\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{101}-\frac{1}{103}\right)=\frac{5}{2}\times\left(1-\frac{1}{103}\right)\)= 255/103
a,1/3+2/3+...+3 1/3+3 2/3=...........
b,9+9/2+9/4+9/8+...+9/128+9/256=...........
c,5/3+5/3*5+5/5*7+...+5/101*103=.......
* là dấu nhân ,còn 3 2/3 là hỗn số
Các bạn giúp mình nhanh với nhé
c: Ta có: \(\dfrac{5}{3}+\dfrac{5}{3\cdot5}+\dfrac{5}{5\cdot7}+...+\dfrac{5}{101\cdot103}\)
\(=\dfrac{5}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{101\cdot103}\right)\)
\(=\dfrac{5}{2}\left(1-\dfrac{1}{103}\right)\)
\(=\dfrac{5}{2}\cdot\dfrac{102}{103}\)
\(=\dfrac{255}{103}\)
tính bằng cách thuận tiện nhất :
a. 1/3 + 2/3 + ..... + 3 1/3 + 3 2/3 = ...........
b. 9 + 9/2 + 9/4 + 9/8 + ..... + 9/128 + 9/256 = ........
c . 5/3 + 5/3*5 + 5 / 5*7 + .......+ 5/101*103 = ......
b.1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
c.1/3+1/9+1/27+1/81+1/283+1/729
giúp mình
bài 7:tính bằng cách thuận tiện nhất
a, 1/3+2/3...+3\(\frac{1}{3}\) + 3\(\frac{2}{3}\) =.......
b,9+9/2+9/4+9/8......+9/128+9/256=......
c,\(\frac{5}{3}\) + \(\frac{5}{3\cdot5}\) + \(\frac{5}{5\cdot7}\) + ......... +\(\frac{5}{101\cdot103}\) =.........
Ai gửi câu trả lời nhanh nhất sau 5 phút thì mình tick nha! ( tính nhanh!)
1/ 2 + 2 = ?
2/ 4 + 4 = ?
3/ 8 + 8 = ?
4/ 16 + 16 = ?
5/ 32 + 32 =?
6/ 64 + 64 =?
7/ 128 + 128 =?
8/ 256 + 256 =?
9/ 521 + 512 =?
10/ 2048 + 2048 =?
1/ 2 + 2 = 4
2/ 4 + 4 = 8
3/ 8 + 8 = 16
4/ 16 + 16 = 32
5/ 32 + 32 =64
6/ 64 + 64 =128
7/ 128 + 128 =256
8/ 256 + 256 =512
9/ 521 + 512 =1033
10/ 2048 + 2048 =4096
tính nhanh p/s 1+ 5/4 + 5/8 + 5/16 + 5/32 + 5/64
b) 1/3 +1/9 + 1/27 + 1/81 +...........+ 1/59049
c) 3/2 + 3/8 + 3/32 +3/128 + 3/512
d) 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 giúp mình với
b: A=1/3+1/9+...+1/3^10
=>3A=1+1/3+...+1/3^9
=>A*2=1-1/3^10=(3^10-1)/3^10
=>A=(3^10-1)/(2*3^10)
c: C=3/2+3/8+3/32+3/128+3/512
=>4C=6+3/2+...+3/128
=>3C=6-3/512
=>C=1023/512
d: A=1/2+...+1/256
=>2A=1+1/2+...+1/128
=>A=1-1/256=255/256