\(B=\frac{10}{18}\times\frac{22}{30}\times\frac{36}{44}\times...\times\frac{200}{209}=\frac{1\times10}{2\times9}\times\frac{2\times11}{3\times10}\times\frac{3\times12}{4\times11}\times...\times\frac{10\times20}{11\times19}\)

\(=\frac{1\times10\times2\times11\times3\times12\times...\times10\times20}{2\times9\times3\times10\times4\times11\times...\times11\times19}=\frac{\left(1\times2\times3\times...\times10\right)\times\left(10\times11\times12\times...\times20\right)}{\left(2\times3\times4\times...\times11\right)\times\left(9\times10\times11\times...\times19\right)}\)

\(=\frac{1\times20}{11\times9}=\frac{20}{99}\)

Sửa đề \(C=\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{9}\right)\times\left(1-\frac{1}{16}\right)\times...\times\left(1-\frac{1}{100}\right)\)

\(=\frac{3}{4}\times\frac{8}{9}\times\frac{15}{16}\times...\times\frac{99}{100}=\frac{3\times8\times15\times...\times99}{4\times9\times16\times...\times100}=\frac{1\times3\times2\times4\times3\times5\times...\times9\times11}{2\times2\times3\times3\times4\times4\times...\times10\times10}\)

\(=\frac{\left(1\times2\times3\times....\times9\right)\times\left(3\times4\times5\times...\times11\right)}{\left(2\times3\times4\times...\times10\right)\times\left(2\times3\times4\times...\times10\right)}=\frac{1\times11}{10\times2}=\frac{11}{20}\)

b) C=(1- 1/4) x (1- 1/9) x (1-1/16) x (1- 1/100)

C = 3/4 . 8/9 . 15/16.......99/100

C= 3.8.15....99/4.9.16...100

C= 1.3.2.4.3.5....9.11/ 2.2.3.3.4.4......10.10

C= 1.2.3.4...9/ 2.3.4.5....10 . 3.4.5....11/ 2.3.4.5...10

C= 1/10 . 11/2

C= 11/20

Mk nghĩ đề nt mới đúng 

Câu a) để sau

b)\(C=\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)\left(1-\frac{1}{100}\right)\)

\(C=\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot\frac{99}{100}\)

\(C=\frac{3\cdot8\cdot15\cdot99}{4\cdot9\cdot16\cdot100}\)

\(C=\frac{3\cdot4\cdot2\cdot3\cdot5\cdot11\cdot9}{2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot5\cdot20}=\frac{11\cdot9}{2\cdot4\cdot20}=\frac{99}{160}\)

#)Giải :

\(\left(1-\frac{3}{4}\right)x\left(1-\frac{3}{7}\right)x\left(1-\frac{3}{10}\right)x\left(1-\frac{1}{13}\right)x...x\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}x\frac{4}{7}x\frac{7}{10}x...x\frac{94}{97}x\frac{97}{100}\)

\(=\frac{1x4x7x...x94x100}{4x7x10x...x97x100}\)

\(=\frac{1}{100}\)

           #~Will~be~Pens~#

\(\left(1-\frac{3}{4}\right)\left(1-\frac{3}{7}\right)\left(1-\frac{3}{10}\right)\left(1-\frac{1}{13}\right)...\left(1-\frac{1}{97}\right)\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.\frac{10}{13}...\frac{94}{97}.\frac{97}{100}\)

\(=\frac{1}{100}\)

\(\left(1-\frac{3}{4}\right)\left(1-\frac{3}{7}\right)\left(1-\frac{3}{10}\right)....\left(1-\frac{3}{100}\right)\)

\(\frac{1}{4}.\frac{4}{7}.\frac{7}{10}....\frac{94}{97}.\frac{97}{100}\)

Rút gọn đi (gạch chéo ý)

\(=\frac{1}{100}\)

Chúc bạn học tốt !!!

Bài 10: \(1^2+2^2+3^2+...+n^2=\frac{n.\left(n+1\right).\left(2n+1\right)}{6}\)

\(A=1+4+9+16+...+100=1^2+2^2+3^2+4^2+...+10^2=385\)

Bài 11:

\(B=1^2+2^2+3^2+...+100^2=\frac{100.\left(100+1\right).\left(2.100+1\right)}{6}=338350\)

tớ lm đc câu a thui nha

1+4+

10) Số số hạng là: \(\frac{100-1}{3}+1=34\)

=> Tổng: \(\frac{\left(100+1\right).34}{2}=1717\)

a: \(=68\cdot72\cdot49\cdot\left[324-324\right]=0\)

b: \(=\left(1250-1250\right)\cdot\left(1+...+100\right)=0\)

\(a,\left(68\times72\times49\right)\times\left(27\times12-9\times36\right)=\left(68\times72\times49\right)\times0=0\\ b,\left(25\times50-125\times10\right)\times\left(1+2+...+100\right)=0\times\left(1+2+...+100\right)=0\)

a, ( 68 × 72 × 49 ) × ( 27 × 12 − 9 × 36 ) = ( 68 × 72 × 49 ) × 0 =

b, ( 25 × 50 − 125 × 10 ) × ( 1 + 2 + ... + 100 ) = 0 × ( 1 + 2 + ... + 100 ) = 0

Bài 1 :

\(A=1+2+3+4+5+6+7+8+9\)

   \(=\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5\)

   \(=10+10+10+10+5\)      

   \(=45\)

Bài 2 bạn tự làm nha

Bài 2 : Tìm x :

a) ( x - 8 )⁵ = ( x - 8 )⁹

=> x - 8 thuộc { 0 ; 1 } vì :

Nếu x - 8 = 0 thì ( x - 8 )⁵ = 0⁵ = 0

Nếu x - 8 = 0 thì ( x - 8 )⁹ = 0⁹ = 0

Vậy x - 8 = 0 là thỏa mãn điều kiện.

Nếu x - 8 = 1 thì ( x - 8 )⁵ = 1⁵ = 1

Nếu x - 8 = 1 thì ( x - 8 )⁹ = 1⁹ = 1

Vậy x - 8 = 1 là thỏa mãn điều kiện.

=> x - 8 thuộc { 0 ; 1 }

=> x thuộc { 8 ; 9 }

Bài 2 : Tìm x :

b) ( x + 1 ) + ( x + 2 ) +.....+ ( x + 100 ) = 5750

    100x + ( 1 + 2 + 3 + 4 + .....+ 100 )   = 5750

    100x +                  5050                    = 5750

    100x                                                = 5750 - 5050

    100x                                                 =      700

         x                                                  = 700 : 100

         x                                                   =      7

ủa sao ổng ko trả lời nhỉ

a, =13x(27+2x35+4-1)=13x100=1300

b, =(99-99):(1x2x...x10)=0

tick nha!

mà đây là môn toán mà

    = ( 125 x 0,75 + 125 x 25% ) x ( 9 x 11 - 0,9 x 100 - 0,9 x10 )
    = ( 125 x 0,75 + 125 x 0,25 ) x ( 9 x 11 - 9 x 10 - 9 x 1 )
    = 125 x ( 0,75 + 0,25 ) x ( 9 x 11 - 9 x 10 - 9 x 1 )
    =  125 x 9 x ( 11-10 -1 )
    =    125 x 9 x 0
    =        0