tính
a)1-1/5
b)8+1/34
c)2/5+1/4
ét o ét
tính
a)1-1/5
b)8+1/34
c)2/5+1/4
tui cần câu trả lười chi tiết chứ hok phải là kết quả lun đâu nhá =(((
5/5-1/5
=4/5
272/34+1/34
=273/33
2/5+1/4
=8/20+5/20=13/20
\(\dfrac{1}{1}-\dfrac{1}{5}=\dfrac{5}{5}-\dfrac{1}{5}=\dfrac{4}{5}\)
\(\dfrac{8}{1}+\dfrac{1}{34}=\dfrac{272}{34}+\dfrac{1}{34}=\dfrac{273}{34}\)
\(\dfrac{2}{5}+\dfrac{1}{4}=\dfrac{8}{20}+\dfrac{5}{20}=\dfrac{13}{20}\)
6. ÉT O ÉT
\(\dfrac{9}{7}\) và \(\dfrac{5}{6}\) \(\dfrac{4}{7}\) và \(\dfrac{8}{21}\) \(\dfrac{2}{5};\dfrac{1}{3}\) và \(\dfrac{1}{2}\) \(\dfrac{1}{3};\dfrac{4}{3}\) và\(\dfrac{1}{5}\)
a: 9/7>1>5/6
b: 4/7=12/21>8/21
c: 2/5=12/30
1/3=10/30
1/2=15/30
mà 10<12<15
nên 1/3<2/5<1/2
Ét o ét🆘
C=1/(-5)+1/(-5)^2+1/(-5)^3+…+1/(-5)^99
(x-3y)^2006+(y+4)^2008=0
Hép mi hép mi
\(C=\dfrac{-1}{5}+\left(\dfrac{1}{-5}\right)^2+\left(-\dfrac{1}{5}\right)^3+...+\left(-\dfrac{1}{5}\right)^{99}\)
=>\(5\cdot C=-1+\left(-\dfrac{1}{5}\right)+\left(-\dfrac{1}{5}\right)^2+...+\left(-\dfrac{1}{5}\right)^{98}\)
=>\(5\cdot C-C=\left(-1\right)-\left(-\dfrac{1}{5}\right)^{99}\)
=>\(4C=-1+\dfrac{1}{5^{99}}=\dfrac{-5^{99}+1}{5^{99}}\)
=>\(C=\dfrac{-5^{99}+1}{4\cdot5^{99}}\)
(x-3y)^2006+(y+4)^2008=0
=>x-3y=0 và y+4=0
=>x=3y và y=-4
=>x=3*(-4)=-12 và y=-4
\(\dfrac{7}{5}X\dfrac{2}{5}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}X\dfrac{1}{2}\)
35864:175
247x328
ÉT O ÉT
247 X 328 = 81016
35864:175= 35864/175
\(\dfrac{7}{5}x\dfrac{2}{5}=\dfrac{14}{25}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}x\dfrac{1}{2}=\dfrac{3}{4}+5x\dfrac{1}{2}=\dfrac{5}{2}\)
7/5 x 2/5 = 14/25
3/4 + 5/4 : 1/4 x 1/2 = 13/4
cú t ccau oiii ét ô ét giải giúp t bài này zới
4,7 : 0,25 + 5,3 x 4
3x ( a - 2) +150 = 240
1/9 + a + 7/12 = 17/18
( 1/2 x 1/3 + 1/3 x 1/4 + 1/4 x 1/5 + 1/5 x 1/6 + 1/6 x 1/7 + 1/7 x 1/8 ) x a = 9/16
\(4,7\div0,25+5,3\times4\)
\(=18,8+21,2\)
\(=40\)
\(3\times\left(a-2\right)+150=240\)
\(3\times\left(a-2\right)=90\)
\(a-2=30\)
\(a=32\)
\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)
\(\dfrac{1}{9}+a=\dfrac{13}{36}\)
\(a=\dfrac{1}{4}\)
\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)
\(a=\dfrac{3}{2}\)
Tìm X
a)8/X+1/5=2/5+1/3
B)(X-3/5):1/5=5/8
ÉT Ô ÉT
a) \(\dfrac{8}{x}+\dfrac{1}{5}=\dfrac{2}{5}+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\dfrac{8}{x}=\dfrac{11}{15}-\dfrac{1}{5}=\dfrac{8}{15}\)
\(x=\dfrac{8\times15}{8}=15\)
B) \(\left(x-\dfrac{3}{5}\right)=\dfrac{5}{8}\times\dfrac{1}{5}=\dfrac{1}{8}\)
\(x=\dfrac{1}{8}+\dfrac{3}{5}=\dfrac{29}{40}\)
1. Rút Gọn
a)√6-2√5
b)√8+2√7
2 Tính
a) √(√10-3)2 -√10
b)√(5+√7)2 - √8-2√7
\(1,\)
\(a,\sqrt{6-2\sqrt{5}}=\sqrt{\sqrt{5^2}-2.\sqrt{5}.1+1}=\sqrt{\left(\sqrt{5}-1\right)^2}=\left|\sqrt{5}-1\right|=\sqrt{5}-1\)
\(b,\sqrt{8+2\sqrt{7}}=\sqrt{\sqrt{7^2}+2.\sqrt{7}.1+1}=\sqrt{\left(\sqrt{7}+1\right)^2}=\left|\sqrt{7}+1\right|=\sqrt{7}+1\)
\(2,\)
\(a,\sqrt{\left(\sqrt{10}-3\right)^2}-\sqrt{10}\)
\(=\left|\sqrt{10}-3\right|-\sqrt{10}\)
\(=\sqrt{10}-\sqrt{10}-3\)
\(=-3\)
\(b,\sqrt{\left(5+\sqrt{7}\right)^2}-\sqrt{8-2\sqrt{7}}\)
\(=\left|5+\sqrt{7}\right|-\sqrt{\left(\sqrt{7}-1\right)^2}\)
\(=5+\sqrt{7}-\left|\sqrt{7}-1\right|\)
\(=5+\sqrt{7}-\sqrt{7}+1\)
\(=6\)
Tính:
1/5 x 7 + 1/ 7 x 9 +....+ 1/2011 x 2013
Ét u ét à nhầm Ét ô ét
\(A=\dfrac{1}{2}\times\left(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)=\dfrac{1}{2}\times\left(\dfrac{1}{5}-\dfrac{1}{2013}\right)=\dfrac{1004}{10065}\)
Tính tổng S = 1 + 2 + 3 + ... + n + ... cho đến khi S>50000. Điều kiện nào sau đây cho vòng lặp while - do là đúng:
A. While S >= 5000
B. While S < 5000 do
C. While S < 50000 do
D. While S>=50000 do
ét o ét, ét o ét, ét o étttttttttttt
tụi chị ghê, thui để em trả lời cho =3
C