giống bài mình cần mà ko có ai trả lời nhỉ

mong mọi người vô giúp 2 đứa mình với

B=81.(12.(1-1/7-1/289-1/85)/4.(1-1/7-1/289-1/85:5.(1+1/13+1/169+1/91)/6.(1+1/13+1/169+1/91).158158158/711711711

  =81.(12/4:5/6).158.1001001/711.1001001

=81.18/5.158/711

=324/5

\(-2,4\cdot\dfrac{17}{4}+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}\right)-2,4\cdot\left(-5\dfrac{5}{4}\right)-\dfrac{12}{7}\cdot\left(-\dfrac{71}{6}\right)\)

\(=-2,4\cdot\dfrac{17}{4}-2,4\cdot\left(-\dfrac{25}{4}\right)+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}\right)+\dfrac{12}{7}\cdot\dfrac{71}{6}\)

\(=-2,4\cdot\left(\dfrac{17}{4}-\dfrac{25}{4}\right)+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}+\dfrac{71}{6}\right)\)

\(=-2,4\cdot\left(-2\right)+\dfrac{12}{7}\cdot\left(-\dfrac{7}{3}\right)\)

\(=4,8-4\)

\(=0,8\)

#\(Toru\)

Ta có \(81.\left(\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{3}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}\right)\)

\(=81.\left(\frac{12.\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4.\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}:\frac{5.\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{6.\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\right)\)

\(=81.\left(\frac{12}{4}:\frac{5}{6}\right)\)

\(=81.\frac{18}{5}\)

\(=291,6\)

\(81\left(\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{159}+\frac{6}{91}}\right)\)

\(=81\left(\frac{12\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}:\frac{5\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{6\left(1+\frac{1}{13}+\frac{2}{169}+\frac{1}{91}\right)}\right)\)

\(=81\left(3\div\frac{5}{6}\right)\)

\(=81.\frac{18}{5}\)

\(=\frac{1458}{5}\)

81.[12(1-1/7-1/289-1/85)/4(1-1/7-1/289-1/85):5(1+1/13+1/169+1/91)/6(1/13+1/169+1/91)

=81.[12/4:5/6]=81.[12/4.6/5]=81.18/5=1458/5

\(=81.\dfrac{12.\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}{4.\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}:\dfrac{5.\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}{6.\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}.\dfrac{158}{711}\)

\(=81.\dfrac{12}{4}:\dfrac{5}{6}.\dfrac{2}{9}\)

\(=243:\dfrac{5}{6}.\dfrac{2}{9}\)

\(=\dfrac{1458}{5}.\dfrac{2}{9}\)

\(=\dfrac{324}{5}\)

\(B=81.\left[\frac{3\left(12-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}\right)}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{6\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\right].\frac{79.2.1001001}{79.9.1001001}\)

\(B=81.\left[3.\frac{6}{5}\right].\frac{2}{9}\)

\(B=\frac{9.9.3.6.2}{5.9}\)

\(B=\frac{9.3.6.2}{5}\)

\(B=\frac{324}{5}\)

Tick cho minh nha Quang Hai Duong tick minh may man ca nam

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