Lời giải:

$2^{299}< 2^{300}=(2^3)^{100}=8^{100}$

$3^{201}> 3^{200}=(3^2)^{100}=9^{100}$

$\Rightarrow 3^{201}> 9^{100}> 8^{100}> 2^{299}$

 5^299 < 5^300 = (5^2)^150 = 25^150 

3^501 = (3^3)^167 = 27^167 

=> 27^167 > 25^150 => 3^501 > 5^299

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\(1.\)

a, \(27^{265}\)và \(81^{199}\)

\(27^{265}=\left(3^3\right)^{265}=3^{795}\)

\(81^{199}=\left(3^4\right)^{199}=3^{796}\)

\(\Rightarrow3^{795}< 3^{796}hay27^{265}< 81^{199}\)

b, \(1024^{15}=\left(2^{10}\right)^{15}=2^{150}\)

\(128^{21}=\left(2^7\right)^{21}=2^{147}\)

\(2^{150}>2^{147}.hay.1024^{15}>128^{21}\)

\(3^{299}< 3^{300}=\left(3^3\right)^{100}=27^{100}\)

\(2^{502}>2^{500}=\left(2^5\right)^{100}=32^{100}\)

Vì \(27^{100}< 32^{100}\)nên \(3^{299}< 27^{100}< 32^{100}< 2^{502}\)

thank you

5²⁹⁹ và 3⁵⁰¹

5²⁹⁹<5³⁰⁰; 3⁵⁰¹>3⁵⁰⁰

5³⁰⁰=(5³)¹⁰⁰=125¹⁰⁰

3⁵⁰⁰=(3⁵)¹⁰⁰=243¹⁰⁰

Vì 243¹⁰⁰>125¹⁰⁰ nên 3⁵⁰¹>5²⁹⁹

Bài 1:

a: Sửa đề: 1/3^200

1/2^300=(1/8)^100

1/3^200=(1/9)^100

mà 1/8>1/9

nên 1/2^300>1/3^200

b: 1/5^199>1/5^200=1/25^100

1/3^300=1/27^100

mà 25^100<27^100

nên 1/5^199>1/3^300

1) \(5^{199}< 5^{200}=25^{100}\)

\(3^{300}=27^{100}>25^{100}\)

\(\Rightarrow3^{300}>5^{199}\)

\(\Rightarrow\dfrac{1}{3^{300}}< \dfrac{1}{5^{199}}\)

2)  a) \(107^{50}=\left(107^2\right)^{25}=11449^{25}\)

\(73^{75}=\left(73^3\right)^{25}=389017^{25}>11449^{25}\)

\(\Rightarrow107^{50}< 73^{75}\)

b) \(54^4< 5^{12}< 21^{12}\Rightarrow54^4< 21^{12}\)

Giúp mình với

chắc là >

2^229<3^119