(-3/4)63x-1=(3/4)^3

3x-1=3+1

3x=3=1

x=4;3

x=4/3

Vậy x=4/3

25556

\(\Leftrightarrow x-5=-4\)

\(\Leftrightarrow x=-4+5=1\)

Vậy ...

(x - 5)³ = - 64

\(\Rightarrow\) (x - 5)³ = - 64 = (- 4)³

\(\Rightarrow\) x - 5 = - 4

\(\Rightarrow\) x = 1

Vậy x = 1

(x - 5)³ = -64

=> x - 5³ = -64

=> x - 125 = -64

=> x = -64 + 125

=> x = 61

\(\left(x+5\right)^3=-64=\left(-4\right)^3\\ Vậy:x+5=-4\\Vậy:x=-4-5=-9 \)

\(\left(x+5\right)^3=-64\)

\(\Rightarrow\left(x+5\right)^3=\left(-4\right)^3\)

\(\Rightarrow x+5=-4\)

\(\Rightarrow x=-4-5\)

\(\Rightarrow x=-9\)

Vậy: \(x=-9\)

(x-5)³=64=4³

=>x-5=4

=>x=4+5=9

        Vậy x=9

⇒x=un=u1+(n-1)d=1+7.2=15

Đáp án C.

a) \(\left(\frac{2x}{3}-3\right)\div\left(-10\right)=\frac{2}{5}\)

\(\Rightarrow\left(\frac{2x}{3}-\frac{9}{3}\right).-\frac{1}{10}=\frac{2}{5}\)

\(\Rightarrow\frac{2x-9}{3}.-\frac{1}{10}=\frac{2}{5}\)

\(\Rightarrow\frac{9-2x}{30}=\frac{2}{5}\Rightarrow\left(9-2x\right).5=60\)

\(\Rightarrow45-10x=60\Rightarrow-10x=15\Rightarrow x=-\frac{15}{10}=-1,5\)

b)\(\left(x+5\right)^3=64\)

\(\Rightarrow\left(x+5\right)^3=4^3\)

\(\Rightarrow x+5=4\Rightarrow x=-1\)

A, 2x/3-3=-4

2x/3=-1

2x=-3

X=-3/2

B,(x+5)^3=4^3

=> x+5=4

X=-1

k nha

b) x+5 =4

x=-1

\(a.\left(x+5\right)^3=-64\Leftrightarrow x+5=-4\Leftrightarrow x=-9\\ b.\left(2x-3\right)^2=9\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\) 

( Nhớ kết luận! )

a.

\(\left(x+5\right)^3=\left(-4\right)^3\)

\(\Leftrightarrow x+5=-4\)

\(\Leftrightarrow x=-9\)

b.

\(\left(2x-3\right)^2=3^2\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)

\(\left(x+5\right)^3=\left(-4\right)^3\)

=-9

Vậy 

(9 không được)

\(\left(2x-3\right)^3=2^3\)

P/s Nhớ tick cho mình nha. Thanks bạn

1.

a) \(2^x=128\)

\(2^x=2^7\)

\(=>x=7\)

b) \(8^{x-1}=64\)

\(8^{x-1}=8^2\)

\(=>x-1=2\)

\(x=2+1\)

\(=>x=3\)

c) \(3+3^x=30\)

\(3^x=30-3\)

\(3^x=27=3^3\)

\(=>x=3\)

d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?

e) \(3^2.x=3^5\)

\(x=3^5:3^2\)

\(=>x=3^3=27\)

f) \(\left(2x-1\right)^3=343\)

\(\left(2x-1\right)^3=7^3\)

\(=>2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=8:2\)

\(=>x=4\)

\(#Wendy.Dang\) 

a,\(2^x\)=128           b,\(8^{x-1}\)=64              c,3+\(3^x\)=30           d,x+2=64

\(2^7\)=128               \(8^{x-1}\)=\(8^2\)                 \(3^x\)=30-3                  x=64-2

=>x=7              =>x-1=2                  \(3^x\)=27                      x=62

                         x=2+1=3                \(3^x\)=\(3^3\)

                                                     =>x=3

e,\(3^2\).x=\(3^5\)                             f,(2x-\(1^3\))=343

x=\(3^5\):\(3^2\)                                 2x=1+343

x=27                                     2x=344

                                               x=344:2

                                               x=172