\(=\left(1+3+...+2021\right)\cdot\left[1001\cdot135\cdot137-1001\cdot135\cdot137\right]\)

\(=\left(1+3+...+2021\right)\cdot0\)

=0

= (1 + 3 + ... + 2021) x (135 x 1001 x 137 - 135 x 137 x 1001)

= (1 + 3 + ... + 2021) x 0

= 0

` ( 1+ 3 + 5 + 7 + ... + 2021 ).(135135.137 - 135.137137 )`

` = ( 1+ 3 + 5 + 7 + ... + 2021 ). ( 18513495 - 18513495)`

` = ( 1+ 3 + 5 + 7 + ... + 2021 ). 0`

` = 0`

= [ 1 + 3 + 5 + ......+ 2002 ] . [ 135 . 1001 . 137 - 105 . 1001 . 137 ]

= [ 1 + 3 + 5 + ..... + 2002 ] . 0

= 0

(1 + 3 + 5 + 7 + ... + 2002) . (135135 . 137 - 135 . 137137)

= (1 + 3 + 5 + 7 + ... + 2002) . (135 . 1001 . 137 - 135 . 137 . 1001)

= (1 + 3 + 5 + 7 + ... + 2002) . 0

= 0

(1 + 3 + 5 + 7 + ... + 2002) . (135135 . 137 - 135 . 137137)

= (1 + 3 + 5 + 7 + ... + 2002) . (135 . 1001 . 137 - 135 . 137 . 1001)

= (1 + 3 + 5 + 7 + ... + 2002) . 0

= 0

\(\left(1+3+5+...+2015\right)\left(135135.137-135.137137\right)\)

\(=\left(1+3+5+...+2015\right)\left(135.1001.137-135.1001.137\right)\)

\(=\left(1+3+5+...+2015\right).0\)

\(=0\)

cảm ơn bạn dung nhé

à không chị Dùng chứ

\(A=\left(1+3+5+...+2002\right).\left(135135.137-135.137137\right)\)

Đặt : \(C=135135.137-135.137137\)

\(C=\left(135.1001\right).137-135.137137\)

\(C=135.\left(137.1001\right)-135.137137\)

\(C=135.137137-135.137137\)

\(C=0\)

Thay vào ta có :

\(A=\left(1+3+5+...+2002\right).0\)

\(A=0\)

Vậy A = 0

\(B=1.2+2.3+3.4+...+99.100\)

\(3B=1.2.3+2.3.3+3.4.3+...+99.100.3\)

\(3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\left(101-98\right)\)

\(3B=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100\)

\(3B=999900\)

\(\Rightarrow B=333300\)

Vậy B = 333300

Gọi A là biểu thức ta có:
B = 1.2+2.3+3.4+......+99.100
Gấp A lên 3 lần ta có:
B . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
B . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98)
B. 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100
B . 3 = 99.100.101
B = 99.100.101 : 3
B = 33.100.101
B = 333 300

(1+3+5+7+...+2002).(135135.137-135.137137)

= (1+3+5+7+...+2002). (135.1001.137-135.137.1001)

= (1+3+5+7+....+2002).0 

= 0 
Vậy kết quả bằng 0 nhé

A love you

Xinh vai

(1+3+5+7+...+2002).(135135.137-135.137137)

= (1+3+5+7+...+2002). (135*1001*137-135*137*1001)

= (1+3+5+7+....+2002).0 

= 0 

Chúc bạn học tốt nha!!!

a) \(10+11+12+...+99=\dfrac{\left(99+10\right)\left(\dfrac{99-10}{1}+1\right)}{2}=4905\)

b) \(1+6+11+...+51=\dfrac{\left(51+1\right)\left(\dfrac{51-1}{5}+1\right)}{2}=286\)

c) \(\left(1+3+5+...+2017\right)\left(135135.137-135.137137\right)=\left(1+3+5+...+2017\right)\left[1001\left(135,137-135.137\right)\right]=\left(1+3+5+...+2017\right).0=0\)

a)
=10+(11+99)+(12+98)+.....+(54+56)+55
=10+55+110+110+...+110
=10+55+110.(99-11):2
=10+55+110.44
=65+4840=4905