\(=\dfrac{7}{23}\left(\dfrac{8}{11}-\dfrac{3}{11}\right)-\dfrac{16}{23}=\dfrac{7}{23}\cdot\dfrac{5}{11}-\dfrac{16}{23}=-\dfrac{141}{253}\)

=-85/23-2/7-7/23+9/7

=(-2/7+9/7)+(-85/23-7/23)

=1+(-92/23=-4)

=-3

=

\(-3-\dfrac{16}{23}-\dfrac{2}{7}-\dfrac{7}{23}+\dfrac{9}{7}\)

\(=-3-\left(\dfrac{16}{23}+\dfrac{7}{23}\right)-\left(\dfrac{2}{7}-\dfrac{9}{7}\right)\)

\(=-3-\dfrac{23}{23}-\dfrac{-7}{7}\)

\(=-3-1-\left(-1\right)\)

\(=-3-1+1\)

\(=-3\)

Ai rảnh mà làm hộ mày, ngu như con chó mới không biết làm

khó hiểu quá

mày bảo tao ngu mày cũng ngu thế thôi câm mồm đi

đéo làm đc cứ thích sĩ

\(A=\frac{7}{3\times13}+\frac{7}{13\times23}+...+\frac{7}{53\times63}\)

\(A=\frac{7}{10}.\left[\left(\frac{1}{3}-\frac{1}{13}\right)+\left(\frac{1}{13}-\frac{1}{23}\right)+....+\left(\frac{1}{53}-\frac{1}{63}\right)\right]\)

\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+....+\frac{1}{53}-\frac{1}{63}\right)\)

\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{63}\right)\)

\(A=\frac{7}{10}.\frac{20}{63}\)

\(A=\frac{2}{9}\)

7/23.5/29+7/29.18/23-7/29

=(7.5)/(23.29)+7/29.18/23-7/29

=7/29.5/23+7/29.18/23-7/29.1

=7/29.(5/23+18/23-1)

=7/29.(1-1)

=7/29.0

=0

\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)

\(=\frac{7}{29}\cdot0\)

\(=0\)

\(=\dfrac{4}{7}-\dfrac{23}{17}-\dfrac{11}{7}+\dfrac{23}{17}-\dfrac{4}{7}\)

\(=\dfrac{4}{7}-\dfrac{4}{7}-\dfrac{23}{17}+\dfrac{23}{17}\)

\(=0-0\)

\(=0\)

Ta có: \(23\dfrac{1}{4}:\left(-\dfrac{3}{7}\right)-23\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)\)

\(=\dfrac{93}{4}\cdot\dfrac{-7}{3}-\dfrac{93}{4}\cdot\dfrac{-7}{5}\)

\(=\dfrac{93}{4}\cdot\left(-\dfrac{7}{3}+\dfrac{7}{5}\right)\)

\(=\dfrac{93}{4}\cdot\dfrac{-14}{15}=-\dfrac{217}{10}\)

Bn hâm mộ lewandoski à? Ghi 41 bàn ở mùa giải 2020 - 2021 đó