The number of solutions of the below polynomial:
\(3x^2+8x^3+x^4+9+\left(-2x\right)^3-3x^2\)
(Giai dum mk nha, ai gioi TA thj dik de dum luon nha!)
the number of factors of 120 is
ai dich dum mik cau nay lun nha vc tu factors nha mik tang 2 tick
5x + 4 - 3 . 5x +3 = 511 . 2
Giup mk vs nhe, giai dum luon nha
5^x+3(5-1*3)=5^11*2
5^x+3*2=5^11*2
5^x+3=5^11
x+3=11
x=8
find the value of n such that the polynomial 2x^5 - 3x^3 + x^2 +n is divisible by the polynomial x+2
tìm giá trị của n sao cho đa thức 2x ^ 5 - 3x ^ 3 + x ^ 2 + n chia hết cho đa thức x + 2
The product of 6 and the greatest 1-digit number is ..... ( Nho dich dum va giai thich lam the nao de ra ket qua )
thực hiện phép tinh sau ; (x^3+X^2-3x+9):(x+3) ai giai dum với
= [(x^3+3x^2)-(2x^2+6x)+(3x+9)] : (x+3)
= (x+3).(x^2-2x+3) : (x+3) = x^2-2x+3
k mk nha
x^2-2x+3 nhé
nhớ đặt tính ra chia nha
tốn 1%calo não của mjk đó
let P(x) be a polynomial of degree 3 and x1, x2, x3 are the solutions of P(x)=0. let \(\frac{P\left(\frac{1}{3}\right)-P\left(\frac{-1}{3}\right)}{P\left(0\right)}=8,\frac{P\left(\frac{1}{4}\right)-P\left(\frac{-1}{4}\right)}{P\left(0\right)}=9\)and x1+x2+x3 = 35. find the value of \(\frac{x2+x3}{x1}+\frac{x1+x3}{x2}+\frac{x1+x2}{x3}\)
Chung to gia tri cua bieu thuc ko phu thuoc vao gia tri cua bien: M=(3+x)-(4x+1)-x(2+x)
Ai giai dum☺cach lam luon nha
\(M=\left(3+x\right)-\left(4x+1\right)-x\left(2+x\right)\)
\(=3+x-4x-1-2x-x^2\)
\(=-x^2-5x+2\)
Đề sai !
the number of solutions to the polynomial x^8 + 8 is......
the number of solutions to the polynomial x^8+8 is