1)4x^2-4x+1
2)36+12x-x^2
3)x^2-6y^2
4)27x^3-1/64
5)(ax+by)^2-(ay+bx)^2
6)(x+y)3-x^3-y^3
7)3x-3y-x^2+2xy-y^2
A.5x^2y^3-25x^3y^4+10x^3y^3
B.12x^2y-18xy^2-30y^2
C.5(x-y)-y(x-y)
D.y(x-z)+7(z-x)
E.27x^2(y-1)-9x^3(1-y)
F.36-12x+x^2
G.x^2+2xy+y^2-xz-yz
H.x^4+64
I.27x^2(y-1)-9x^3(1-y)
K.36-12x+x^2
M.-4x^2+4x-1
N.x^2+5x+6
P.x^2-x-6
Q.x^4-5x^2+4
PP nhóm
1)x^2+x-y^2+y
2)4x^2-9y^2+4x-6y
3)x^2+x+y^2+y+2xy
4)-x^2+5x+2xy-5y-y^2
5)x^2-y^2+2x+1
6)x^2-1-y^2+2y
7)x^2+2xz-y^2+2uy+z^2-u^2
8)x^3+3x^2y+x+3xy^2+y+y^3
9)x^3+y(1-3x^2)+x(3y^2-1)-y^3
10)27x^3+27x^2+9x+1+x+1/3
1) x2 + x - y2 + y = (x2 - y2) + (x + y) = (x - y)(x + y) + (x + y) = (x - y + 1)(x + y)
2) 4x2 - 9y2 + 4x - 6y = (4x2 - 9y2) + (4x - 6y) = (2x - 3y)(2x + 3y) + 2(2x - 3y) = (2x - 3y)(2x + 3y + 2)
3) x2 + x + y2 + y + 2xy = (x2 + 2xy + y2) + (x + y) = (x + y)2 + (x + y) = (x + y)(x + y + 1)
4) -x2 + 5x + 2xy - 5y - y2 = -(x2 - 2xy + y2) + (5x - 5y) = -(x - y)2 + 5(x - y) = (x - y)(y - x + 5)
5) x2 - y2 + 2x + 1 = (x2 + 2x + 1) - y2 = (x + 1)2 - y2 = (x + 1 + y)(x - y + 1)
6) x2 - 1 - y2 + 2y = x2 - (y2 - 2y + 1) = x2 - (y - 1)2 = (x - y + 1)(x + y - 1)
7) x2 + 2xz - y2 + 2uy + z2 - u2 =(x2 + 2xz + z2) - (y2 - 2uy + u2) = (x + z)2 - (y - u)2 = (x + z - y + u)(x + z + y - u)
8) x3 + 3x2y + x + 3xy2 + y + y3 = (x3 + 3x2y + 3xy2 + y3) + (x + y) = (x + y)3 + (x + y) = (x + y)(x2 + 2xy + y2 + 1)
9) x3 + y(1 - 3x2) + x(3y2 - 1) - y3 = x3 + y - 3x2y + 3xy2 - x - y3 = (x3 - 3x2y + 3xy2 - y3) - (x - y) = (x - y)3 - (x - y) = (x - y)(x2 - 2xy+y2-1)
1/ tìm GTNN
4x^2+y^2-4x-2y+3
X^2+y^2+2*(x-2y)y+6
2 phân tich đa thức thành nhân tử
(x+y)^2-25(x+y)+24
2x^3y-2xy-4xy-2xy
y^2 +3xy+3y^2 (y#0)
(x^2+4x+8)^2-3x(x^2+4x+8) +x^2
x^3-y^3-3x+3y
x^4+6x^2+13x^2+12x+4
Phân tích đa thức thành nhân tử
1: ax+ay-4x-4y
2: x^2+ab+ax+bx
3: ax+a-bx-b+cx+c
4: ab(x^2+y^2)+xy(a^2+b^2)
5: ab(x^2+1)+x(a^2+b^2)
6: x^2-2xy+y^2-4
7: x^2-y^2+4x+4
8: x^2-2xy+y^2-1
9: 9-x^2-2xy-x^2
10: 25-x^2+4xy-4y^2
11: x^2+xy+xz-x-y-z
12: x^2-2xy+3xz+x-2y+3z
13: 4x^2-9y^2-4x-6y
14: x^3-y^3+2x^2-2y^2
15: x^2+y^2+2xy+yz+zx
16: x^3+y^3+x^2y+xy^2+xz^2+yz^2
Mọi người vào giải hộ em với, em đang cần gấp ạ :))
1: \(=a\left(x+y\right)-4\left(x+y\right)=\left(x+y\right)\left(a-4\right)\)
2: \(=x\left(x+b\right)+a\left(x+b\right)=\left(x+b\right)\left(x+q\right)\)
3: \(=a\left(x+1\right)-b\left(x+1\right)+c\left(x+1\right)\)
\(=\left(x+1\right)\left(a-b+c\right)\)
6: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)
Bài 1. Tính
1. 4x^2 - 12x + 9
2. (x - 1/3)^2
3. (4x -x^2) . (4x + x^2)
4. (3x + 2y)^3
5. 27x^3 - 1/2
6. 8x^3 + 12xy + 6xy^2 + y^3
7. (2x + y) . (4x^2 - 2xy + y^2)
Bài 2. Rút gọn
1. (x - y) - (x + y)^2
2. (2x + 1) . (4x^2 - 2x + 1) - (2x - 1) . (4x^2 + 2x +1)
Bài 3. Tìm A
A = x^2 + y^2 - x + 6y + 10
Em cần gấp lắm ạ :( Mong anh, chị giải dùm em
( Bài 6: Phân tích thành nhân tử ( phối hợp các phương pháp )
5) 4x^5y^2 + 8x^4y^3 + 4x^3y^4 ;
9) 4x^5y^2 + 16x^4y^2 + -6x^3y^2 ;
13) -3x^4y + 6x^3y -3x^2y ;
17) 8x^3 - 8x^2y + 2xy^2 ;
21) (a^2 + 4) ^2 - 16a^2b^2 ;
25) 100a^2 - (a^2 + 25)^2 ;
29) 25a^2b^2 - 4x^2 + 4x - 1 ;
33) 1 - 2m + m^2 - x^2 - 4x - 4 ;
37) ax^2 + bx^2 + 2xy(a + b) + 2ay^2 + by^2 ;
41) 5a^2 - 5 ;
45) 9xy - 4a^2xy ;
49) -4 + 32a^3b^3 ;
53) -5x^3y^3 - 5x^3y^3 ;
57) ab(x - y)^3 + 8ab ;
61) x^2 + (a + b)xy + aby^2 ;
65) y^2 - (3b + 2a) xy + 6abx^2 ;
69) xy(a^2 + 2b^2) + ab( 2x^2 + y^2) ;
73) (xy + ab)^2 + (ay - bx)^2 ;
77) (xy - 3ab)^2 + (3ay + bx)^2 ;
5.
\(4x^5y^2+8x^4y^3+4x^3y^4=4x^3y^2(x^2+2xy+y^2)\)
\(=4x^3y^2(x+y)^2\)
9.
\(4x^5y^2+16x^4y^2-6x^3y^2=2x^3y^2(2x^2+4x-3)\)
13.
\(-3x^4y+6x^3y-3x^2y=-3x^2y(x^2-2x+1)=-3x^2y(x-1)^2\)
17.
\(8x^3-8x^2y+2xy^2=2x(4x^2-4xy+y^2)\)
\(=2x[(2x)^2-2.2x.y+y^2]=2x(2x-y)^2\)
21.
\((a^2+4)^2-16a^2b^2=(a^2+4)^2-(4ab)^2\)
\(=(a^2+4-4ab)(a^2+4+4ab)\)
25.
\(100a^2-(a^2+25)^2=(10a)^2-(a^2+25)^2\)
\(=(10a-a^2-25)(10a+a^2+25)\)
\(=-(a^2-10a+25)(a^2+10a+25)=-(a-5)^2(a+5)^2\)
29.
\(25a^2b^2-4x^2+4x-1=25a^2b^2-(4x^2-4x+1)\)
\(=(5ab)^2-(2x-1)^2=(5ab-2x+1)(5ab+2x-1)\)
33.
\(1-2m+m^2-x^2-4x-4=(m^2-2m+1)-(x^2+4x+4)\)
\(=(m-1)^2-(x+2)^2=[(m-1)-(x+2)][(m-1)+(x+2)]\)
\(=(m-x-3)(m+x+1)\)
37.
\(ax^2+bx^2+2xy(a+b)+ay^2+by^2\)
\(=x^2(a+b)+2xy(a+b)+y^2(a+b)\)
\(=(a+b)(x^2+2xy+y^2)=(a+b)(x+y)^2\)
41.
\(5a^2-5=5(a^2-1)=5(a^2-1^2)=5(a-1)(a+1)\)
bài 1 phân tích đa thức thành nhân tử bằng phương pháp đặt nhân tử chung
21)x^3-4x^2+4x
22)15x^2y+20xy^2-25xy
23)4x^2+8xy-3x-6y
24)x^3-6x^2+9x
25)x^2-xy+x-y
26)xy-2x-y^2+2y
27)x^2+x-xy-y
28)x^2+4x-y^2+4x
29)x^2-2xy+y^2-4
21, \(x^3-4x^2+4x=x\left(x^2-4x+4\right)=x\left(x-2\right)^2\)
22, \(15x^2y+20xy^2-25xy=5xy\left(3x+4y-5\right)\)
23, \(4x^2+8xy-3x-6y=4x\left(x+2y\right)-3\left(x+2y\right)=\left(4x-3\right)\left(x+2y\right)\)
24, \(x^3-6x^2+9x=x\left(x^2-6x+9\right)=x\left(x-3\right)^2\)
Tương tự :))
21.\(x^3-4x^2+4x\)
\(=x\left(x^2-4x+4\right)\)
\(=x\left(x-2\right)^2\)
22,\(15x^2y+20xy^2-25xy\)
\(=5xy\left(3x+4y-5\right)\)
23,\(4x^2+8xy-3x-6y\)
\(=4x\left(x+2y\right)-3\left(x+2y\right)\)
\(=\left(4x-3\right)\left(x+2y\right)\)
24\(x^3-6x^2+9x\)
\(=x\left(x^2-6x+9\right)\)
\(=x\left(x-3\right)^2\)
25,\(x^2-xy+x-y\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
26.\(xy-2x-y^2+2y\)
\(=x\left(x-2\right)-y\left(y-2\right)\)
\(=\left(x-y\right)\left(x-2\right)\)
27,\(x^2+x-xy-y\)
\(=\left(x^2-xy\right)+\left(x-y\right)\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
28,\(x^2+4x-y^2+4\)
\(=\left(x^2+4x+4\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2-y\right)\left(x+2+y\right)\)
29.\(x^2-2xy+y^2-4\)
\(=\left(x-y\right)^2-2^2\)
\(=\left(x-y-2\right)\left(x-y+2\right)\)
1) Rút gọn
x2 + 4x +4 \ 3x + 6 ; 12x + 3x \ 2x(x + 4)
2) Quy đồng mẫu
a/ 6 \ x2 + 4x ; 3 \ 2x + 8
b/ 1 \ x + 2 ; 1 \ (x + 2)(4x +7)
c/ y - 12 \ 6y - 36 ; 6 \ y2 - 6y
d/ 1 \ x + 3 ; 1 \ (x + 3)(x + 2) ; 1 \ (x + 2)(4x + 7)
1, a,= (x+2)^2/3.(x+2) = x+2/3
b, = 3x.(x+4)/2x.(x+4) = 3/2
k mk nha
Đặt nhân tử :
a) x^3-16x
b) x^3-3x^2-4x
c) x^2-y^2+2x+1
d) ax^2+ay-bx^2-by
e) 2x^3-4x^2+x-2
\(a.x^3-16x=x\left(x^2-16\right)=x\left(x-4\right)\left(x+4\right)\)
\(b.x^3-3x^2-4x=x^3+x^2-4x^2-4x=x^2\left(x+1\right)-4x\left(x+1\right)=\left(x+1\right)\left(x^2-4x\right)=x\left(x+1\right)\left(x-4\right)\)\(c.x^2-y^2+2x+1=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)
\(d.ax^2+ay-bx^2-by=a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)\(e.2x^3-4x^2+x-2=2x^2\left(x-2\right)+\left(x-2\right)=2x^2\left(x-2\right)\)
Giải:
a) \(x^3-16x=x\left(x^2-16\right)=x\left(x-4\right)\left(x+4\right)\)
b) \(x^3-3x^2-4x=x\left(x^2-3x-4\right)=x\left(x+4\right)\left(x-1\right)\)
c) \(x^2-y^2+2x+1=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)
d) \(ax^2+ay-bx^2-by=a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)
e) \(2x^3-4x^2+x-2=2x^2\left(x-2\right)+\left(x-2\right)=\left(2x^2+1\right)\left(x-2\right)\)
Vậy ...