a, \(\dfrac{x}{3}=\dfrac{8}{12};12:3=4\)\(;8:4=2\)

⇒\(x=\dfrac{2}{3}\)

a: \(\dfrac{x}{3}=\dfrac{8}{12}\)

nên x/3=2/3

hay x=2

b: \(x+\dfrac{1}{15}=\dfrac{1}{3}\)

\(\Leftrightarrow x=\dfrac{1}{3}-\dfrac{1}{15}=\dfrac{5}{15}-\dfrac{1}{15}=\dfrac{4}{15}\)

c: \(x\cdot\dfrac{4}{7}-\dfrac{2}{7}=\dfrac{5}{7}\)

\(\Leftrightarrow x\cdot\dfrac{4}{7}=\dfrac{5}{7}+\dfrac{2}{7}=1\)

hay x=7/4

d: \(\Leftrightarrow x\cdot\dfrac{3}{4}-\dfrac{5}{4}=-\dfrac{1}{2}\)

\(\Leftrightarrow x\cdot\dfrac{3}{4}=-\dfrac{2}{4}+\dfrac{5}{4}=\dfrac{3}{4}\)

hay x=1

A\(\frac{7}{8}+\frac{7}{12}+\frac{9}{8}+\frac{5}{12}\)

\(=\left(\frac{7}{12}+\frac{5}{12}\right)+\left(\frac{7}{8}+\frac{9}{8}\right)\)

\(=1+2\)

\(=3\)

1.

a, (x+50)*2=220

=> 2x+100=220

=> 2x = 120

=> x= 60

b, (2x-75)*12=144

=> 24x-900=144

=> 24x=1044

=>  x= 43,5

c, (47-3x)=5

=> 47-3x=5

=> 3x=42

=> x= 14

A. ( x + 50 ) x 2= 220

=> 2x + 100 = 220

=> 2x = 220 - 100

=> 2x = 120

=> x = 120 : 2

=> x = 60

B. ( 2x - 75 ) x 12 = 144

=> (2x - 75) x 12 = 144

=> 2x - 75 = 144 : 12

=> 2x - 75 = 12

=> 2x = 75 + 12 

=> 2x = 87

=> x = 87 : 2 = 43,5

C. 47 - 3x = 5

=> 3x = 47 - 5 = 42

=> x = 42 : 3

=> x = 14.

2)1 + 2 + 3 + 4 + 5 +..+ X = 2550

=> \(\frac{x.\left(x+1\right)}{2}\)=2550

=> x.(x+1) = 2550 x 2 = 5100. Mà không có 2 số liên tiếp nào nhân với nhau bằng 5100 nên x không thỏa mãn đề bài.

3)Đề sai nha bạn.

a)\(\left(x+50\right).2=220\)

\(\left(x+50\right)=220:2\)

\(x+50=110\)

\(x=110-50\)

\(x=60\)

b)\(\left(2x-75\right).12=144\)

\(\left(2x-75\right)=144:12\)

\(2x-75=12\)

\(2x=12+75\)

\(2x=87\)

\(x=87:2\)

\(x\notin N\)

c)\(\left(47-3x\right)=5\)

\(3x=47-5\)

\(3x=42\)

\(x=42:3\)

\(x=14\)

a)

\(\frac{5.12.3.7}{3.8.7.5}=\frac{1.12.1.1}{1.8.1.10}=\frac{12}{8}=\frac{3}{2}\)

b)

\(\frac{2.5.4.6}{4.3.5.7}\frac{2.1.1.2.3}{1.1.1.7}=\frac{12}{7}\)

HOK TỐT!

cảm ơn bạn

2/3 + 7/1 = 2/3 + 7 = 2/3 + 21/3 = 23/3

25/48 + 11/24 = 25/48 + 22/48 = 47/48

5/7 + 3/8 = 40/56 + 21/56 = 61/56

15/24 + 12/6 = 5/8 + 2 = 5/8 + 16/8 = 21/8

5/6 + 4/3 = 5/6 + 8/6 = 13/6

3/8 + 7/12 = 9/24 + 14/24 = 23/24

= 23/3

= 47/48

=61/56

=21/8

=13/6

= 23/24

Cảm ơn mn nhìu nhaaaaaa

\(=\left(\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}\right):\left(\dfrac{55}{132}-\dfrac{132}{132}-\dfrac{84}{132}\right)\)

\(=\dfrac{115}{-161}=-\dfrac{115}{161}\)

a) 3 2/7 - 2/5 + 5/7 - 3/5

= 3 + 2/7 - (2/5 + 3/5) + 5/7

= 3 + (2/7 + 5/7) - 1

= 3 + 1 - 1

= 3

b) 5 4/7 - 4/9 + 1 3/7 - 5/9

= 5 + 4/7 - 4/9 + 1 + 3/7 - 5/9

= (5 + 1) + (4/7 + 3/7) - (4/9 + 5/9)

= 6 + 1 - 1

= 6

a) \(3\dfrac{2}{7}-\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{3}{5}\)

\(=\left(\dfrac{23}{7}+\dfrac{5}{7}\right)-\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)

\(=4-1\)

\(=3\)

b) \(5\dfrac{4}{7}-\dfrac{4}{9}+1\dfrac{3}{7}-\dfrac{5}{9}\)

\(=\left(\dfrac{32}{7}+\dfrac{10}{7}\right)-\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)

\(=6-1\)

\(=5\)

a) \(3\dfrac{2}{7}-\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{3}{5}\)

\(=\left(\dfrac{23}{7}+\dfrac{5}{7}\right)-\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)

\(=4-1\)

\(=3\)

b) \(5\dfrac{4}{7}-\dfrac{4}{9}+1\dfrac{3}{7}-\dfrac{5}{9}\)

\(=\left(\dfrac{39}{7}+\dfrac{10}{7}\right)-\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)

\(=7-1\)

\(=6\)

a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)

    (\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)

     - \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)

     \(x\)   = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))

     \(x=\) - \(\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\) 

b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)

           \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)

          \(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)

         3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)

         3\(x\)   - 3,7 = - \(\dfrac{19}{2}\)

         3\(x\)         = - \(\dfrac{19}{2}\) + 3,7

          3\(x\)        = - \(\dfrac{29}{5}\)

           \(x\)         = - \(\dfrac{29}{5}\) : 3

           \(x\)        = - \(\dfrac{29}{15}\)

Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\) 

c; \(\dfrac{7}{9}\) : (2 + \(\dfrac{3}{4}\)\(x\)) + \(\dfrac{5}{9}\) = \(\dfrac{23}{27}\)

    \(\dfrac{7}{9}\): (2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{23}{27}\) - \(\dfrac{5}{9}\)

     \(\dfrac{7}{9}\):(2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) = \(\dfrac{7}{9}\) : \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{21}{8}\)

             \(\dfrac{3}{4}x\) = \(\dfrac{21}{8}\) - 2

             \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{5}{8}\)

               \(x\) = \(\dfrac{5}{8}\) : \(\dfrac{3}{4}\)

              \(x\) =  \(\dfrac{5}{6}\)

Vậy \(x=\dfrac{5}{6}\)