\(a,\left(x+3\right)\left(5-x\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x+3=0\\5-x=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-3\\x=5\end{matrix}\right.\)

\(c,x+17⋮x+3\\ x+3+14⋮x+3\\ 14⋮x+3\\ x+3\inƯ\left(14\right)=\left\{\pm14;\pm7\pm2;\pm1\right\}\)

Từ đó bạn tìm những giá trị của x nha!

a) 5.(x-20) = 35

(x-20) = 35:5

x-20 = 7

x = 27

b) (x+125) -301 = 56

x+125 -301 = 56

x - 176 = 56

x = 56 +176

x= 232

c) 215 + (x-21):2 = 235

(x-21):2 = 235 - 215

(x-21):2 = 20

x-21 = 20 .2

x-21 = 40

x = 61

d) (x:23 +45) .67 = 8911

(x:23 +45) = 8911 : 67

x:23+45 = 133

x:23 = 133-45

x:23 = 88

x = 88.23

x = 2024

a) 5.(x - 20) = 35

⇒ x - 20 = 35 : 5

⇒ x - 20 = 7

⇒ x = 7 + 20

⇒ x = 27

b) (x + 125) - 301 = 56

⇒ x + 125 = 56 + 301

⇒ x + 125 = 357

⇒ x = 357 - 125

⇒ x = 232

c) 215 + (x - 21) : 2 = 235

⇒ (x - 21) : 2 = 235 - 215

⇒ (x - 21) : 2 = 20

⇒ x - 21 = 20 x 2 

⇒ x - 21 = 40

⇒ x = 21 + 40

⇒ x = 61

d) (x : 23 + 45).67 = 8911

⇒ x : 23 + 45 = 8911 : 67

⇒ x : 23 + 45 = 133

⇒ x : 23 = 133 - 45

⇒ x : 23 = 88

⇒ x = 88 x 23

⇒ x = 2024

a) \(5.\left(x-20\right)=35\)

\(x-20=35:5\)

\(x-20=7\)

\(x=7+20\Rightarrow x=27\)

b) \(\left(x+125\right)-301=56\)

\(x+125=357\)

\(x=357-125\Rightarrow x=232\)

c) \(215+\left(x-21\right):2=235\)

\(\left(x-21\right):2=20\)

\(x-21=40\Rightarrow x=40+21\Rightarrow x=61\)

d) \(\left(x:23+45\right).67=8911\)

\(x:23+45=133\)

\(x:23=88\Rightarrow x=88.23\Rightarrow x=2024\)

(7.x + 1) : 2 - 23 = 2

=> (7.x + 1) : 2 = 2 + 23

=> (7.x + 1) : 2 = 25

=> 7.x + 1 = 25 . 2

=> 7.x + 1 = 50

=> 7.x = 50 - 1

=> 7.x = 49

=> x = 49 : 7 = 7

(7.x + 1) : 2 - 23 = 2

=> (7.x + 1) : 2 = 2 + 23

=> 7.x + 1 = 25 . 2

=> 7.x = 50 - 1

=> 7.x = 49

 x = 49 : 7 = 7

Vậy.............

hok tốt

b: \(\Leftrightarrow8x=41\)

hay x=41/8

1: =>3^x=81

=>x=4

2: =>2^x=8

=>x=3

3: =>x^3=2^3

=>x=2

4: =>x^20-x=0

=>x(x^19-1)=0

=>x=0 hoặc x=1

5: =>2^x=32

=>x=5

6: =>(2x+1)^3=9^3

=>2x+1=9

=>2x=8

=>x=4

7: =>x^3=115

=>\(x=\sqrt[3]{115}\)

8: =>(2x-15)^5-(2x-15)^3=0

=>(2x-15)^3*[(2x-15)^2-1]=0

=>2x-15=0 hoặc (2x-15)^2-1=0

=>2x-15=0 hoặc 2x-15=1 hoặc 2x-15=-1

=>x=15/2 hoặc x=8 hoặc x=7

1. Tìm số tự nhiên x biết:

1) \(3^x.3=243\)

\(3^x=243:3\)

\(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

_____

2) \(7.2^x=56\)

\(2^x=56:7\)

\(2^x=8\)

\(2^x=2^3\)

\(\Rightarrow x=3\)

_____

3) \(x^3=8\)

\(x^3=2^3\)

\(\Rightarrow x=3\)

_____

4) \(x^{20}=x\)

\(x^{20}-x=0\)

\(x\left(x^{19}-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x=1\)

5) \(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

_____

6) \(\left(2x+1\right)^3=9.81\)

\(\left(2x+1\right)^3=729=9^3\)

\(\rightarrow2x+1=9\)

\(2x=9-1\)

\(2x=8\)

\(x=8:2\)

\(\Rightarrow x=4\)

_____

7) \(x^6:x^3=125\)

\(x^3=125\)

\(x^3=5^3\)

\(\Rightarrow x=5\)

_____

8) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=7\\x=8\end{matrix}\right.\)

_____

9) \(3^{x+2}-5.3^x=36\)

\(3^x.\left(3^2-5\right)=36\)

\(3^x.\left(9-5\right)=36\)

\(3^x.4=36\)

\(3^x=36:4\)

\(3^x=9\)

\(3^x=3^2\)

\(\Rightarrow x=2\)

_____

10) \(7.4^{x-1}+4^{x+1}=23\)

\(\rightarrow7.4^{x-1}+4^{x-1}.4^2=23\)

\(4^{x-1}.\left(7+4^2\right)=23\)

\(4^{x-1}.\left(7+16\right)=23\)

\(4^{x-1}.23=23\)

\(4^{x-1}=23:23\)

\(4^{x-1}=1\)

\(4^{x-1}=4^1\)

\(\rightarrow x-1=0\)

\(x=0+1\)

\(\Rightarrow x=1\)

Chúc bạn học tốt

8: =>6x^2-9x+2x-3-6x^2-12x=16

=>-19x=19

=>x=-1