Tìm x,y
15/x=y/21=31/105
tìm x, y, z a) x10=y15=z−21x10=y15=z−21 và x+y+z =92
b) x5=y1=z−2x5=y1=z−2 và x+y-2z =160
c) 4x=3y=3z và x+y+z=1975
c: Ta có: 4x=3y=3z
nên \(\dfrac{x}{\dfrac{1}{4}}=\dfrac{y}{\dfrac{1}{3}}=\dfrac{z}{\dfrac{1}{3}}\)
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{x}{\dfrac{1}{4}}=\dfrac{y}{\dfrac{1}{3}}=\dfrac{z}{\dfrac{1}{3}}=\dfrac{x+y+z}{\dfrac{1}{4}+\dfrac{1}{3}+\dfrac{1}{3}}=\dfrac{1975}{\dfrac{11}{12}}=\dfrac{23700}{11}\)
Do đó: \(\left\{{}\begin{matrix}x=\dfrac{5925}{11}\\y=\dfrac{7900}{11}\\z=\dfrac{7900}{11}\end{matrix}\right.\)
Tìm x :
a) 49 x (X – 21) =441
b) 53 x 31 x X = 4929
c) 61 x ( 126 : X ) = 1281
d) 79 x ( X : 23) = 316
e) X : ( 12 + 13) = 7
g) 429 : (x + 31) = 11
h) 1615 : (X x 19) = 17
i) 420 : ( X : 39) = 105
a) 49 x ( X – 21 ) = 441 e) X : (12 + 13) = 7
X – 21 = 441:49 X : 25 = 7
X – 21 = 9 X = 7 x 25
X = 21 + 9 X = 175
X = 30
b) 53 x 31 x X = 4929 g) 429 : ( X + 31) = 11
31 x X = 4929 : 53 X + 31 = 429 : 11
31 x X = 93 X + 31 = 39
X = 93 : 31 ’ X = 39 – 31
X = 3 X = 8
c) 61 x (126 : X ) = 1281 h) 1 615 : (X x 19) = 17
126 : X = 1281 : 61 X x 19 = 1 615 : 17
126 : X = 21 X x 19 = 95
X = 126 : 21 X = 95 : 19
X = 6 X = 5
d) 79 x ( X : 23 ) = 316 i) 420 : ( X : 39 ) = 105
X : 23 = 316 : 79 X : 39 = 420 : 105
X : 23 = 4 X : 39 = 4
X = 4 x 23 X = 4 x 39
X = 92 X = 156
Bài 7. Tìm x ϵ N biết:
a) (x – 15 ) – 75 = 0
b) 575- (6x +70) =445
c) x –105 : 21 =15
d) (x - 105) :21 = 15
giải đầy đủ giúp mik với
Bài 7:
a)(x-15)-75=0
⇔x-15=75
⇔x=90
b)575-(6x+70)=445
⇔6x+70=130
⇔6x=60
⇔x=10
c)x-105:21=15
⇔x-5=15
⇔x=20
d)(x-105):21=15
⇔x-105=315
⇔x=420
tìm x thuộc N, biết :
a) x - 105 : 21 = 15
b) ( x - 105 ) : 21 = 15
c) 315 + ( 125 - x ) = 435
a) x - 105 : 21 = 15
x - 5 = 15
=> x = 20
b) ( x - 105 ) : 21 = 15
x - 105 = 315
=> x = 420
c) 315 + ( 125 - x ) = 435
125 - x = 120
=> x = 5
a)x - 105 : 21 = 15
x - 5 =15
x =20
b) (x - 105) :21=15
x -105 =315
x =420
c) 315+ (125 - x ) =435
125 - x =-120
x =5
tìm x biết:
a,315+(125-x)=435
b,x:41=32
c,(x-105):21=15
d,x-105:21=15
,
a) \(315+\left(125-x\right)=435\)
\(\Leftrightarrow125-x=435-315\)
\(\Leftrightarrow125-x=120\)
\(\Leftrightarrow x=125-120\)
\(\Leftrightarrow x=5\)
b) \(x:41=32\)
\(\Leftrightarrow x=32\cdot41\)
\(\Leftrightarrow x=1312\)
c) \(\left(x-105\right):21=15\)
\(\Leftrightarrow x-105=15\cdot21\)
\(\Leftrightarrow x-105=315\)
\(\Leftrightarrow x=315+105\)
\(\Leftrightarrow x=420\)
d) \(x-105:21=15\)
\(\Leftrightarrow x-5=15\)
\(\Leftrightarrow x=15+5\)
\(\Leftrightarrow x=20\)
a, 315 + ( 125 - x ) = 435
( 125 - x) = 435 - 315
( 125 - x ) = 320
x = 320 - 125
x = 195
bạn văn quang long tính sai rồi 435-315=120 chứ
Tìm GTLN của X;Y;Z biết x + 6y = 21 ; 2x + 3z = 31 và x;y;z > 0
bạn tham khảo TIM GTLN CUA TONG X+Y+Z BIET X+5Y = 21 ; 2X+3Z = 51 ; X,Y,Z >= 0? | Yahoo Hỏi & Đáp
Tìm X biết:
1) X - 105 : 21 = 15
2) ( X - 105 ) : 21 = 15
3) ( 32 + X ) : 17 = X
4) 1818 : ( 6X - 37 ) = 18
1)\(x-105:21=15\)
\(x-5=15\)
\(x=15+5\)
\(x=20\)
Vậy \(x=20.\)
2)\(\left(x-105\right):21=15\)
\(\left(x-105\right)=15.21\)
\(x-105=315\)
\(x=315+105\)
\(x=420\)
Vậy \(x=412.\)
4)\(1818:\left(6x-37\right)=18\)
\(6x-37=1818:18\)
\(6x-37=101\)
\(6x=101+37\)
\(6x=138\)
\(x=138:6\)
\(x=23\)
Vậy \(x=23.\)
mk quên,còn phần 3) nữa:
3)\(\left(32+x\right):17=x\)
\(32+x=x.17\)
\(\Leftrightarrow x=2\)
Vậy \(x=2.\)
tìm x
a; 35-15+x=70
b; 568-(2.x+14)=15
c; x-105:21=15
d; (x-105).21=15
a) 35-15+x=70
=> 20+x=70
=> x=50
b) 568-(2x+14)=15
=> 2x+14=553
=> 2x=539
=> x=269,5
c) x-105:21=15
=> x-5=15
=> x=20
d) (x-105)*21=15
=> x-105=5/7
=> x=5/7+105
=> x=740/7
a, 35 - 15 + x = 70 b, 568 - (2.x + 14 )= 15
x = 70 - 35 + 15 2.x + 14 = 568 - 15
x = 50 2.x + 14 =553 => 2.x =553-14=539 =>x=539 : 2 =269.5
c, x - 105 : 21 =15 d, (x - 105) . 21 = 15
x - 105 = 15 x 21 x - 105 = 15 : 21
x - 105 = 315 x - 105 = \(\frac{5}{7}\)
x = 315+105 x = \(\frac{5}{7}\)+ 105
x = 420 x = \(\frac{740}{7}\)
a/ 35-15+x=70 b/ 569-(2x+14)=15 c/ x-105:21=15 d/(x-105).21 =15
20+x =70 2x+14 =569-15 x-5 =15 x-105 =15:21
x =70-20 2x+14 =554 x =15+5 x-105 =5/7
x =50 2x =554-14 x =20 x=5/7+105
x=740/7
2x =540
x =540 : 2
x =270
x-105:21=15 tìm x
x - 105 : 21 = 15
=> x - 5 = 15
=> x = 15 + 5
=> x = 20
~Study well~
#KSJ
\(x-105:21=15\)
\(x-5=15\)
\(x=15+5\)
\(x=20\)