ta có\(\dfrac{2001}{2002}< 1\)và\(\dfrac{2005}{2003}>1\)

\(\Rightarrow\dfrac{2001}{2002}< \dfrac{2005}{2003}\)

Ta có: \(\dfrac{2001}{2002}< 1\)

mà \(1< \dfrac{2005}{2003}\)

nên \(\dfrac{2001}{2002}< \dfrac{2005}{2003}\)

Vì \(\frac{2000}{2001}< \frac{2003}{2002}\) do \(\frac{2000}{2001}< 0< \frac{2003}{2003}\) (tử lớn hơn mẫu) nên khi là số nguyên âm \(\frac{2000}{-2001}>\frac{-2003}{2002}\)

𝓣𝓪 𝓬𝓸́: \(1-\dfrac{2002}{2003}=\dfrac{1}{2003}\)

            \(1-\dfrac{2003}{2004}=\dfrac{1}{2004}\)  

𝓓𝓸 \(\dfrac{1}{2003}>\dfrac{1}{2004}\) 

𝓷𝓮̂𝓷 \(\dfrac{2002}{2003}>\dfrac{2003}{2004}\)

𝓥𝓪̣̂𝔂 \(\dfrac{2002}{2003}>\dfrac{2003}{2004}\)

Ta có :

\(\dfrac{2002}{2003}< \dfrac{2002+1}{2003+1}=\dfrac{2003}{2004}\)

Vậy \(\dfrac{2002}{2003}< \dfrac{2003}{2004}\)

Ta có

Ta có: \(\dfrac{2002}{2003}< \dfrac{14}{13}\) vì \(\dfrac{2002}{2003}< 1\), \(\dfrac{14}{13}>1\)

ta có

2002/2003<1<14/13

=>2002/2003<14/13

a)-17/23=-171717/232323

b)-265/317<-83/111

c)2002/2003<14/13

d)-27/463<1/3

Ta có

\(\frac{2002}{2003}< 1< \frac{14}{13}\)

\(\frac{\Rightarrow2002}{2003}< \frac{14}{13}\)

có\(\hept{\begin{cases}\frac{2002}{2003}< 1\\\frac{14}{13}>1\end{cases}\Leftrightarrow\frac{2002}{2003}< 1< \frac{14}{13}}\)

vậy \(\frac{2002}{2003}< \frac{14}{13}\)

                                              Bài giải

\(\frac{2002}{2003}< 1< \frac{14}{13}\)

\(\Rightarrow\text{ }\frac{2002}{2003}< \frac{14}{13}\)

a) 534 phần 215 < 533 phần 214

b)-325 phần364 > -326 phần 365

c) 2002 phần 2003 < 2003 phần 2004

d) -2002 phần 2003 > 2005 phần -2004

a) \(\frac{-2}{3}>\frac{4}{-5}\)
b) \(\frac{-18}{31}< \frac{-18.18.18}{31.31.31}\)
c) \(\frac{-13}{31}< \frac{29}{-88}\)

bạn nào làm cụ thể hơn thì mình k nhaa ! camon mng

a) \(\frac{2002}{2003}v\text{à}\frac{14}{13}\)

\(\frac{2002}{2003}1\)

\(\Rightarrow\frac{2002}{2003}