2/3-2/4+3/8x2/5:4/6=?
1/8x2/6:3/4+5/3=???????
=1/24:3/4+5/3 =1/18+5/3 =31/18 Ủng hộ nka!!!!!
1/8*2/6:3/4+5/3
=1/8*1/3:3/4+5/3
=1/24*4/3+5/3
=1/18+30/18
=31/18
Tìm x, biết:
a) 2(5x-8)-3(4x-5) = 4(3x-4) + 11;
b) 2 x ( 6 x - 2 x 2 ) + 3 x 2 ( x - 4 ) = 8;
c) 2 ( x 3 - 1 ) - 2 x 2 ( x + 2 x 4 ) + ( 4 x 5 + 4 ) x = 6;
d)(2x)2(4x-2)-(x3 -8x2) = 15.
a) x = 2 7 b) x = 2.
c) x = 2 d) x = 1.
Bài 1. Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
1. a) 5 – (x – 6) = 4(3 – 2x) b) 2x(x + 2)2 – 8x2 = 2(x – 2)(x2 + 2x + 4)
c) 7 – (2x + 4) = – (x + 4) d) (x – 2)3 + (3x – 1)(3x + 1) = (x + 1)3
e) (x + 1)(2x – 3) = (2x – 1)(x + 5) f) (x – 1)3 – x(x + 1)2 = 5x(2 – x) – 11(x + 2)
g) (x – 1) – (2x – 1) = 9 – x h) (x – 3)(x + 4) – 2(3x – 2) = (x – 4)2
i) x(x + 3)2 – 3x = (x + 2)3 + 1 j) (x + 1)(x2 – x + 1) – 2x = x(x + 1)(x – 1)
2. a) b)
c) d)
e) f)
g) h)
i) k)
m) n)
bạn đăng tách cho mn cùng giúp nhé
Bài 1 :
a, \(\Leftrightarrow11-x=12-8x\Leftrightarrow7x=1\Leftrightarrow x=\dfrac{1}{7}\)
b, \(\Leftrightarrow2x\left(x^2+4x+4\right)-8x^2=2\left(x^3-8\right)\)
\(\Leftrightarrow2x^3+8x^2+8x-8x^2=2x^3-16\Leftrightarrow x=-2\)
c, \(\Leftrightarrow3-2x=-x-4\Leftrightarrow x=7\)
d, \(\Leftrightarrow x^3-6x^2+12x-8+9x^2-1=x^3+3x^2+3x+1\)
\(\Leftrightarrow3x^2+12x-9=3x^2+3x+1\Leftrightarrow x=\dfrac{10}{9}\)
e, \(\Leftrightarrow2x^2-x-3=2x^2+9x-5\Leftrightarrow x=5\)
f, \(\Leftrightarrow x^3-3x^2+3x-1-x^3-2x^2-x=10x-5x^2-11x-22\)
\(\Leftrightarrow-5x^2+2x-1=-5x^2-x-22\Leftrightarrow3x=-21\Leftrightarrow x=-7\)
h) \(PT\Leftrightarrow x^2+4x-3x-12-6x+4=x^2-8x+16\)
\(\Leftrightarrow3x=24\)
\(\Leftrightarrow x=8\)
Vậy: \(S=\left\{8\right\}\)
j) \(PT\Leftrightarrow x^3-x^2+x+x^2-x+1-2x=x^3-x\)
\(\Leftrightarrow x=1\)
Vậy: \(S=\left\{1\right\}\)
Bài 1: \(\dfrac{1}{3}\) + \(\dfrac{2}{4}\) + \(\dfrac{3}{5}\) ...........................3(>,<,=)
A.>
B.<
C.=
Bài 2: \(\dfrac{8x7-8x3}{8x2}\) = ?
A.2
B.3
C.4
D.5
35\8x24\36
rút gọn ps
35/8*24/36 = 35/23*24/36 = 2/3
A) 9/5+2/5x4/6 B)3/8x2-6/7x1/3
\(a,\dfrac{9}{5}+\dfrac{2}{5}\times\dfrac{4}{6}=\dfrac{9}{5}+\dfrac{4}{15}=\dfrac{27}{15}+\dfrac{4}{15}=\dfrac{31}{15}\\ b,\dfrac{3}{8}\times2-\dfrac{6}{7}\times\dfrac{1}{3}=\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{21}{28}-\dfrac{8}{28}=\dfrac{13}{28}\)
A)=9/5 + 4/15
=27/15+4/15
=31/15
B)=3/4-2/14
=36/28-4/28
=32/28=?
1. x2+3x-8=0; 2). 8x2-2x-5=0 3). 2x2+7x+6=0 4). 3x2 -10x+8=0
5). 2x(8x-1)2(4x-1)=9
BT: Viết biểu thức sau về dạng bình phương hoặc dạng tích.
a, x4 - 8x2 + 16
b, (4x+5)2 - (5x+4)2
c, (2x-3)2 - 2(2x-3).(x+2) + (-x-2)2
a, \(x^4-8x^2+16=\left(x^2-4\right)^2\)
b, \(\left(4x+5\right)^2-\left(5x+4\right)^2=\left(4x+5-5x-4\right)\left(4x+5+5x+4\right)=\left(1-x\right)\left(9x+9\right)=9\left(1-x\right)\left(1+x\right)=9\left(1-x^2\right)\)
c, \(\left(2x-3\right)^2-2\left(2x-3\right)\left(x+2\right)+\left(-x-2\right)^2=\left(2x-3-x-2\right)^2=\left(x-5\right)^2\)
a) \(x^4-8x^2+16=\left(x^2-4\right)^2\)
b) \(\left(4x+5\right)^2-\left(5x+4\right)^2=\left(4x+5-5x-4\right)\left(4x+5+5x+4\right)=9\left(1-x\right)\left(x+1\right)\)c) \(\left(2x-3\right)^2-2.\left(2x-3\right)\left(x+2\right)+\left(-x-2\right)^2=\left(2x-3-x-2\right)^2=\left(x-5\right)^2\)
bài 1 Phân tích đa thức thành nhân tử ( bằng kĩ thuật bổ sung hằng đẳng thức )
1, 2x2 - 3x - 2
2,4x2 - 7x - 2
3, 6x2 + 7x - 3
bài 2 phân tích thành nhân tử ( bằng kĩ thuật tách hạng tử )
1, 3x2 + 7x - 6
2, 8x2 - 2x - 3
3, -8x2 + 5x + 3
4, -10x2 + 11x + 6
\(1,2x^2-3x-2\)
\(=2x^2-4x+x-2\)
\(=2x\left(x-2\right)+\left(x-2\right)\)
\(=\left(2x+1\right)\left(x-2\right)\)
\(2,4x^2-7x-2\)
\(=4x^2-8x+x-2\)
\(=4x\left(x-2\right)+x-2\)
\(\left(4x+1\right)\left(x-2\right)\)