A, 11/12

B, 12,6

a,

x- 7/12 = 1/3

x = 1/3 + 7/12

x = 11/12

b,

x + 31/10 = 14,5

x = 14,5 - 31/10

x = 57/5

\(a,\\ x=\dfrac{1}{3}+\dfrac{7}{12}=\dfrac{11}{12}\\ b,\\ x+\dfrac{31}{10}=\dfrac{157}{10}\\ x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{63}{5}\)

đề bài là làm gì vậy bạn?

Tính m x n nhé bạn

(5x-3)⁵-1=31

(5x-3)⁵=32

(5x-3)5=2⁵

5x-3=2

x=1

tinh nhanh sao lai co x vay ban oi , x hay la nhan vay

31-3.x=10
=> 3.x = 31-10
=> 3.x = 21
=> x = 21:3
=> x= 7

10-3=7

a) Ta có: \(\left(x-1\right)^{x+2}-\left(x-1\right)^{x+4}=0\)

\(\Leftrightarrow\left(x-1\right)^x\cdot\left(x-1\right)^2-\left(x-1\right)^x\cdot\left(x-1\right)^4=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\cdot\left[1-\left(x-1\right)^2\right]=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-1=1\\x-1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\\x=0\end{matrix}\right.\)

b) Ta có: \(\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot\dfrac{4}{10}\cdot\dfrac{5}{15}\cdot...\cdot\dfrac{30}{62}\cdot\dfrac{31}{64}=2x\)

\(\Leftrightarrow2x=\dfrac{1}{64}\)

hay \(x=\dfrac{1}{128}\)

a) x+2(3-x)-3(1-x)=9

<=> x+6-2x-3+3x=9

<=> 2x+3=9

<=> 2x=6

<=> x=3

b) (3x+5)-(x-10)+2x=31

<=> 3x+5-x+10+2x=31

<=> 4x+15=31

<=> 4x=16

<=> x=4

a) x+2(3-x)-3(1-x)=9

        x+6-2x-3+3x=9

               x-2x+3x=9-6+3

                       2x=6

                         x=6:2

                         x=3

Vậy x=3

b) (3x+5)-(x-10)+2x=31

     3x+5-x+10+2x=31

     3x-x+2x=31-5-10

              4x=16 

                x=16:4

                x=4

Vậy x=4

a, x + 2(3 - x) - 3( 1 - x) = 9

<=> x + 6 - 2x - 3 + 3x = 9

<=> x - 2x + 3x = 9 - 6 +3 

<=> 2x = 6

<=> x = 3

Vậy_

b, ( 3x + 5) - ( x - 10) + 2x = 31

<=> 3x + 5 - x + 10 + 2x = 31

<=> 3x - x + 2x = 31 - 5 - 10

<=> 4x =16

<=> x = 4

Vậy_

BT1 :thực hành phép tính

4/3+-11/31+3/10-20/31-2/5 = 7/30

7/12-1/-16+3/4 = 67/48

2/11.-5/4+-9/11.5/4+ 1 và 3/4 = -1/4 * và 3/4 là sao bạn *

-9/27-25/75 = -2/3