1. on - in

2. with - at

3. over - up

4. to

5. out

6. up with 

B

1 ; 2 ; 3 ; 4

2,004 ; 1,850 ; 1,805 ; 0,5880

2,004,1,850,1,805,0,5880

Đáp án: Khuyên chúng ta sống không chỉ biết nhận mà còn phải biết cho.

=864

864

tick chưa

\(8,64\cdot93+8,64:0,5+8,64:0,25+8,64\)

\(=8,64\cdot93+8,64:\dfrac{1}{2}+8,64:\dfrac{1}{4}+8,64\)

\(=8,64\cdot93+8,64\cdot2+8,64\cdot4+8,64\)

\(=8,64\cdot\left(93+2+4+1\right)=8,64\cdot10=864\)

Ta có: \(3x=4y\Rightarrow\dfrac{x}{4}=\dfrac{y}{3}\Rightarrow\dfrac{x}{20}=\dfrac{y}{15}\)

            \(2y=5z\Rightarrow\dfrac{y}{5}=\dfrac{z}{2}\Rightarrow\dfrac{y}{15}=\dfrac{z}{6}\)

Áp dụng t/c dtsbn:

\(\dfrac{x}{20}=\dfrac{y}{15}=\dfrac{z}{6}=\dfrac{x+z}{20+6}=\dfrac{52}{26}=2\)

\(\Rightarrow\left\{{}\begin{matrix}x=20.2=40\\y=15.2=30\\z=6.2=12\end{matrix}\right.\)

a: Xét ΔBIP vuông tại I và ΔBDA vuông tại D có

\(\widehat{IBP}\) chung

Do đó: ΔBIP đồng dạng với ΔBDA

=>\(\dfrac{BI}{BD}=\dfrac{BP}{BA}\)

=>\(BI\cdot BA=BD\cdot BP\)

b: ta có: \(\dfrac{BI}{BD}=\dfrac{BP}{BA}\)

=>\(\dfrac{BI}{BP}=\dfrac{BD}{BA}\)

=>\(\dfrac{BP}{BI}=\dfrac{BA}{BD}\)

Xét ΔBPA và ΔBID có

\(\dfrac{BP}{BI}=\dfrac{BA}{BD}\)

\(\widehat{PBA}\) chung

Do đó: ΔBPA đồng dạng với ΔBID

cooked

looked

calld

played

helped

opened

Cột 2 :

liked

lived

shared

used

- cooked

- looked

- called

- walked

- played

- helped

- opened

- liked

- lived

- shared

- used

cooked

looked

called

walked

played

helped

opened

liked

lived

shared

used tick mik nha

2 went

3 had

4 got, weren't

5 liked

6 took

7 did

8 was, played