a) \(9\cdot3^3\cdot\frac{1}{81}\cdot3^2\)

\(=\frac{3^2\cdot3^3\cdot3^2}{3^4}\)

\(=3^3=27\)

b) \(4\cdot2^5:\left(2^3\cdot\frac{1}{16}\right)\)

\(=\frac{2^2\cdot2^2\cdot2^4}{2^3}\)

\(=2^5=32\)

c) \(3^2\cdot2^5\cdot\left(\frac{2}{3}\right)^2\)

\(=\frac{3^2\cdot2^5\cdot2^4}{3^2}\)

\(=2^9=512\)

d) \(\left(\frac{1}{3}\right)^2\cdot\frac{1}{3}\cdot9^2\)

\(=\frac{1^2\cdot1\cdot3^4}{3^2}\)

\(=3^2=9\)

a) \(9\cdot3^3\cdot\frac{1}{81}\cdot3^2=3^2\cdot3^3\cdot\left(\frac{1}{3}\right)^43^2=3^7\cdot\frac{1}{3^4}=3^3\)

b) \(4\cdot2^5:\left(2^3\cdot\frac{1}{16}\right)=2^2\cdot2^5:\left(2^3\cdot\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^8\)

c) \(3^2\cdot2^5\cdot\left(\frac{2}{3}\right)^2=3^2\cdot2^5\cdot\frac{2^2}{3^2}=2^7\)

d) \(\left(\frac{1}{3}\right)^2\cdot\frac{1}{3}\cdot9^2=\frac{1}{3^2}\cdot\frac{1}{3}\cdot3^4=\frac{1}{3^3}\cdot3^4=3\)

a)9.3³.\(\frac{1}{81}\).3²

   =3².3³.3⁴.\(\frac{1}{3^4}\).3²

    ⁼3¹¹.\(\frac{1}{3^4}\)

    =3⁷

b)4.2⁵:(\(2^3.\frac{1}{16}\))

  =2².2⁵:(\(2^3.\frac{1}{2^4}\))

  =2⁷:\(\frac{2^3}{2^4}\)

  =2⁷.\(\frac{2^4}{2^3}\)

   =\(\frac{2^{11}}{2^3}\)

   =2⁸

c)3².2⁵.\(\left(\frac{2}{3}\right)^2\)

   =3².2⁵.\(\frac{2^2}{3^2}\)

   =\(\frac{3^2.2^5.2^2}{3^2}\)

   =2⁷

d)\(\left(\frac{1}{3}\right)^2.\frac{1}{3}.9^2\)

    =\(\frac{1^2}{3^2}.\frac{1}{3}.\left(3^2\right)^2\)

    =\(\frac{1^2}{3^2}.\frac{1}{3}.3^4\)

    =\(\frac{1^2}{3^2}.\frac{3^4}{3}\)

    =\(\frac{1^2}{3^2}.3^3\)

   =3

d,\(=\frac{1}{3^2}\cdot\frac{1}{3}\cdot\left(3^2\right)^2=\frac{3^4}{3^3}=3\)

b,\(=2^2\cdot2^5:\left(2^3\cdot\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^7\cdot2=2^8\)

ủa , còn câu trả lời của e ạ !!! chắc oline math duyệt !!! 

a: \(=3^2\cdot3^3\cdot3^{-4}\cdot3^2=3^{2+3-4+2}=3^3\)

b: \(=2^2\cdot2^5:\left(2^3\cdot\dfrac{1}{2^4}\right)=2^7:\dfrac{1}{2}=2^8\)

c: \(=9\cdot32\cdot\dfrac{4}{9}=128=2^7\)

d: \(=\dfrac{1}{27}\cdot3^4=3^1\)

\(a,3^{16}:3=3^{16-1}=3^{15}\)

\(b,3^6.3^4.3^2.3=3^{6+4+2+1}=3^{13}\)

\(c,\left(-\frac{1}{4}\right).\left(6\frac{2}{11}\right)+\left(3\frac{9}{11}\right).\left(-\frac{1}{4}\right)=\left(-\frac{1}{4}\right).\frac{68}{11}+\frac{42}{11}.\left(-\frac{1}{4}\right)\)

\(=\left(-\frac{1}{4}\right)\left(\frac{68}{11}+\frac{42}{11}\right)\)

\(=\left(-\frac{1}{4}\right).10\)

\(=-\frac{10}{4}=-\frac{5}{2}\)

\(d,\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5=\left(-\frac{1}{2}\right)\left(\left(\frac{1}{2}\right)^2-\frac{1}{5}\right)\)

\(=-\frac{1}{2}.\left(\frac{1}{4}-\frac{1}{5}\right)\)

\(=-\frac{1}{2}.\frac{1}{20}\)

\(=-\frac{1}{40}\)

\(g,1\frac{1}{25}+\frac{2}{21}-\frac{1}{25}+\frac{19}{21}=\frac{26}{25}+\frac{2}{21}-\frac{1}{25}+\frac{19}{21}\)

\(=\left(\frac{26}{25}-\frac{1}{25}\right)+\left(\frac{2}{21}+\frac{19}{21}\right)\)

\(=1+1\)

\(=2\)

\(a,9.3^3.\frac{1}{81}.3^2=3^2.3^3.3^{\left(-4\right)}.3^2=3^{2+3-4+2}=3^3.\)

\(b,4.2^5:\left(2^3.\frac{1}{16}\right)=2^2.2^5:\left(2^3.2^{-4}\right)=2^{2+5}:2^{3-4}=2^7:2^{-1}=2^{7-\left(-1\right)}=2^8.\)

\(c,3^2.2^5.\left(\frac{2}{3}\right)^2=3^2.2^5.\frac{2^2}{3^2}=\left(\frac{3^2}{3^2}\right).\left(2^5.2^2\right)=1.2^{5+2}=2^7\)

\(d,\left(\frac{1}{3}\right)^2.\frac{1}{3}.9^2=\left(\frac{1}{3}\right)^2.\frac{1}{3}.\left(3^2\right)^2=\left(\frac{1}{3}\right)^{2+1}.3^4=\left(\frac{1}{3}\right)^3.\left(\frac{1}{3}\right)^{-4}=\left(\frac{1}{3}\right)^{3-4}=\left(\frac{1}{3}\right)^{-1}=3^1\)