a) x²+10x+26+y²+2y

=x²+10x+25+y²+2y+1

=(x+5)²+(y+1)²

b) z²-6z+5-t²-4t

=z²-6z+9-t²-4t-4

=(z-3)²-(t²+4t+4)

=(z-3)²-(t+2)²

c)x²-2xy+2y²+2y+1

=x²-2xy+y²+y²+2y+1

=(x-y)²+(y+1)²

d) 4x²-12x-y²+2y+8

=4x²-12x+9-y²+2y-1

=(2x-3)²-(y²-2y+1)

=(2x-3)²-(y-1)²

bạn ơi , bạn lấy bài này ở đâu vậy bạn

2x y 2  +  x 2 y 4 + 1 = x y 2 2 + 2.x y 2 .1 + 1 2  = x y 2 + 1 2

1)a)x²+10x+26+y²+2y

=(x²+10x+25)+(y²+2y+1)

=(x+5)²+(y+1)²

b)x²-2xy+2y²+2y+1

=(x²-2xy+y²)+(y²+2y+1)

=(x-y)²+(y+1)²

c)z²-6z+13+t²+4t

=(z²-6z+9)+(t²+4t+4)

=(z-3)²+(t+2)²

d)4x²+2z²-4xz-2z+1

=(4x²-4xz+z²)+(z²-2z+1)

=(2x-z)²+(z-1)²

2)a)(x-3)²-4=0

<=>(x-3-2)(x-3+2)=0

<=>(x-5)(x-1)=0

<=>x-5=0 hoặc x-1=0

<=>x=5 hoặc x=1

b)x²-2x=24

<=>x²-2x-24=0

<=>(x²-6x)+(4x-24)=0

<=>x(x-6)+4(x-6)=0

<=>(x-6)(x+4)=0

<=>x-6=0 hoặc x+4=0

<=>x=6 hoặc x=-4

a) x^2 + 10x + 26 + y^2 + 2y

=x²+10x+25+y²+2y+1

=x²+2.x.5+5²+y²+2.y.1+1²

=(x+5)²+(y+1)²

b)x^2 - 2xy + 2y^2 + 2y +1

=x²-2xy+y²+y²+2y+1

=(x-y)²+(y+1)²

c)z^2 - 6z + 13 + t^2 + 4t

=z²-6z+9+t²+4z+4

=z²-2.z.3+3²+t²+2.t.2+2²

=(z-3)²+(t+2)²

d)4x^2 + 2z^2 - 4xz - 2z + 1

=4x²-4xz+z²+z²-2z+1

=(2x)²-2.2x.z+z²+z²-2z.1+1²

=(2x-z)²+(z-1)²

a) x^2 + 10x + 26 + y^2 + 2y

=x²+10x+25+y²+2y+1

=x²+2.x.5+5²+y²+2.y.1+1²

=(x+5)²+(y+1)²

b)x^2 - 2xy + 2y^2 + 2y +1

=x²-2xy+y²+y²+2y+1

=(x-y)²+(y+1)²

c)z^2 - 6z + 13 + t^2 + 4t

=z²-6z+9+t²+4z+4

=z²-2.z.3+3²+t²+2.t.2+2²

=(z-3)²+(t+2)²

d)4x^2 + 2z^2 - 4xz - 2z + 1

=4x²-4xz+z²+z²-2z+1

=(2x)²-2.2x.z+z²+z²-2z.1+1²

=(2x-z)²+(z-1)²

a) (x-3)^2 - 4 =0

<=>(x-3)²-2²=0

<=>(x-3-2)(x-3+2)=0

<=>(x-5)(x-1)=0

<=>x-5=0 hoặc x-1=0

<=>x=5 hoặc x=1

b) x^2 - 2x = 24

<=>x²-2x-24=0

<=>x²-2x+1-25=0

<=>(x-1)²-25=0

<=>(x-1)²-5²=0

<=>(x-1-5)(x-1+5)=0

<=>(x-6)(x+4)=0

<=>x-6=0 hoặc x+4=0

<=>x=6 hoặc x=-4

x² + 10x + 26 + y² + 2y
= x² + 10 + 25 + 1 + y² + 2y
= (x² + 10x + 25) + (y² + 2y + 1)
= (x + 5)² + (y + 1)²

x² - 2xy + 2y² + 2y + 1
= x² - 2xy + y² + y² + 2y + 1
= (x² - 2xy + y²) + (y² + 2y + 1)
= (x - y)² + (y + 1)²

4x² + 2z² - 4xz - 2z + 1
= 4x² + z² + z² - 4xz - 2z + 1
= (4x² - 4xz + z²) + (z² - 2z + 1)
= (2x + z)² + (z - 1)²

1) x² + 10x + 26 + y² + 2y 

= (x² + 10x + 25) + (y² + 2y + 1)

= (x² + 5x + 5x + 25) + (y² + y + y + 1)

= x(x + 5) + 5(x + 5) + y(y +  1) + (y + 1)

= (x + 5)² + (y + 1)²

2) z² - 6z + 13 + t² + 4t 

= (z² - 6z + 9) + (t² + 4t + 4) 

= (z² - 3z - 3z + 9) + (t² + 2t + 2t + 4)

= z(z - 3) - 3(z - 3) + t(t + 2) + 2(t + 2)

= (z - 3)² + (t + 2)²

3) x² - 2xy + 2y² + 2y + 1

(x² - 2xy + y²) + (y² + 2y + 1)

= (x - xy - xy + y²) + (y² + y + y +1)

= x(x - y) - y(x - y) + y(y + 1) + (y + 1)

= (x - y)² + (y + 1)²

a) Sửa đề: \(x^2+3x+1\rightarrow x^2+2x+1\)

\(x^2+2x+1=\left(x+1\right)^2\)

b) \(x^2+y^2+2xy=\left(x+y\right)^2\)

c) \(9x^2+12x+4=\left(3x+2\right)^2\)

d) \(-4x^2-9-12x=-\left(4x^2+12x+9\right)=-\left(2x+3\right)^2\)

này mình có vài câu không làm được, xin lỗi bạn nha

\(b,16x^2-8x+1=\left(4x-1\right)^2\\ c,4x^2+12xy+9y^2=\left(2x+3y\right)^2\\ e,=x^2+2x+1+y^2+2y+1+2\left(x+1\right)\left(y+1\right)\\ =\left(x+1\right)^2+2\left(x+1\right)\left(y+1\right)+\left(y+1\right)^2\\ =\left[\left(x+1\right)+\left(y+1\right)\right]^2=\left(x+y+2\right)^2\\ g,=x^2-2x\left(y+2\right)+\left(x+2\right)^2=\left[x-\left(y+2\right)\right]^2=\left(x-y-2\right)^2\\ h,=\left[x+\left(y+1\right)\right]^2=\left(x+y+1\right)^2\)

\(a.\)

\(z^2-6z+5-t^2-4t\)

\(=z^2-6z+9-\left(t^2+4t+4\right)\)

\(=\left(z-3\right)^2-\left(t+2\right)^2\)

\(b.\)

\(4x^2-12x-y^2+2y+1\)

Câu này đề sai sao ấy em !

b, mik nghĩ đề sửa thành: \(4x^2-12x-y^2+2y+8\)

\(=4x^2-12x+9-y^2+2y-1\)

\(=\left(2x\right)^2-2.2.3.x+3^2-\left(y^2-2y+1\right)\)

\(=\left(2x-3\right)^2-\left(y-1\right)^2\)