Cho a/b =c/d. CMR :
a) a+c/b+d = a-c/b-d.
b) a-b/b = c-d/d.
Ai biet thi chi giup minh voi nhe. Minh dang can gap lam.
Cho a,b,c,d > 0. CMR:
1 < (a+b)/(a+b+c) + (b+c)/(b+c+d) + (c+d)/(c+d+a) + ( d+a)/((d+a+b) < 3
Minh da lam dc nua y roi ( y 1<...) con nua y con lai ( ...< 3). Cac ban giup minh lam not nua y cuoi nhe! Minh cam on!
P/s: Minh sap phai nop bai roi, mong cac ban giup minh som nhe, khong minh se bi phat mat! Cam on rat nhiu! That ra thi cung co mot cau hoi giong nhu the nay, nhung ma nua y con lai ma minh chua biet lam lai khong giong nen cac ban giup minh chi tiet mot chut nhe!
Ta có \(\frac{x}{y}< \frac{x+m}{y+m}\)khi 0<x<y,m>0
Áp dụng ta được
\(\frac{a+b}{a+b+c}< \frac{a+b+d}{a+b+c+d}\)
\(\frac{b+c}{b+c+d}< \frac{a+b+c}{a+b+c+d}\)
....................................................
Khi đó
\(VT< \frac{a+b+d+a+b+c+c+d+b+d+a+c}{a+b+c+d}=3\)
Vậy VT<3
Cho a+b=c+d va a^2+b^2=c^2+d^2.Chung minh rang:a^2022+b^2022=c^2022+d^2022
Moi nguoi giup minh voi,minh dang can gapCho A = 1/1.2 + 1/3.4 + 1/5.6 +.......+ 1/49.50.
B = 1 + 1/2 + 1/3 + 1/4 +........+ 1/49 + 1/50.
C = 1/2 + 1/4 + 1/6 +.........+ 1/48 + 1/50.
CMR A = B - 2C.
Minh dang can gap. Ai biet thi chi giup minh nhe ! Cam on moi nguoi nhieu lam.
A = 1/1.2 + 1/3.4 + 1/5.6 + ... + 1/49.50
A =1 - 1/2 + 1/3 - 1/4 + 1/5 - 1/6 + ... + 1/49 - 1/50
A = (1 + 1/3 + 1/5 + ... + 1/49) - (1/2 + 1/4 + 1/6 + ... + 1/50)
A = (1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + ... + 1/49 + 1/50) - 2.(1/2 + 1/4 + 1/6 + ... +1/50)
A = B - 2C
=> đpcm
Ủng hộ mk nha ♡_♡☆_☆
cho ti le thuc a/b = c/d ,chung to rang a,3a + 2b / a = 3c + 2d / c ; b, 2a - 3b/ b = 2c - 3d / b ; c, a/ a-2b = c/c-2d giup minh voi dang can gap
Đặt a/b=c/d=k
=>a=bk; c=dk
a: \(\dfrac{3a+2b}{a}=\dfrac{3bk+2b}{bk}=\dfrac{3k+2}{k}\)
\(\dfrac{3c+2d}{c}=\dfrac{3dk+2d}{dk}=\dfrac{3k+2}{k}\)
Do đó: \(\dfrac{3a+2b}{a}=\dfrac{3c+2d}{c}\)
b: \(\dfrac{2a-3b}{b}=\dfrac{2bk-3b}{b}=2k-3\)
\(\dfrac{2c-3d}{d}=\dfrac{2dk-3d}{d}=2k-3\)
Do đó: \(\dfrac{2a-3b}{b}=\dfrac{2c-3d}{d}\)
c: \(\dfrac{a}{a-2b}=\dfrac{bk}{bk-2b}=\dfrac{k}{k-2}\)
\(\dfrac{c}{c-2d}=\dfrac{dk}{dk-2d}=\dfrac{k}{k-2}\)
Do đó: \(\dfrac{a}{a-2b}=\dfrac{c}{c-2d}\)
Cho a, b, c,d la cac so thuc . Chung minh bat dang thuc sau:
a2 + b2 +c2 +d2 +e2 >= ab +ac + ad +ae
Lam giup minh nhe cac ban minh can gap lam
\(a^2+b^2+c^2+d^2+e^2\ge ab+ac+ad+ae\left(1\right)\)
\(\Leftrightarrow a^2+b^2+c^2+d^2+e^2-a\left(b-c-d-e\right)\ge0\)
\(\Leftrightarrow\left(b^2-ab+\frac{1}{4}a^2\right)+\left(c^2-ac+\frac{1}{4}a^2\right)+\left(d^2-ad+\frac{1}{4}a^2\right)+\left(e^2-ae+\frac{1}{4}a^2\right)\ge0\)
\(\Leftrightarrow\left(b+\frac{1}{2}a\right)^2+\left(c+\frac{1}{2}a\right)^2+\left(d+\frac{1}{2}a\right)^2+\left(e+\frac{1}{2}a\right)^2\ge0\left(2\right)\)
( 2 ) đúng => ( 1 ) đúng
giai thich ngan gon mot so cau tuc ngu sau a,muon biet phai hoi muon gioi phai hoc b, ko co cay ko co thoc hoc khong biet chu c, tot go hon tot nuoc son d gan muc thi den gan den thi sang e con dang dong vua trong vua chay con dang nam vua lam vua choi f an khong nen doi noi khong nen loi
giup minh nhe minh dang can gapcho \(\dfrac{a}{b}=\dfrac{c}{d}\left(a,b,c,d\ne0\right)\) chung minh rang
a ,\(\dfrac{a+b}{a-b}=\dfrac{c+d}{c-d}\)
b ,\(\dfrac{2a+5b}{3a-4d}=\dfrac{2c+5d}{3c-4d}\)
giup minh nhe minh dang can gap
a. Ta có : ( a + b )( c - d ) = ac-ad+bc-bd (1)
( a - b )( c + d ) = ac+ad-bc+bd (2)
Từ giả thuyết : \(\dfrac{a}{b}=\dfrac{c}{d}\Rightarrow ad=bc\) (3)
Từ (1) , ( 2) và ( 3) \(\Rightarrow\)( a + b )( c - d) = ( a - b)( c + d )
\(\Rightarrow\dfrac{a+b}{a-b}=\dfrac{c+d}{c-d}\left(đpcm\right)\)
Bo dau ngoac roi rut gon bieu thuc :
a) - ( -a + c - d ) - ( c- a + d )
b) - ( a + b - c + d ) + ( a - b - c - d )
c) a( b- c -d ) - a( b + c - d )
Giup minh nhe minh dang can gap
a)= a-c+d-c+a-d
=2a-2c=2(a-c)
b)=-a-b+c-d+a-b-c-d
=-2b-2d
=2.(-b)-2d=2(-b-d)
c)=ab-ac-ad-ab-ac+ad
=-2.ac
Gấp đến mức độ nào vậy . Bài này đơn giản mà
bai 1 cho a,b,c>0
CMR: \(\frac{a}{1+b-a}+\frac{b}{1+c-b}+\frac{c}{1+a-c}>=1\)
cac ban oi giup minh. minh dang can gap lam. . lam on giup minh di. hu hu