8/3

= 8/3

\(x:\dfrac{1}{2}=\dfrac{2}{3}\times\dfrac{3}{4}\\ x:\dfrac{1}{2}=\dfrac{6}{12}\\ x=\dfrac{1}{2}\times\dfrac{1}{2}\\ x=\dfrac{1}{4}\)

Vậy `x=1/4`

a, \(\dfrac{20}{15}=\dfrac{4}{3}\)

b, \(\dfrac{6}{15}=\dfrac{2}{5}\)

c, \(\dfrac{42}{30}=\dfrac{7}{5}\)

d, \(\dfrac{40}{35}=\dfrac{8}{7}\)

e, \(\dfrac{42}{42}=1\)

g, \(\dfrac{54}{10}=\dfrac{27}{5}\)

h, \(\dfrac{12}{15}\)

k đúng để nhận câu trả lời
 

Ta có

( 2 x 4   –   3 x 3   +   x 2 )   :   - 1 2 x 2   +   4 ( x   –   1 ) 2   =   0 ⇔   2 x 4 : ( - 1 2 x 2 ) - 3 x 3 : ( - 1 2 x 2 ) + x 2 : ( - 1 2 x 2 ) + 4 ( x 2 - 2 x + 1 ) = 0 ⇔   - 4 x 2   +   6 x   –   2   +   4 x 2   –   8 x   +   4   =   0

ó -2x + 2 = 0

ó x  = 1

Đáp án cần chọn là: C

Câu c nha bạn

Gọi A = x2 + 2xy – 3x3 + 2y3 + 3x3 – y3

Trước hết ta thu gọn đa thức :

A = x2 + 2xy – 3x3 + 2y3 + 3x3 – y3

= (– 3x3+ 3x3) + x2 + 2xy + (2y3– y3)

= 0 + x2 + 2xy + y3.

= x2 + 2xy + y3.

Thay x = 5 ; y = 4 vào A ta được :

A = 52+ 2.5.4 + 43 = 25 + 40 + 64 = 129.

Vậy giá trị biểu thức x2 + 2xy – 3x3 + 2y3 + 3x3 – y3 tại x = 5 ; y = 4 bằng 129.

1: Sửa đề: 3x-5

\(=\dfrac{-x^2\left(3x-5\right)-3\left(3x-5\right)}{3x-5}=-x^2-3\)

2: \(=\dfrac{5x^4-5x^3+14x^3-14x^2+12x^2-12x+8x-8}{x-1}\)

=5x^2+14x^2+12x+8

3: \(=\dfrac{5x^3+10x^2+4x^2+8x+4x+8}{x+2}=5x^2+4x+4\)

4: \(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}=x^2+1-2x\)

5: \(=\dfrac{x^2\left(5-3x\right)+3\left(5-3x\right)}{5-3x}=x^2+3\)

a: =9/11(7/4+5/4)=9/11x3=27/11

b: \(=\dfrac{28}{5}\cdot\dfrac{5}{8}\cdot\dfrac{5}{4}=\dfrac{28}{8}\cdot\dfrac{5}{4}=\dfrac{140}{32}=\dfrac{35}{8}\)

c: \(=\dfrac{2}{6}+\dfrac{4}{5}\cdot\dfrac{6}{5}-\dfrac{2}{5}=\dfrac{67}{75}\)

a,=(7/4+5/4):11/9

=3:11/9

=27/11

b,=28/5.5/4.5/8

=7.5/8

=35/8

c,=1/3+24/25-2/5

=97/75-2/5

=67/75

7/4:11/9+5/4:11/9

=7/4×9/11+5/4×9/11

=9/11×(7/4+5/4)

=9/11×12/4

=9/11×3

=27/11

b)

28/5:4/5×5/8

=28/5×5/4×5/8

=28/4×5/8

=7×5/8

=35/8

c)

2/3×3/6+4/5:5/6−2/5

=2/6+4/5×6/5−2/5

=1/3+24/25−2/5

=(24/25−2/5)+1/3

=14/25+1/3

=67/75