* \(20+65.4=\left(x+75\right):5+30\)

\(\Leftrightarrow20+260-30=\frac{x}{5}+\frac{75}{5}\)

\(\Leftrightarrow20+260-30-\frac{75}{5}=\frac{x}{5}\)

\(\Leftrightarrow235=\frac{x}{5}\Rightarrow x=235.5=1175\)

* \(2248:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow2248:\left(119-x+6\right)=24\)

\(\Leftrightarrow2248:\left(125-x\right)=24\)

A mình lỡ tay, để mình tính tiếp nhá!

\(\Leftrightarrow125-x=2248:24\Leftrightarrow125-x=\frac{281}{3}\Rightarrow-x=\frac{94}{3}\Rightarrow x=-\frac{94}{3}\)(bài này mình thấy sai sai sao á, nếu mình làm sai thì thông cảm cho mình nhé!

* \(\left(x+70\right):14-40=\left(32.15\right):2\)

\(\Leftrightarrow\left(x+70\right):14=480:2+40\)

\(\Leftrightarrow\frac{x}{14}+5=280\Leftrightarrow\frac{x}{14}=275\Rightarrow x=3850\)

* \(x-4867=\left(175.2050.70\right):25+23\)

\(\Leftrightarrow x-4867-23=\left(175:25\right).\left(2050:25\right).\left(70:25\right)\)

\(\Leftrightarrow x-4890=7.82.\frac{14}{5}\)

\(\Leftrightarrow x-4890=\frac{8036}{5}\Rightarrow x=\frac{8036}{5}+4890=\frac{32486}{5}\)(bài này mình thấy hình như cũng có cái gì đó sai sai luôn hihi!)

=24 nha

x - 4867 = (175 . 2 - 5 . 70): 25 .23

x - 4867 = ( 5².7.2 - 5².7.2) : 25.23

x - 4867 = 0 : 25 . 23 = 0

x = 0 + 4867

x=4867.

x - 4867 = (175 . 2 - 5 . 70) : 25 .23

x - 4867 = (5².7.2 - 5².7.2) : 25.23

x - 4867 = 0 : 25 . 23 = 0

x = 0 + 4867

x = 4867

\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)

a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)

b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)

c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)

d. \(8782-291\cdot13=8782-3783=4999\)

e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)

f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\

a) \(5+3^{x+1}=86\)

\(=>3^{x+1}=86-5\)

\(=>3^{x+1}=81=3^4\)

\(=>x+1=4\) ( cùng cơ số )

\(=>x=4-1\)

\(=>x=3\)

b) \(15:\left(x+2\right)=\left(3^3+3\right):10\)

\(=>15:\left(x+2\right)=\left(27+3\right):10\)

\(=>15:\left(x+2\right)=30:10=3\)

\(=>x+2=15:3\)

\(=>x+2=5\)

\(=>x=5-2\)

\(=>x=3\)

c) \(\left(9x+2\right).4=80\)

\(=>9x+2=80:4\)

\(=>9x+2=20\)

\(=>9x=20-2\)

\(=>9x=18\)

\(=>x=18:9\)

\(=>x=2\)

d) \(\left(245-x\right)+7^2=14\)

\(=>\left(245-x\right)+14=14\)

\(=>245-x=14-14\)

\(=>245-x=0\)

\(=>x=245-0\)

\(=>x=245\)

?

a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)

=>\(\left[2\left(10-x\right)+51\right]:3=5\)

=>\(\left[2\left(10-x\right)+51\right]=15\)

=>\(2\left(10-x\right)=15-51=-36\)

=>10-x=-36/2=-18

=>\(x=10-\left(-18\right)=10+18=28\)

b: \(\left(x-12\right)-15=20-\left(17+x\right)\)

=>\(x-12-15=20-17-x\)

=>\(x-27=3-x\)

=>\(2x=30\)

=>\(x=\dfrac{30}{2}=15\)

c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

=>\(720-\left[41-2x+5\right]=8\cdot5=40\)

=>\(\left[41-2x+5\right]=720-40=680\)

=>-2x+46=680

=>-2x=680-46=634

=>\(x=\dfrac{634}{-2}=-317\)

131 . x - 942 = 2^7 . 2^3 

131 . x - 942 = 2^10

131 . x - 942 = 1024

131 . x = 1024 + 942 

131 . x = 1966

x = 1966 : 131 

x \(\approx15\)

b ) [ ( x + 32 ) - 17 ] . 2 = 42 

     [ ( x + 32 ) - 17 ] = 42 : 2

     ( x + 32 ) - 17  = 21

     x + 32 = 21 + 17

     x + 32 = 38

     x = 38 - 32

    x = 6

A. 131.x-942=2^7.2^3

    131.x-942=1024

    131.x       =1966

       x           =1966/131

B. [(x+32)-17].2=42

     (x+32-17) .2 =42

     (x+15).2       =42

      x+15           = 21

     x                 =6

- Tính giá trị ở mỗi vế.

- So sánh rồi điền dấu thích hợp vào chỗ trống.

a) 32 + 7 < 40     b) 32 + 14 = 14 + 32

45 + 4 < 54 + 5     69 - 9 < 96 - 6

55 - 5 > 40 + 5     57 - 1 < 57 + 1

\(1500:\left[\left(30x+40\right):x\right]=30\)

\(\left[\left(30x+40\right):x\right]=1500:30\)

\(\left[\left(30x+40\right):x\right]=50\)

\(30x:x+40:x=50\)

\(30+40:x=50\Leftrightarrow40:x=50-30\)

\(40:x=20\Leftrightarrow x=40:20\Leftrightarrow x=2\)

1500 : [(30.x+40):x] = 30

\(\left(30.x+40\right):x=50\)

=> 30.x + 40 = 50.x

=> 30.x - 50.x = -40

-20x = -40

x = 2

cảm ơn mọi người

Có ai biết không giúp tôi với nhé 

a) 0,5 + ( x - 15/2 ) : 1/2 = 9/2

<=>      (x - 15/2 ): 1/2   = 9/2 - 0,5

<=>      (x - 15/2)  : 1/2   = 4 

<=>        (x - 15/2)          = 4 . 1/2 

<=>        x - 15/2            = 2

<=>        x                     = 2 + 15/2 

<=>        x                     = 19/2  

b) 2012x - 2010x  = 2014 

( 2012 - 2010 ) .x  = 2014 

  2x                     = 2014 

   x                      = 2014 :2  

   x                      = 1007  

cảm ơn