-111/5  x  3= -333/15

do -15 lớn hơn -17 => -111/5 >-333/17

-337/339= -115/339 - 222/339

-115/339 > -155/133   => -337/339 > -155/133

a, ta có :

 \(\hept{\begin{cases}\frac{6}{7}< 1\\\frac{11}{10}>1\end{cases}}\Rightarrow\frac{6}{7}< \frac{11}{10}\)

b, ta có :

\(\hept{\begin{cases}\frac{-5}{7}< 0\\\frac{2}{7}>0\end{cases}}\Rightarrow\frac{-5}{7}>\frac{2}{7}\)

c, ta có :

\(\hept{\begin{cases}\frac{419}{-723}< 0\\\frac{-697}{-313}>0\end{cases}}\Rightarrow\frac{419}{-723}< \frac{-679}{-313}\)

a]6/7 va 11/10 

60/70 và 77/70 vay 11/10 lớn hơn 6/7 

a) \(\frac{6}{7}\) và \(\frac{11}{10}\)

Vì \(\frac{6}{7}< 1;1< \frac{11}{10}\)

\(\Rightarrow\frac{6}{7}< \frac{11}{10}\)

Vậy \(\frac{6}{7}< \frac{11}{10}\)

\(1)\)

\(a)(-50).37=-1850\)

\(b)(-20).(-14).25=280.25=7000\)

\(c)40.(-30).12=-1200.12=-14400\)

\(2)\)

\(a)\)

\(-40.[(-15)+30)]\)

\(=-40.15\)

\(=-600\)

\(b)\)

\(-5 . [(-27) - (-7)]\)

\(=-5 . [(-27)+7]\)

\(=-5 . (-20)\)

\(=100\)

\(c)\)

\(-10 . [(-28) + (-22) - 10]\)

\(=-10 . [-50 - 10]\)

\(=-10.(-60)\)

\(=600\)

a) Ta có: \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

Mà \(\frac{1}{32}=\left(\frac{1}{2}\right)^5\)

\(\Rightarrow\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\Rightarrow m=5\)

b)Ta có:  \(\frac{343}{125}=\left(\frac{7}{5}\right)^3\)

Mà \(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\Rightarrow n=3\)

\(a)\) \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\frac{1^5}{2^5}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\)

\(\Leftrightarrow\)\(m=5\)

Vậy \(m=5\)

\(b)\) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\frac{7^3}{5^3}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(n=3\)

Vậy \(n=3\)

Chúc bạn học tốt ~ 

a, \(\frac{1}{2^m}=\frac{1}{32}\)

\(\Rightarrow\frac{1}{2^m}=\frac{1}{2^5}\)

\(\Rightarrow m=5\)

\(b,\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Rightarrow\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Rightarrow n=3\)

1.Giải:

Gọi 4 phần chia là \(a,b,c,d\)

Theo đề bài ta có:

\(\frac{a}{2}=\frac{b}{3};\frac{b}{4}=\frac{c}{5}\Leftrightarrow\frac{a}{8}=\frac{b}{12};\frac{b}{12}=\frac{c}{15}\Rightarrow\frac{a}{8}=\frac{b}{12}=\frac{c}{15}\)

\(\frac{a}{8}=\frac{b}{12}=\frac{c}{15};\frac{c}{6}=\frac{d}{7}\Leftrightarrow\frac{a}{16}=\frac{b}{24}=\frac{c}{30};\frac{c}{30}=\frac{d}{35}\Rightarrow\frac{a}{16}=\frac{b}{24}=\frac{c}{30}=\frac{d}{35}\)

Áp dụng tính chất của dãy tỉ số "=" nhau , ta có:

\(\frac{a}{16}=\frac{b}{24}=\frac{c}{30}=\frac{d}{35}=\frac{a+b+c+d}{16+24+30+35}=\frac{210}{105}=2\)

\(\Rightarrow\left[\begin{matrix}a=16.2=32\\b=24.2=48\\c=30.2=60\\d=35.2=70\end{matrix}\right.\)

Đáp án D

a) \(27^{64}:81^{20}=3^{192}:3^{80}=3^{112}\)

b) \(\left(\dfrac{1}{8}\right)^{20}:\left(\dfrac{1}{16}\right)^9=\left(\dfrac{1}{2}\right)^{60}:\left(\dfrac{1}{2}\right)^{36}=\left(\dfrac{1}{2}\right)^{24}\)

c) \(\dfrac{1}{3}:\dfrac{1}{5}-\dfrac{1}{6}=\dfrac{5}{3}-\dfrac{1}{6}=\dfrac{10}{6}-\dfrac{1}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)

A=7*(1/3*13+1/13*23+1/23*33+1/33*43+1/43*53+1/53*63)

A=7/10(1/3-1/13+1/13-1/23+1/23-1/33+1/33-1/43+1/43-1/53+1/53-1/63)

A=7/10*(1/3-1/63)

A=7/10*20/63

A=2/9