TÌM X BIẾT :3X+3X+2=270 ?
3x+1+3x+2-2x3x=270 tìm x
3x+1 + 3x+2 - 2 x 3x = 270
3x ( 3 + 32 - 2) = 270
3x . 10 = 270
3x = 270 : 10
3x = 27
3x = 33
x = 3
\(3^{x+1}+3^{x+2}-2.3^x=270\)
\(\Leftrightarrow3.3^x+3^2.3^x-2.3^x=270\)
\(\Leftrightarrow\left(3+3^2-2\right).3^x=270\)
\(\Leftrightarrow10.3^x=270\)
\(\Leftrightarrow3^x=27\)
\(\Leftrightarrow3^x=3^3\)
\(\Leftrightarrow x=3\)
Tìm x biết
a) 2x - 24.27.32 = 0.
b) b) 3x + 3x+2 = 270.
c) 6 ⁝ x+1
a.\(2^x-2^4.2^7.32=0\)
\(2^x-2^{16}=0\)
\(=>x=16\)
b.\(3^x+3^{x+2}=270\)
\(3^x+3^x.3^2=270\)
\(3^x.10=270\)
\(3^x=27\)
\(=>x=3\)
tìm x
x2-3x-270=0
x2-3x-270=0
<=> x^2 - 18x + 15x - 270 = 0
<=> x(x - 18) + 15(x - 18) = 0
<=> (x + 15)(x - 18) = 0
<=> x = - 15 hoặc x = 18
vậy_
kết bạn nhé ^^
\(x^2 -3x-270=0\)
\(\Leftrightarrow\)\(( x^2 -18x) + ( 15x-270)=0\)
\(\Leftrightarrow\)\(x. (x-18)+15. (x-18)=0\)
\(\Leftrightarrow\)\((x-18)(x+15)=0\)
\(\Rightarrow\)\(x =18\) hoặc \(x=-15\)
x2 -3x-270=0
<=> x2 - 18x + 15x - 270 = 0
<=> x(x - 18) + 15(x - 18) = 0
<=> (x + 15)(x - 18) = 0
<=> x = - 15 hoặc x = 18
Vậy......................................
Tìm x
3x + 3x + 2 = 270
\(\Leftrightarrow3^x=27\)
hay x=3
\(\Leftrightarrow3^x+3^x.3^2=270\Leftrightarrow3^x.10=270\\\Leftrightarrow3^x=3^3\Leftrightarrow x=3\)
Tìm số tự nhiên x biết :
a ) 1245 - 3x = 735
b ) 14x - 8x + 34 = 94
c ) 3x+2 + 3x = 270
các bạn giúp mình với
a) 1245 - 3x = 735
3x = 1245 - 735
3x = 510
x = 510 : 3
x = 170
b,14x - 8x + 34 = 94
14x - 8x =94-34
14x - 8x =60
x(14-8) = 60
x.6 =60
x =60 :6
x =10
Bài này giải ra như thế này !
a ) 1245 -3x = 735
=> 3x = 1245 - 735 = 510
=> x = 510 : 3 = 170
b ) 14x - 8 x + 34 = 94
=> 6x = 94 -34 = 60
=> x = 60 : 6 = 10
3x+4+3x+2=270
\(3^{x+4}+3^{x+2}=270\)
\(\Leftrightarrow3^x\cdot90=270\)
hay x=1
\(3^{x+2}.3^2+3^{x+2}=270\)
\(3^{x+2}\left(3^2+1\right)=270\)
\(3^{x+2}.10=270\)
\(3^{x+2}=27\)
⇒x+2=3
⇒x=1
Tìm x ϵ N biết :
a) 280 – ( x – 140 ) : 35 = 270 ;
b)( 190 – 2x ) : 35 – 32 = 16;
c) 720 : [ 41 – ( 2x – 5 ) ] = 23 .5
d) ( x : 23 + 45 ) . 37 – 22 = 24 . 105 ;
e) ( 3x – 4 ) . ( x – 1 ) 3 = 0 ;
f) 22x-1 : 4 = 83
g) x17 = x ;
h) ( x – 5 ) 4 = ( x – 5 ) 6 ;
i) ( x + 2 ) 5 = 210 ;
k ) 1 + 2 + 3 + … + x = 78
l) ( 3 .x – 24) . 73 = 2 .74 ;
n) 5x : 52 = 125 ;
m) ( x + 1) 2 = ( x + 1) 0 ;
o) ( 2 + x ) + ( 4 + x ) + ( 6 + x ) + ……+ ( 52 + x ) = 780 ;
p) 70⋮ x , 80 ⋮ x và x > 8
q) x ⋮ 12 , x ⋮ 25 , x ⋮ 30 và 0 < x < 500
Tìm x; biết: 3x + 3x+1 + 3x+2 + 3x+3 = 1080
đặt 3x ra ngoài bạn nhé bàn phím mik hỏng rồi ;-;
$\Rightarrow 3^x(1+3+3^2+3^3)=1080$
$\Rightarrow 3^x.40=1080$
$\Rightarrow 3^x=27=3^3$
$\Rightarrow x=3$
\(3^x+3^{x+1}+3^{x+2}+3^{x+3}=1080\)
\(\Rightarrow3^x+3^x.3^1+3^x.3^2+3^x.3^3=1080\)
\(3^x.\left(1+3+9+27\right)=1080\)
\(3^x.40=1080\)
\(3^x=27\)
\(3^x=3^3\)
Vậy: x = 3
Tìm x biết a) 3x^2+x)4-3x)=12 b)3x^2-2x-1=0
b: \(3x^2-2x-1=0\)
=>\(3x^2-3x+x-1=0\)
=>\(\left(x-1\right)\left(3x+1\right)=0\)
=>\(\left[{}\begin{matrix}x-1=0\\3x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)
a: Bạn ghi lại đề đi bạn
Thu gọn biểu thức
9x(x+5)-(3x+2)(3x-2)
tìm x biết:
(3x-2)2=49x2
Thu gọn biểu thức:
\(9x\left(x+5\right)-\left(3x+2\right)\left(3x-2\right)\)
\(=9x^2+45x-\left(9x^2-4\right)\)
\(=45x+4\)
Tìm x. biết:
\(\left(3x-2\right)^2=49x^2\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-2=7x\\3x-2=-7x\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{5}\end{matrix}\right.\)
Vậy \(x\in\left\{-\dfrac{1}{2};\dfrac{1}{5}\right\}\)
a: Ta có: \(9x\cdot\left(x+5\right)-\left(3x+2\right)\left(3x-2\right)\)
\(=9x^2+45x-9x^2+4\)
=45x+4
b: Ta có: \(\left(3x-2\right)^2=49x^2\)
\(\Leftrightarrow\left(3x-2-7x\right)\left(3x-2+7x\right)=0\)
\(\Leftrightarrow\left(4x+2\right)\left(10x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{5}\end{matrix}\right.\)